使用g ++编译问题 [英] Compiling problems with g++
问题描述
大家好。我正在尝试编译别人的代码而且我使用
g ++ 3.3编译器来解决编译问题。基本上，在编译下面的代码时，我得到了这个错误信息：
parsefcns.cc：在函数`void get_token（std :: ifstream *， char **）''：
parsefcns.cc:57：错误：无法转换`std :: basic_string< char，
std :: char_traits< char>，std ::分配器<炭> >''到'char *''在
分配
make：*** [parsefcns.o]错误1
我不知道C ++，我想知道是否有一个善良的人愿意帮助我解决这个问题。
提前谢谢。
Arturo
............................... ............
#include< fstream>
#include< sstream>
#include < cctype>
#include< cstring>
#include< iostream>
using namespace std;
使用std :: ifstream;
使用std :: ostringstream;
void get_token（std :: ifstream * f_stream，char * * ch_ptr）
{
char ch;
std :: ostringstream buffer;
while （（f_stream-> get（ch））&&
（！isspace（ch））&&
（！f_stream-> eof（ ）））
{
buffer<< ch;
}
buffer<< ''\''';
（* ch_ptr）= buffer.str（）; //这是给出汇编的行
问题
//返回ch;
f_stream-> seekg（-1，std :: ios :: cur）;
}
.............等。
Hello everyone. I am trying to compile someone else code and I am
stuck with compilation problems using
the g++ 3.3 compiler. Basically, when compiling the following code, I
get this error message:
parsefcns.cc: In function `void get_token(std::ifstream*, char**)'':
parsefcns.cc:57: error: cannot convert `std::basic_string<char,
std::char_traits<char>, std::allocator<char> >'' to `char*'' in
assignment
make: *** [parsefcns.o] Error 1
I don''t know C++ and I was wondering if there was a kind soul willing
to help me in solving this problem.
Thanks in advance.
Arturo
...........................................
#include <fstream>
#include <sstream>
#include <cctype>
#include <cstring>
#include <iostream>
using namespace std;
using std::ifstream;
using std::ostringstream;
void get_token(std::ifstream *f_stream, char **ch_ptr)
{
char ch;
std::ostringstream buffer;
while( (f_stream->get(ch)) &&
(!isspace(ch)) &&
(!f_stream->eof()) )
{
buffer << ch;
}
buffer << ''\0'';
(*ch_ptr) = buffer.str(); // This is the line giving compilation
problems
// return ch;
f_stream->seekg(-1, std::ios::cur);
}
.............etc.
推荐答案
" Arturo DiDonna" < AR ************ @ yahoo.it>在消息中写道
新闻：ba ************************** @ posting.google.c om ...
"Arturo DiDonna" <ar************@yahoo.it> wrote in message
news:ba**************************@posting.google.c om...
大家好。我正在尝试编译别人的代码，并且我使用g ++ 3.3编译器来解决编译问题。基本上，在编译以下代码时，我收到此错误消息：
parsefcns.cc：在函数`void get_token（std :: ifstream *，char **）''：
parsefcns.cc：57：错误：无法转换`std :: basic_string< char，
std :: char_traits< char> ;,std :: allocator< char> >''到'char *''在
作业中
make：*** [parsefcns.o]错误1
我不知道C ++而我是想知道是否有一个善良的灵魂愿意帮助我解决这个问题。
提前致谢。
Arturo
......... .................................
#include< fstream>
#include< ; sstream>
#include< cctype>
#include< cstring>
#include< iostream>
使用命名空间std;
这个指令..
使用std :: ifstream;
使用std :: ostringstream;
...不需要这两个声明。
void get_token（std :: ifstream * f_stream，char ** ch_ptr）
const char ** ch_ptr
{
char ch;
std :: ostringstream buffer;
while（（ f_stream-> get（ch））&&
（！isspace（ch））&&
（！f_stream-> eof（）））
{
buffer<< ch;
}
缓冲区<< ''\''';
（* ch_ptr）= buffer.str（）; //这是给出编译的行
问题
* ch_ptr = buffer.str（）。c_str（）;
//返回ch ;
f_stream-> seekg（-1，std :: ios :: cur）;
这里更好地检查成功/失败。
}
............等。
Hello everyone. I am trying to compile someone else code and I am
stuck with compilation problems using
the g++ 3.3 compiler. Basically, when compiling the following code, I
get this error message:
parsefcns.cc: In function `void get_token(std::ifstream*, char**)'':
parsefcns.cc:57: error: cannot convert `std::basic_string<char,
std::char_traits<char>, std::allocator<char> >'' to `char*'' in
assignment
make: *** [parsefcns.o] Error 1
I don''t know C++ and I was wondering if there was a kind soul willing
to help me in solving this problem.
Thanks in advance.
Arturo
..........................................
#include <fstream>
#include <sstream>
#include <cctype>
#include <cstring>
#include <iostream>
using namespace std;
This directive..
using std::ifstream;
using std::ostringstream;
... obviates the need for these two declarations.
void get_token(std::ifstream *f_stream, char **ch_ptr)
const char **ch_ptr
{
char ch;
std::ostringstream buffer;
while( (f_stream->get(ch)) &&
(!isspace(ch)) &&
(!f_stream->eof()) )
{
buffer << ch;
}
buffer << ''\0'';
(*ch_ptr) = buffer.str(); // This is the line giving compilation
problems
*ch_ptr = buffer.str().c_str();
// return ch;
f_stream->seekg(-1, std::ios::cur);
Better check for success/failure here.
