JSON中的正则表达式模式？ [英] Regex pattern in JSON?

问题描述

我正在尝试使用单个JSON文件来验证前端（JS）和后端（PHP）中的数据。
我无法弄清楚如何在json字符串中使用我的模式，PHP不会转换它。
这是我想要使用的内容（电子邮件验证）：

I'm trying to have a single JSON file to validate data both in front (JS) and back (PHP). I cannot figure out how to have my pattern in a json string, PHP won't convert it. Here's what I'd like to use (email validation):

'{"name":"email", "pattern":"^[a-z0-9]+(\.[_a-z0-9]+)*@[a-z0-9-]+(\.[a-z0-9-]+)*(\.[a-z]{2,15})$"}'

我想模式中的某些内容不会被视为字符串？实际上，它不会转换为PHP中的对象。我不应该逃避任何事情，但我可能错了......

I suppose there's something in pattern that doesn't get treated as a string? This as it is, won't convert to an object in PHP. I shouldn't have to escape anything but I might be wrong...

谢谢

编辑：试过这在评论中建议：

Tried this as suggested in comments:

json_decode('{"name":"email", "pattern":"^[a-z0-9]+(\\.[_a-z0-9]+)*@[a-z0-9-]+(\\.[a-z0-9-]+)*(\\.[a-z]{2,15})$"}‌​');  ==> NULL

推荐答案

问题是反斜杠 \ 。用两个来表示有一个它会运行良好：

The problem are the backslashes \. Use two to signal that there is one and it will work well:

{"name":"email","pattern":"^[a-z0-9]+(\\.[_a-z0-9]+)*@[a-z0-9-]+(\\.[a-z0-9-]+)*(\\.[a-z]{2,15})$"}

---

以上是有效的JSON但会导致PHP字符串出现问题，因为 \\ 已经被解释为一个 \ 在传递给 json_decode（）之前，我们回到了我们开始的地方。正如 deceze 在评论中指出的那样，这可以通过添加四个反斜杠来解决：

---

The above is valid JSON but will cause trouble as PHP string, because \\ will already be interpreted as one \ before it is passed to json_decode(), and we're back where we started from. As deceze kindly pointed out in the comments, this can be solved by adding four backslashes:

{"name":"email","pattern":"^[a-z0-9]+(\\\\.[_a-z0-9]+)*@[a-z0-9-]+(\\\\.[a-z0-9-]+)*(\\\\.[a-z]{2,15})$"}

或者立即从<$传递内容c $ c> file_get_contents（）（或类似）到 json_decode（）。

Or by immediately passing the contents from file_get_contents() (or similar) to json_decode().

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