更多解决方案 [英] More Solutions
问题描述
我被要求针对以下问题提交至少5个解决方案:
通过替换/添加或删除以下
代码段中的一个字符,让它打印ttttttttttttttttttttt(20次)
#include< stdio.h>
int main()
{
int k,j = 20;
for(k = 0; k< j; k--)
printf( " t);
printf(" \ n");
返回0;
}
>
我想出了3个解决方案,而不是(k = 0; k
2.而不是(k = 0; k
3.而不是for(k = 0; k
有谁可以建议我另外两个解决方案?
I was asked to submit atleast 5 solutions for the following problem:
By Replacing/Adding or deleting only one character from the following
code snippet, make it print tttttttttttttttttttt (20 times)
#include<stdio.h>
int main()
{
int k, j=20;
for(k=0;k<j;k--)
printf("t);
printf("\n");
return 0;
}
I came up with 3 solutions which were
1. instead of for(k=0;k<j;k--) write for(k=0;k<j;j--)
2. instead of for(k=0;k<j;k--) write for(k=0;-k<j;k--)
3.instead of for(k=0;k<j;k--) write for(k=0;k+j;k--)
Can anyone suggest me 2 more solutions?
推荐答案
Romram< sa ** *********@gmail.com>写道:
Romram <sa***********@gmail.com> wrote:
我被要求提交至少5个解决方案以解决以下问题:
通过替换/添加或删除以下
代码段中的一个字符, make it print tttttttttttttttttttt(20次)
#include< stdio.h>
int main()
{
int k,j = 20 ;
for(k = 0; k< j; k--)
printf(" t);
printf(" \ n");
返回0 ;
}
我假设您忘记了第一个printf()中的结束语。请确保您发布的代码实际上是正确的并且编译。
1.而不是for(k = 0; k< j; k--)写入(k = 0; k2.而不是(k = 0; k
3. for(k = 0; k
任何人都可以建议我另外两个解决方案吗?
I was asked to submit atleast 5 solutions for the following problem:
By Replacing/Adding or deleting only one character from the following
code snippet, make it print tttttttttttttttttttt (20 times)
#include<stdio.h>
int main()
{
int k, j=20;
for(k=0;k<j;k--)
printf("t);
printf("\n");
return 0;
}
I assume you forget the closing quote in the first printf(). Please make
sure that the code you post actually is correct and compiles.
1. instead of for(k=0;k<j;k--) write for(k=0;k<j;j--)
2. instead of for(k=0;k<j;k--) write for(k=0;-k<j;k--)
3.instead of for(k=0;k<j;k--) write for(k=0;k+j;k--)
Can anyone suggest me 2 more solutions?
而不是for(k = 0; k
而不是for(k = 0; k
等等。如果这不是正确答案,那么问题
应该更准确。
-
:wq
^ X ^ Cy ^ K ^ X ^ C ^ C ^ C ^ C
instead of for(k=0;k<j;k--) write for(k=0;k<j;j-- )
instead of for(k=0;k<j;k--) write for(k=0;k<j;j-- )
et cetera. If this is not considered a correct answer, the question
should have been more precise.
--
:wq
^X^Cy^K^X^C^C^C^C
任何人都可以建议我另外两个解决方案吗?
Can anyone suggest me 2 more solutions?
而不是(k = 0; k
等等。如果这不是正确的答案,那么问题应该更准确。
-
:wq
^ X ^ Cy ^ K ^ X ^ C ^ C ^ C ^ C
instead of for(k=0;k<j;k--) write for(k=0;k<j;j-- )
instead of for(k=0;k<j;k--) write for(k=0;k<j;j-- )
et cetera. If this is not considered a correct answer, the question
should have been more precise.
--
:wq
^X^Cy^K^X^C^C^C^C
我的意思是5种不同或独特的解决方案。它现在是否清楚问题
?
I meant 5 different or unique solutions. Does it make the question
clear now?
Ico< us **** @ zevv.nl>写道:
Ico <us****@zevv.nl> wrote:
Romram< sa *********** @ gmail.com>写道:
Romram <sa***********@gmail.com> wrote:
我被要求提交至少5个解决方案以解决以下问题:
通过替换/添加或删除以下
代码段中的一个字符, make it print tttttttttttttttttttt(20次)
#include< stdio.h>
int main()
{
int k,j = 20 ;
for(k = 0; k< j; k--)
printf(" t);
printf(" \ n");
返回0 ;
}
I was asked to submit atleast 5 solutions for the following problem:
By Replacing/Adding or deleting only one character from the following
code snippet, make it print tttttttttttttttttttt (20 times)
#include<stdio.h>
int main()
{
int k, j=20;
for(k=0;k<j;k--)
printf("t);
printf("\n");
return 0;
}
我假设您忘记了第一个printf()中的结束语。请确保您发布的代码实际上是正确的并且编译。
I assume you forget the closing quote in the first printf(). Please make
sure that the code you post actually is correct and compiles.
1.而不是for(k = 0; k< j; k--)写入(k = 0; k2.而不是(k = 0; k
3. for(k = 0; k
任何人都可以建议我另外两个解决方案吗?
1. instead of for(k=0;k<j;k--) write for(k=0;k<j;j--)
2. instead of for(k=0;k<j;k--) write for(k=0;-k<j;k--)
3.instead of for(k=0;k<j;k--) write for(k=0;k+j;k--)
Can anyone suggest me 2 more solutions?
而不是for(k = 0; k
instead of for(k=0;k<j;k--) write for(k=0;k<j;j-- )
instead of for(k=0;k<j;k--) write for(k=0;k<j;j-- )
嗯,没有那些是错的,我改变了*和*插入,这是违反规则的
。在我输入之前我应该坐在我的手上。
-
:wq
^ X ^ Cy ^ K ^ X ^ C ^ C ^ C ^ C
Ehm, no those are wrong ofcourse, I changed *and* inserted, which is
against the rules. I should sit on my hands before I type.
--
:wq
^X^Cy^K^X^C^C^C^C
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