指向引用的指针 [英] a pointer to a reference
问题描述
C ++允许引用指针，但是不允许指向
引用，为什么？
C++ allows a reference to a pointer, but doesn''t allow a pointer to a
reference, why?
推荐答案
asdf写道：
asdf wrote:
C ++允许引用指针，但不允许指向
参考，为什么？
C++ allows a reference to a pointer, but doesn''t allow a pointer to a
reference, why?
它的目的是什么？
What would be its purpose?
asdf写道：
asdf wrote:
C ++允许引用指针，但是不允许指向
引用，为什么？
C++ allows a reference to a pointer, but doesn''t allow a pointer to a
reference, why?
你错了：
int main（）
{
int i;
int& ref_i = i; //引用int
int * p =& i; //指向int的指针
int * p_ref =& ref_i; //指向int的引用的指针。
}
p_ref是指向引用的指针。现在引用只是另一个变量的别名
，所以p_ref == p，但这仍然与你的
前提相矛盾。
祝你好运，
Tom
You''re mistaken:
int main()
{
int i;
int& ref_i = i; // reference to an int
int* p = &i; // pointer to an int
int* p_ref = &ref_i; // pointer to a reference to an int.
}
p_ref is a pointer to a reference. Now a reference is simply an alias
for another variable, so p_ref==p, but that still contradicts your
premise.
Best regards,
Tom
Thomas Tutone< Th ******** ***@yahoo.comwrote：
Thomas Tutone <Th***********@yahoo.comwrote:
asdf写道：
asdf wrote:
> C ++允许引用一个指针，但不允许指向
引用，为什么？
>C++ allows a reference to a pointer, but doesn''t allow a pointer to a
reference, why?
你错了：
int main（）
{
int i;
int& ref_i = i; //引用int
int * p =& i; //指向int的指针
int * p_ref =& ref_i; //指向int的引用的指针。
}
p_ref是指向引用的指针。
You''re mistaken:
int main()
{
int i;
int& ref_i = i; // reference to an int
int* p = &i; // pointer to an int
int* p_ref = &ref_i; // pointer to a reference to an int.
}
p_ref is a pointer to a reference.
我倾向于不同意。一旦参考坐下，任何使用它
实际上是指引用的对象，所以（p_ref =& ref_i）真的意味着
（p_ref =& i ），所以它是一个指向引用对象的指针，但不是
实际上是指向实际引用的指针。虽然，这可能会分裂
头发，我可以看到你的解释也可以看作是正确的，
因为参考文献本身并不存在。
I tend to disagree. Once a reference has been seated, any use of it
really refers to the referenced object, so (p_ref = &ref_i) really means
(p_ref = &i), so it is a pointer to the referenced object, but not
really a pointer to the actual reference. Though, this may be splitting
hairs, and I can see how your interpretation can be seen as correct too,
since a reference doesn''t really exist on its own.
现在引用只是别名
另一个变量，所以p_ref == p，
Now a reference is simply an alias
for another variable, so p_ref==p,
我同意。
This I agree with.
但这仍然与你的
前提相矛盾。
but that still contradicts your
premise.
-
Marcus Kwok
将''invalid''替换为''net''来回复
--
Marcus Kwok
Replace ''invalid'' with ''net'' to reply
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