函数根据给定的概率生成1或0 [英] function to generate 1 or 0 according to a given probability

问题描述

大家好，


我试图创建一个生成1或0的函数，其中生成1的

概率等于X（传递给

函数作为参数）。


任何想法？

感谢期待，

Mayank

解决方案

Mayank Kaushik写道：

大家好，我试图创建一个生成1或0的函数，生成1的概率等于X（传递给
函数为一个参数）。

任何想法？
感谢期待，

/ * BEGIN new.c * /


#include< stdio.h>

#include< stdlib.h>


int X_prob（double x ）;


int main（无效）

{

无符号数;


printf（" \ n0.95"）;

for（count = 0; c ount！= 70; ++ count）{

printf（"％d"，X_prob（0.95））;

}

printf （\ n\\\
0.50"）;

for（count = 0;伯爵！= 70; ++ count）{

printf（"％d"，X_prob（0.5））;

}

printf（" \ n\\\
0.05"）;

for（count = 0; count！= 70; ++ count）{

printf（"％d"， X_prob（0.05））;

}

putchar（''\ n''）;

返回0;

}


int X_prob（双x）

{

返回RAND_MAX * x> = rand（）;

}


/ * END new.c * /

-

pete

" Mayank Kaushik" < PR *************** @ yahoo.com>写在

新闻：11 ********************* @ f14g2000cwb.googlegro ups.com：

我试图创建一个生成1或0的函数，生成1的概率等于X（作为参数传递给
函数）。 / blockquote>


假设rand生成均匀分布的值，这是微不足道的。我怀疑这个问题在clc中可能是偏离主题的：comp.programming

可能是一个更好的地方可以提出这个问题。


#include< stdio.h>

#include< stdlib.h>

#include< time.h>


int成功（双概率）{

返回概率> =（（双）rand（））/ RAND_MAX;

}


int main（void）{

int i;

srand（time（NULL））;


for（i = 0; i< 10; ++ i）{

printf（"％s \ n"，success（0.38）？" success""失败）;

}


返回0;

}


思南

-

A. Sinan Unur< 1u ** @ llenroc.ude.invalid>

（反转每个组件并删除.invalid对于电子邮件地址）

A. Sinan Unur写道：

" Mayank Kaushik" < PR *************** @ yahoo.com>在
新闻中写道：11 ********************* @ f14g2000cwb.googlegro ups.com：

我试图创建一个生成1或0的函数，生成1的概率等于X（作为参数传递给
函数）。

假设rand生成均匀分布的值，这是微不足道的。我怀疑这个问题在clc中可能是偏离主题的：comp.programming
可能是提出这个问题的更好的地方。

#include< stdio.h>
#include< stdlib.h>
#include< time.h>

int success（double prob）{
return prob> =（（ double）rand（））/ RAND_MAX;
}

如果prob == 0.0并且对rand（）的调用返回0怎么办？

hi everyone,

im trying to create a function that generates a 1 or a 0, with the
probability of a 1 being generated equal to X (which is passed to the
function as a parameter).

any ideas?
thanks in anticipation,
Mayank

解决方案

Mayank Kaushik wrote:

hi everyone,

im trying to create a function that generates a 1 or a 0, with the
probability of a 1 being generated equal to X (which is passed to the
function as a parameter).

any ideas?
thanks in anticipation,

/* BEGIN new.c */

#include <stdio.h>
#include <stdlib.h>

int X_prob(double x);

int main(void)
{
unsigned count;

printf("\n0.95 ");
for (count = 0; count != 70; ++count) {
printf("%d", X_prob(0.95));
}
printf("\n\n0.50 ");
for (count = 0; count != 70; ++count) {
printf("%d", X_prob(0.5));
}
printf("\n\n0.05 ");
for (count = 0; count != 70; ++count) {
printf("%d", X_prob(0.05));
}
putchar(''\n'');
return 0;
}

int X_prob(double x)
{
return RAND_MAX * x >= rand();
}

/* END new.c */
--
pete

"Mayank Kaushik" <pr***************@yahoo.com> wrote in
news:11*********************@f14g2000cwb.googlegro ups.com:

im trying to create a function that generates a 1 or a 0, with the
probability of a 1 being generated equal to X (which is passed to the
function as a parameter).

Assuming rand generates uniformly distributed values, this is trivial. I
suspect that the question might be off-topic in clc: comp.programming
might be a better place to ask this question.

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int success(double prob) {
return prob >= ((double) rand())/RAND_MAX;
}

int main(void) {
int i;
srand(time(NULL));

for(i = 0; i < 10; ++i) {
printf("%s\n", success(0.38) ? "success" : "failure");
}

return 0;
}

Sinan
--
A. Sinan Unur <1u**@llenroc.ude.invalid>
(reverse each component and remove .invalid for email address)

A. Sinan Unur wrote:

"Mayank Kaushik" <pr***************@yahoo.com> wrote in
news:11*********************@f14g2000cwb.googlegro ups.com:

im trying to create a function that generates a 1 or a 0, with the
probability of a 1 being generated equal to X (which is passed to the
function as a parameter).

Assuming rand generates uniformly distributed values, this is trivial. I
suspect that the question might be off-topic in clc: comp.programming
might be a better place to ask this question.

#include <stdio.h>
#include <stdlib.h>
#include <time.h>

int success(double prob) {
return prob >= ((double) rand())/RAND_MAX;
}

What if prob == 0.0 and the call to rand() returns 0?

这篇关于函数根据给定的概率生成1或0的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！