链表问题 [英] linked list problem
问题描述
自从我用C语言编程以来已经有一段时间了，我很困惑为什么我会得到以下错误信息（为什么他们都不是'指针）结构
chromT {}"？：
" genet.c"，第192行：警告：作业类型不匹配：
指向struct的结果{double score，enum {worst（2），mid（1），best（0）}
cat，array [10]指向struct geneT {..}的指针基因，结构指针
chromT {..} next}" ="指向struct chromT的指针{}
我的代码如下（I已经注意到了问题的界限）：
//数据结构
typedef struct {
双得分;
categ cat;
struct geneT *基因[GENES_PER_CHROM];
struct chromT * next;
} chromT;
typedef struct {
double x [PTS_PER_FEAT];
double id; //跟踪每个功能。
} geneT;
// F. UNCTION PROTOTYPES
static void * LLGo（chromT * start，int n）;
/ * LLGo
*
*此函数返回第n个的地址。元素
*在链表中。
* /
static void * LLGo（chromT * start，int n）{
int i = 0;
chromT * cursor = start;
while（（cursor-> next！= NULL）&& ;（i< n））{
cursor = cursor-> next; //这就是问题的界限
i ++;
}
if（i< n）{
返回NULL;
}
else {
返回光标;
}
}
在文章< bo ********** @ news.Stanford.EDU>中，
Darius Fatakia< da ************ @ yahoo.com>写道：自从我用C编程以来已经有一段时间了，我很困惑为什么我得到以下错误信息（为什么他们俩都没有指向struct的指针
chromT {}？：
" genet.c"，第192行：警告：赋值类型不匹配：
指向struct {double score的指针，enum {最差（2），mid（1），最佳（0）}
cat，array [10]指向struct geneT {..}基因，指向struct的指针
chromT {.. } next}" ="指向struct chromT的指针{}
我的代码如下（我已注意到问题所在的行）：
//数据结构
typedef struct {
分类cat;
struct geneT *基因[GENES_PER_CHROM];
struct chromT * next;
} chromT;
typedef struct {
double x [PTS_PER_FEAT];
double id; //跟踪每个功能的东西。
} geneT;
在第一个typedef中：
哟你指的是struct geneT，但是你还没有定义struct geneT。
你引用的是struct chromT，但是你还没有定义一个struct geneT。 struct chromT"。
试试这个：
typedef struct {
double x [PTS_PER_FEAT];
double id; //跟踪每个功能的东西。
} geneT;
typedef struct chromT {//注意：struct chromT
双重分数;
分类猫;
geneT *基因[GENES_PER_CHROM]; //注意：geneT，而不是struct geneT
struct chromT * next;
} chromT;
-
Rouben Rostamian< ro ******* @ umbc.edu>
谢谢!!!
It''s been a while since I programmed in C, and I''m confused as to why I get
the following error message (why aren''t they both "pointer to struct
chromT{}"?:
"genet.c", line 192: warning: assignment type mismatch:
pointer to struct {double score, enum {worst(2), mid(1), best(0)}
cat, array[10] of pointer to struct geneT {..} genes, pointer to struct
chromT {..} next} "=" pointer to struct chromT {}
my code is as follows (I have noted the line with the problem):
// DATA STRUCTURES
typedef struct {
double score;
categ cat;
struct geneT *genes[GENES_PER_CHROM];
struct chromT *next;
} chromT;
typedef struct {
double x[PTS_PER_FEAT];
double id; // something to keep track of each feature.
} geneT;
// FUNCTION PROTOTYPES
static void *LLGo (chromT *start, int n);
/* LLGo
*
* This function returns the address of the "n-th" element
* in the linked list.
*/
static void *LLGo (chromT *start, int n) {
int i = 0;
chromT *cursor = start;
while((cursor->next != NULL) && (i < n)) {
cursor = cursor->next; // THIS IS THE LINE WITH THE PROBLEM
i++;
}
if(i < n) {
return NULL;
}
else {
return cursor;
}
}
In article <bo**********@news.Stanford.EDU>,
Darius Fatakia <da************@yahoo.com> wrote:It''s been a while since I programmed in C, and I''m confused as to why I get
the following error message (why aren''t they both "pointer to struct
chromT{}"?:
"genet.c", line 192: warning: assignment type mismatch:
pointer to struct {double score, enum {worst(2), mid(1), best(0)}
cat, array[10] of pointer to struct geneT {..} genes, pointer to struct
chromT {..} next} "=" pointer to struct chromT {}
my code is as follows (I have noted the line with the problem):
// DATA STRUCTURES
typedef struct {
double score;
categ cat;
struct geneT *genes[GENES_PER_CHROM];
struct chromT *next;
} chromT;
typedef struct {
double x[PTS_PER_FEAT];
double id; // something to keep track of each feature.
} geneT;
In the first typedef:
you refer to "struct geneT", but you haven''t defined a "struct geneT".
you refer to "struct chromT", but you haven''t defined a "struct chromT".
Try this:
typedef struct {
double x[PTS_PER_FEAT];
double id; // something to keep track of each feature.
} geneT;
typedef struct chromT { // note: struct chromT
double score;
categ cat;
geneT *genes[GENES_PER_CHROM]; // note: "geneT", not "struct geneT"
struct chromT *next;
} chromT;
--
Rouben Rostamian <ro*******@umbc.edu>
Thanks!!!
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