复杂的表达 [英] Complex Expression
问题描述
亲爱的笔友
我是Anwar，请解释这个表达式如何变成24岁
{
int a = 10 ;
a = ++ a + ++ a;
cout<< a;
}
这个程序在屏幕上显示24，所以我无法理解这个表达式请解释它如何变成24
Dear thescripts
I am Anwar, please explain this expression how it becomes 24
{
int a = 10 ;
a = ++a + ++a;
cout << a ;
}
this program shows 24 on the screen so i can''t understand this expression please explain it how it becomes 24
推荐答案
Preincrement ++的优先级高于+。这就是为什么你的表达式
Preincrement ++ has higher precedence than +. That''s why in your expression
它的内存，...
++时a遇到了，a的地址值被改变了..所以当在第二个++ a时，同一个地址被改为12 ..
所以当加法运算时，12 +12被评估..
如果错误请告诉我答案...
its a thing of memory,..
when ++a is encountered, the value in address of a is changed.. so when in second ++a, the same address is changed as 12..
so when addition is operated, 12+12 is evaluated..
if wrong pls tell me the answer...
亲爱的帖子
我是安华，请解释这个表达式如何变成24
{
int a = 10;
a = ++ a + ++ a;
cout<< a;
}
这个程序在屏幕上显示24，所以我无法理解这个表达，请解释它如何变成24
Dear thescripts
I am Anwar, please explain this expression how it becomes 24
{
int a = 10 ;
a = ++a + ++a;
cout << a ;
}
this program shows 24 on the screen so i can''t understand this expression please explain it how it becomes 24
如果我们将其作为更改写出来，我们会看到：
a = 10
++ a + + + a
a = 11
a + ++ a
a = 12
a + a等于24.
但如果你把它写成
a = ++（a + a）
你会得到21 {++（10 + 10）}
- Miles
If we write it out as a changes we''d see this:
a = 10
++a + ++a
a = 11
a + ++a
a = 12
a + a which equals 24.
but if you wrote it as
a = ++(a + a)
you''d get 21 { ++( 10 + 10 ) }
- Miles
这篇关于复杂的表达的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
