指针指向的内容?? [英] contents of what a pointer points to??
问题描述
在K& RI中发现了这个：
静态字符allocbuf [ALLOCSIZE];
静态字符* allocp = allocbuf;
但是* allocp还没有设置为指向任何东西，所以怎么可能
使未知地址的内容成为allocbuf？
JS
In K&R I have found this:
static char allocbuf[ALLOCSIZE];
static char *allocp = allocbuf;
But *allocp has not been set to point at anything yet so how is it possible
to make the contents of an unknown address be "allocbuf"??
JS
推荐答案
JS写道：
在K& RI中发现了这个：
静态字符allocbuf [ALLOCSIZE];
静态字符* allocp = allocbuf;
但是* allocp还没有设置为指向任何东西，那么它是怎么回事可能
使未知地址的内容为allocbuf??
In K&R I have found this:
static char allocbuf[ALLOCSIZE];
static char *allocp = allocbuf;
But *allocp has not been set to point at anything yet so how is it possible
to make the contents of an unknown address be "allocbuf"??
它已被设置为指向某个东西，allocbuf []这是一块
内存。所以allocp指向allocbuf的第一个元素。
It has been set to point to something, allocbuf[] which is a block of
memory. So allocp points to the first element of allocbuf.
> static char * allocp = allocbuf;
^^^^^^^^^
如果你看起来更小心，你会看到allocp已被设置为
数组allocbuf的开头。 allocbuf基本上是指向数组的
内存位置的指针。
-
bjrnove
>
> static char *allocp = allocbuf;
^^^^^^^^^
If you look more careful you''ll see that allocp has been set to the
start of the array allocbuf. allocbuf is basicly a pointer to the
memorylocation for the array.
--
bjrnove
" Mark Odell" < OD ******* @ hotmail.com> skrev i en meddelelse
news：39 ************* @ individual.net ...
"Mark Odell" <od*******@hotmail.com> skrev i en meddelelse
news:39*************@individual.net...
JS写道：
在K& RI中发现了这个：
静态字符allocbuf [ALLOCSIZE];
静态字符* allocp = allocbuf;
但* allocp有还没有设置为指向任何东西，那么如何使
可以使未知地址的内容成为allocbuf??
In K&R I have found this:
static char allocbuf[ALLOCSIZE];
static char *allocp = allocbuf;
But *allocp has not been set to point at anything yet so how is it possible to make the contents of an unknown address be "allocbuf"??
它已被设置为点某事，allocbuf []这是一块内存。所以allocp指向allocbuf的第一个元素。
It has been set to point to something, allocbuf[] which is a block of
memory. So allocp points to the first element of allocbuf.
但是不应该写成：
1）static char * allocp; //声明* allocp是指向char的指针。
2）allocp =& allocbuf [0]; //使allocp指向
allocbuf中的第一个地址。
3）allocp = allocbuf; //与2相同只是一个简短的手。
然后我可以写：
* allocp = allocbuf;
这意味着allocp指向的地址的内容是
allocbuf的第一个元素。
JS
But should that not be written as:
1) static char *allocp; // declares that *allocp is a pointer to a char.
2) allocp = &allocbuf[0]; // makes allocp point to the first address in
allocbuf.
3) allocp = allocbuf; // the same as 2) just a short hand.
Then I can write:
*allocp = allocbuf;
which means that the contents of the address that allocp is pointing at is
the first element of allocbuf.
JS
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