}
............etc.
-Mike
-Mike
Arturo DiDonna写道：
Arturo DiDonna wrote:
...
void get_token（std :: ifstream * f_stream，char ** ch_ptr）
{
char ch;
std :: ostringstream buffer;
while（ （f_stream-> get（ch））&&
（！isspace（ch））&&
（！f_stream-> eof（）））
{
buffer<< ch;
}
缓冲区<< ''\''';
（* ch_ptr）= buffer.str（）; //这是给出编译的行
问题
...
void get_token(std::ifstream *f_stream, char **ch_ptr)
{
char ch;
std::ostringstream buffer;
while( (f_stream->get(ch)) &&
(!isspace(ch)) &&
(!f_stream->eof()) )
{
buffer << ch;
}
buffer << ''\0'';
(*ch_ptr) = buffer.str(); // This is the line giving compilation
problems
''std :: ostringstream :: str（）''的返回类型是''std： ：string''，你是
试图将这个值赋给'char *''类型的对象。显然，
这是一个错误。
无论如何，这不行。看来你正试图将一个
指针返回给一个在函数退出时将被销毁的对象。什么
你想要实现吗？
-
祝你好运，
Andrey Tarasevich
Return type of ''std::ostringstream::str()'' is ''std::string'' and you are
trying to assign this value to an object of type ''char*''. Obviously,
this is an error.
Anyway, this can''t work. It appears that you are trying to return a
pointer to an object that will be destroyed when function exits. What
are you trying to implement?
--
Best regards,
Andrey Tarasevich
" Arturo DiDonna" < AR ************ @ yahoo.it>在消息中写道
新闻：ba ************************** @ posting.google.c om ...
"Arturo DiDonna" <ar************@yahoo.it> wrote in message
news:ba**************************@posting.google.c om...
大家好。我正在尝试编译别人的代码，并且我使用g ++ 3.3编译器来解决编译问题。基本上，在编译以下代码时，我收到此错误消息：
parsefcns.cc：在函数`void get_token（std :: ifstream *，char **）''：
parsefcns.cc：57：错误：无法转换`std :: basic_string< char，
std :: char_traits< char> ;,std :: allocator< char> >''到'char *''在
作业中
make：*** [parsefcns.o]错误1
我不知道C ++而我是想知道是否有一个善良的灵魂愿意帮助我解决这个问题。
提前致谢。
Arturo
......... .................................
#include< fstream>
#include< ; sstream>
#include< cctype>
#include< cstring>
#include< iostream>
使用命名空间std;
使用std :: ifstream;
使用std :: ostringstream;
void get_token（std :: ifstream * f_stream，char ** ch_ptr）
{
char ch;
std :: ostringstream buffer;
while（（f_stream-> get（ch））&&
（！isspace（ch））&&& br />（！f_stream-> eof（）））
{
缓冲区<< ch;
}
缓冲区<< ''\''';
（* ch_ptr）= buffer.str（）; //这是给编译
问题的一行
//返回ch;
f_stream-> seekg（-1，std :: ios :: cur）;
}
............等。
Hello everyone. I am trying to compile someone else code and I am
stuck with compilation problems using
the g++ 3.3 compiler. Basically, when compiling the following code, I
get this error message:
parsefcns.cc: In function `void get_token(std::ifstream*, char**)'':
parsefcns.cc:57: error: cannot convert `std::basic_string<char,
std::char_traits<char>, std::allocator<char> >'' to `char*'' in
assignment
make: *** [parsefcns.o] Error 1
I don''t know C++ and I was wondering if there was a kind soul willing
to help me in solving this problem.
Thanks in advance.
Arturo
..........................................
#include <fstream>
#include <sstream>
#include <cctype>
#include <cstring>
#include <iostream>
using namespace std;
using std::ifstream;
using std::ostringstream;
void get_token(std::ifstream *f_stream, char **ch_ptr)
{
char ch;
std::ostringstream buffer;
while( (f_stream->get(ch)) &&
(!isspace(ch)) &&
(!f_stream->eof()) )
{
buffer << ch;
}
buffer << ''\0'';
(*ch_ptr) = buffer.str(); // This is the line giving compilation
problems
// return ch;
f_stream->seekg(-1, std::ios::cur);
}
............etc.
如何在不了解C ++的情况下管理所有这些代码？
无论如何代码是错误的，但是修复是什么并不清楚，因为你不知道C ++ b你也不知道C ++。猜测我会说代码是
意味着使用ostrstream而不是ostringstream，并且< strstream>不是< sstream>，
至少会让它编译成我认为。
john
How did you manage all this code without knowing C++?
Anyway the code is wrong but what the fix is isn''t clear, and since you
don''t know C++ you can help either. At a guess I would say that the code is
meant to use ostrstream not ostringstream, and <strstream> not <sstream>,
that would make it compile at least I think.
john
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