std :: string sprintf [英] std::string sprintf

问题描述

嘿

Iam偶尔会使用像

char buffer [1024];

sprinf（buffer，" Hello test％d％） s"，someint，somestring）;


是否有任何_convenient_和buffer overflow安全等效于

使用std :: string？

谢谢

Hey
Iam occaisonally using something like
char buffer[1024];
sprinf(buffer,"Hello test %d %s",someint,somestring);

Is there any _convenient_ and buffer overflow secure equivalent for that
using std::string?
Thanks

推荐答案

" Frank Neuhaus" < FN ****** @ uni-koblenz.de>在留言中写道

news：di ********** @ cache.uni-koblenz.de ...

"Frank Neuhaus" <fn******@uni-koblenz.de> wrote in message
news:di**********@cache.uni-koblenz.de...

嘿
Iam occaisonally使用类似
char buffer [1024];
sprinf（缓冲区，Hello test％d％s，someint，somestring）;

是否有_convenient_和buffer溢出安全相当于
使用std :: string？

Hey
Iam occaisonally using something like
char buffer[1024];
sprinf(buffer,"Hello test %d %s",someint,somestring);

Is there any _convenient_ and buffer overflow secure equivalent for that
using std::string?

查找''std :: ostringstream''


-Mike

Look up ''std::ostringstream''

-Mike

Frank Neuhaus写道：

Frank Neuhaus wrote:

嘿


嘿你自己

Iam偶尔使用像
char buffer [1024];
sprinf（缓冲区，Hello test％d％s，someint，somestring）;
使用std :: string是否有_convenient_和buffer overflow安全等效？

Hey
Hey yourself
Iam occaisonally using something like
char buffer[1024];
sprinf(buffer,"Hello test %d %s",someint,somestring);

Is there any _convenient_ and buffer overflow secure equivalent for that
using std::string?

有一个snprintf，IIRC ...


一般来说，我所知道的唯一合理的方式是


std :: ostringstream os;
os<< 你好测试 << someint<< ''''<< somestring;

std :: string buffer（os.str（））;


//这里''缓冲''有字符串


V

There is a snprintf, IIRC...

Generally speaking, the only reasonable way I know is

std::ostringstream os;
os << "Hello test " << someint << '' '' << somestring;
std::string buffer(os.str());

// here ''buffer'' has the string

V

Frank Neuhaus写道：

Frank Neuhaus wrote:

Iam偶尔使用像
char buffer [1024]这样的东西;
sprinf（缓冲区，Hello test％d％s，someint，somestring）;

是否有任何_convenient_和buffer overflow安全等效于
使用std： ：string？

Iam occaisonally using something like
char buffer[1024];
sprinf(buffer,"Hello test %d %s",someint,somestring);

Is there any _convenient_ and buffer overflow secure equivalent for that
using std::string?

Boost.Format通过重载operator％来实现printf样式的格式化。它虽然
对我来说仍然感觉不是很好。你做什么，基本上，

是创建一个格式化程序对象，它有一个内部流缓冲区，保存格式化序列的
。然后你可以获取它的字符串值并将它分配给std :: string。


示例：


std :: string s;

s = str（格式（"％d％d"）％11％22）;


参见 http://www.boost.org/libs/format/index.html 更多例子。


-

Matthias Kaeppler |电话：[phone]

Gerhart-Hauptmann-Str。 16a |手机：[phone]

D-67663凯撒斯劳滕|电子邮件：有限状态点组织的matthias

Boost.Format has printf-style formatting by overloading operator%. It
still doesn''t feel very printf-ish to me though. What you do, basically,
is create a formatter object which has an internal stream buffer holding
the formatted sequence. You can then take its string value and assign it
to a std::string.

Example:

std::string s;
s = str( format(" %d %d ") % 11 % 22 );

See http://www.boost.org/libs/format/index.html for more examples.

--
Matthias Kaeppler | Tel: [phone]
Gerhart-Hauptmann-Str. 16a | Mob: [phone]
D-67663 Kaiserslautern | E-Mail: matthias at finitestate dot org

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