字符串错误 [英] String Error
问题描述
我正在使用我的sql语句分配一个字符串变量，从数据库中填充的listview中获取项目
。
我收到错误说那&未定义类型''字符串''
和Systems.Windows.Forms.ListViewItems。
我使用索引0因为值I想要在第一栏
（这是数据库中的客户ID）
将mySqlString作为字符串调暗
''定义从数据库中删除的sqlString
mySqlString =" DELETE from Customers WHERE Cust_ID =''" &
ListView.SelectedItems（0）& "''"
-Ivan
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您正在尝试获取所选项目并将其视为字符串。
" SelectedItems（0）"有一个.value属性或类似的东西暴露
所选项目的文本？
基本上，你正在处理类似值的类型。 />
" Ivan Weiss" < 4 ***** @ optonline.net>在消息中写道
news：OV ************** @ tk2msftngp13.phx.gbl ...我正在分配一个字符串变量与我的sql语句从数据库填充的列表视图中获取项目
我收到一个错误说&没有为类型''String''和Systems.Windows.Forms.ListViewItems定义。
我使用的索引为0，因为我想要的值在第一列
（它是来自数据库的客户ID）
将mySqlString作为字符串调整
''定义从数据库中删除的sqlString
mySqlString =" DELETE from客户WHERE Cust_ID =''" &
ListView.SelectedItems（0）&通过开发人员索引 http://www.developersdex.com ***
不要只是参加USENET ......获得奖励！
Ivan The Terrible？
您需要ListViewItem.Text属性来获取项目文本。
问候 - OHM
Ivan Weiss写道：我正在用我的sql语句分配一个字符串变量来获取
从数据库填充的列表视图中的项目。
我收到错误说&没有为类型''String''和Systems.Windows.Forms.ListViewItems定义。
我使用的索引为0因为我想要的值是在第一个
列（它是来自数据库的客户ID）
将mySqlString作为字符串调整
''定义从数据库中删除的sqlString
mySqlString =" DELETE from客户WHERE Cust_ID =''" &
ListView.SelectedItems（0）&通过开发人员索引 http://www.developersdex.com ***
不要只是参加USENET ......获得奖励！
我觉得伊万很可怕，因为我在寻找这个应用程序时发现了所有的错误
但他们正慢慢得到解决。
我把它改成了listview.text并且摆脱了错误。但是，
如何知道从哪个列中获取文本？我只需要确认
我的id =我的列表视图第一列中的值。
感谢您的帮助，真的很感激！
-Ivan
***通过Developersdex发送 http://www.developersdex.com ***
不要只是参加USENET ......获得奖励！
I am assigning a string variable with my sql statement getting the item
from a listview filled from a database.
I am getting an error saying that & is not defined for types ''String''
and Systems.Windows.Forms.ListViewItems.
I am using an index of 0 because the value I want is in the first column
(it is the customer ID from the database)
Dim mySqlString As String
''Define sqlString that deletes from database
mySqlString = "DELETE from Customers WHERE Cust_ID = ''" &
ListView.SelectedItems(0) & "''"
-Ivan
*** Sent via Developersdex http://www.developersdex.com ***
Don''t just participate in USENET...get rewarded for it!
You are trying to take the selected item and treat it as a string. Does
"SelectedItems(0)" have a .value property or something similar that exposes
the text of the selected item?
Essentially, you are treating a type like a value.
"Ivan Weiss" <iv*****@optonline.net> wrote in message
news:OV**************@tk2msftngp13.phx.gbl...I am assigning a string variable with my sql statement getting the item
from a listview filled from a database.
I am getting an error saying that & is not defined for types ''String''
and Systems.Windows.Forms.ListViewItems.
I am using an index of 0 because the value I want is in the first column
(it is the customer ID from the database)
Dim mySqlString As String
''Define sqlString that deletes from database
mySqlString = "DELETE from Customers WHERE Cust_ID = ''" &
ListView.SelectedItems(0) & "''"
-Ivan
*** Sent via Developersdex http://www.developersdex.com ***
Don''t just participate in USENET...get rewarded for it!
Ivan The Terrible ?
You need to you the ''ListViewItem.Text'' property to get the items text.
Regards - OHM
Ivan Weiss wrote:I am assigning a string variable with my sql statement getting the
item from a listview filled from a database.
I am getting an error saying that & is not defined for types ''String''
and Systems.Windows.Forms.ListViewItems.
I am using an index of 0 because the value I want is in the first
column (it is the customer ID from the database)
Dim mySqlString As String
''Define sqlString that deletes from database
mySqlString = "DELETE from Customers WHERE Cust_ID = ''" &
ListView.SelectedItems(0) & "''"
-Ivan
*** Sent via Developersdex http://www.developersdex.com ***
Don''t just participate in USENET...get rewarded for it!
I feel like Ivan the terrible with all of the errors I have been finding
throughout writing this app but they are slowly getting resolved.
I changed it to listview.text and that got rid of the error. However,
how does it know what column to grab text from? I only need to confirm
my id = the value in the first column of my listview.
Thank for your help, it is truly appreciated!
-Ivan
*** Sent via Developersdex http://www.developersdex.com ***
Don''t just participate in USENET...get rewarded for it!
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