生成多级JSON [英] Generating multi-level JSON
问题描述
我有一个对象数组,每个对象包含一个位置和一个不确定长度的链接数组。如何创建带循环的多级JSON对象?
I have an array of Objects, each containing a Location and a Links array of indeterminate length. How can I create a multilevel JSON object with loops?
结束JSON应该看起来像
The end JSON should look like
item1: [
{ "location": [
{"latitude": value, "longitude": value, "stopNum": value, "fileName": value }
],
"links": [
{"latitude": value, "longitude": value, "stopNum": value, "fileName": value },
{"latitude": value, "longitude": value, "stopNum": value, "fileName": value },
{"latitude": value, "longitude": value, "stopNum": value, "fileName": value }
]
}
],
item2: [ //repeat of above ]
我遇到的问题是如何正确形成对象。数组包含的对象定义为
The issue I'm having is how to correctly form the objects. The objects that the array contains are defined as
function Links(){
this.location = null;
this.links= [];
function getLocation(){
return location;
}
function setLocation(marker){
this.location = marker;
}
function getLinks(){
return links;
}
}
我目前的解决方案是
var json=[];
var linkData;
for (var i=0; i < tourList.length; i++){
var data = tourList[i];
//create new child array for insertion
var child=[];
//push location marker data
child.push({
latitude: data.location.position.$a,
longitude: data.location.position.ab,
stopNum: i,
filename: data.location.title
});
//add associated link data
for (var j=0; j<data.links.length; j++){
linkData = data.links[i];
child.push({
latitude: linkData.position.$a,
longitude: linkData.position.ab,
stopNum: i+j,
fileName: linkData.title
});
}
//push to json array
json.push(child);
}
//stringify the JSON and post results
var results= JSON.stringify(json);
然而,这不是很有效,因为
However, this is not quite working, as
$post= json_decode($_POST['json'])
PHP语句返回格式错误的数组,其中 $ post.length
被视为未定义的常量。我假设这是由于格式不正确。
PHP statement is returning a malformed array where $post.length
is seen as an undefined constant. I'm assuming that this is due to the incorrect formatting.
如上面定义的对象,我如何创建一个格式良好的JSON发送到服务器?
With objects defined above, how can I create a well-formed JSON to be sent to the server?
stringify()
的当前结果是
[
{"latitude":43.682211,"longitude":-70.45070499999997,"stopNum":0,"filename":"../panos/photos/1-prefix_blended_fused.jpg"},
[
{"latitude":43.6822,"longitude":-70.45076899999998,"stopNum":0,"fileName":"../panos/photos/2-prefix_blended_fused.jpg"}
],
{"latitude":43.6822,"longitude":-70.45076899999998,"stopNum":1,"filename":"../panos/photos/2-prefix_blended_fused.jpg"},
[
{"latitude":43.68218,"longitude":-70.45088699999997,"stopNum":1,"fileName":"../panos/photos/4-prefix_blended_fused.jpg"},
{"latitude":43.68218,"longitude":-70.45088699999997,"stopNum":2,"fileName":"../panos/photos/4-prefix_blended_fused.jpg"}
]
]
此外,我m使用 $ post.length
in
Also, I'm using $post.length
in
$post = json_decode($POST['json']);
for ($i=0; $i<$post.length; $i++) { }
迭代已处理的数组。
POST请求是通过 jQuery.ajax()
函数定义为
The POST request is via a jQuery.ajax()
function defined as
$.ajax({
type: "POST",
url: "../includes/phpscripts.php?action=postTour",
data: {"json":results},
beforeSend: function(x){
if (x && x.overrideMimeType){
x.overrideMimeType("application/json;charset=UTF-8");
}
},
success: function(data){
if (data == "success")
console.log("Tour update successful");
else
console.log("Tour update failed");
}
});
推荐答案
这应该有效。
var json = [];
var linkData;
for (var i = 0; i < tourList.length; i++) {
var data = tourList[i];
//create new child array for insertion
var child = [{ }];
//push location marker data
child[0]['location'] = [{
latitude: data.location.position.$a,
longitude: data.location.position.ab,
stopNum: i,
filename: data.location.title
}];
child[0]['links'] = [];
//add associated link data
for (var j = 0; j < data.links.length; j++) {
linkData = data.links[i];
child.links.push({
latitude: linkData.position.$a,
longitude: linkData.position.ab,
stopNum: i + j,
fileName: linkData.title
});
}
//push to json array
json.push(child);
}
//stringify the JSON and post results
var results = JSON.stringify(json);
但为什么输出JSON如此复杂?一种更简单的方法是使用这样的东西:
But why are you making the output JSON so complex? A simpler way would be to use something like this:
item1: {
"location": {
"latitude": value, "longitude": value, "stopNum": value, "fileName": value
},
"links": [
{"latitude": value, "longitude": value, "stopNum": value, "fileName": value },
{"latitude": value, "longitude": value, "stopNum": value, "fileName": value },
{"latitude": value, "longitude": value, "stopNum": value, "fileName": value }
]
},
item2: [ //repeat of above ]
您正在做的是为单个对象创建数组。为什么这样?如果你使用这种格式,代码(巧妙)简化:
What you are doing is creating 'arrays' for single objects. Why do that? If you use this format, the code (subtly) simplifies:
var json = [];
var linkData;
for (var i = 0; i < tourList.length; i++) {
var data = tourList[i];
//create new child array for insertion
var child = { };
//push location marker data
child.location = {
latitude: data.location.position.$a,
longitude: data.location.position.ab,
stopNum: i,
filename: data.location.title
};
child.links = [];
//add associated link data
for (var j = 0; j < data.links.length; j++) {
linkData = data.links[i];
child.links.push({
latitude: linkData.position.$a,
longitude: linkData.position.ab,
stopNum: i + j,
fileName: linkData.title
});
}
//push to json array
json.push(child);
}
//stringify the JSON and post results
var results = JSON.stringify(json);
这篇关于生成多级JSON的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!