< IMG>宽度高度 [英] <img> width height
问题描述
我试图能够操纵< img>的宽度和高度。但是好像没有b $ b。
是，我知道JavaScript会不操纵任何东西，这没关系。我
根本就不知道如何捕捉宽度或高度。一旦我能做到这一点，我就可以操纵它们。
这是< img>
<的HTML div class =" ImgMnp" ID = QUOT; myImg" onmouseover =" imgSize（''myImg''，''fpImg）">
< img src =" images / FirePlace.jpg"宽度= QUOT; 480"高度= QUOT; 640" ID = QUOT; fpImg" />
< / div>
这是我试图操纵< img>
函数的JavaScript imgSize（myID，myImg）
{
var myDiv = document.getElementById（myID）; //得到正确< div>
var myImage = document.getElementById（myImg）; //得到正确< img>
var myWidth = myImage.style.width; //尝试捕获< img>的宽度
var myHeight = myHeight.style.height; //尝试捕获< img>
alert（" myWidth +，+ myHeight"）的高度; //显示我这个功能是否有效
}
有人请告诉我我做错了什么
-
Totus负鼠，总计Deum。
Totus ero，totum meum。
WSW
操纵< img>的宽度和高度但似乎没有。
是的，我知道JavaScript会不。操纵任何东西，这没关系。我根本不知道如何捕捉宽度或高度。一旦我能做到这一点，我就可以操纵它们。
这是< img>
< div class =" ImgMnp"的HTML。 ID = QUOT; myImg" onmouseover =" imgSize（''myImg''，''fpImg）">
此行中有一个语法错误，接近结尾。你是
错过了撇号。它应该去：
< div class =" ImgMnp" ID = QUOT; myImg" onmouseover =" imgSize（''myImg''，''fpImg''）;">
我不知道这是不是破坏了代码的原因。
新闻aécrit：我试图能够操纵< img>的宽度和高度但似乎没有能力。
< div class =" ImgMnp" ID = QUOT; myImg" onmouseover =" imgSize（''myImg''，''fpImg）">
< img src =" images / FirePlace.jpg"宽度= QUOT; 480"高度= QUOT; 640" ID = QUOT; fpImg" />
< / div>
以下是我试图操纵< img>
函数imgSize（myID，myImg）
{
var myDiv = document.getElementById（myID）; //得到正确的< div>
var myImage = document.getElementById（myImg）; //得到正确< img>
var myWidth = myImage.style.width; //尝试捕获< img>
var myHeight = myHeight.style.height的宽度; //尝试捕获< img>
警报的高度（" myWidth +，+ myHeight"）; //显示我这个功能是否有效
有人请告诉我我做错了什么
最简单的方法：
< img src =" pict.jpg"
onmousover =" alert（''width =''+ this.width +''height =''+ this.height）" ;;>
也许你的代码会更好用：
var myWidth = myImage。风格和放大器;&放大器; myImage.style.width？ myImage.style.width：
myImage.width; //尝试捕获< img>
var myWidth = myImage.style&& myImage.style.height的宽度？ myImage.style.height：
myImage.height; //尝试捕捉< img>的高度
想法：
如果你的图像没有宽度或高度样式，你可以'抓住它。
-
Stephane Moriaux et son [moins] vieux Mac
test写道：2006年4月21日星期五21:46:37 GMT，新闻写道：
我试图能够操纵宽度和/的高度
< img>但似乎不能。
是的，我知道JavaScript会不。操作任何东西，这没关系。
我根本不知道如何捕捉宽度或高度。一旦我能够这样做，我就可以操纵它们。
这是< img>
< div class =" ImgMnp"的HTML。 ID = QUOT; myImg" onmouseover =" imgSize（''myImg''，''fpImg）">
此行中有一个语法错误，接近结尾。你错过了撇号。它应该去：
< div class =" ImgMnp" id =" myImg"
onmouseover =" imgSize（''myImg''，''fpImg''）;">
不知道那是什么意思虽然打破了密码。
我不知道我需要那个撇号谢谢。
Nope没有解决问题，如果我取出这两行
var myWidth = myImage.style.width;
var myHeight = myHeight.style.height;
功能正常，将它们放入功能崩溃中。
-
Totus负鼠，总计Deum。
Totus ero，totum meum。
WSW
I am trying to be able to manipulate the width and height of an <img> but do
not seem to be able.
"Yes", I know the JavaScript will "not" manip anything, which is ok. I
simply do not know how to capture the width or height. Once I can do that I
can manipulate them.
Here is the HTML for the <img>
<div class="ImgMnp" id="myImg" onmouseover="imgSize(''myImg'',''fpImg)">
<img src="images/FirePlace.jpg" width="480" height="640" id="fpImg" />
</div>
Here is the JavaScript I tried to manipulate the <img>
function imgSize(myID,myImg)
{
var myDiv= document.getElementById(myID); //get correct <div>
var myImage=document.getElementById(myImg); //get correct <img>
var myWidth=myImage.style.width; //attempt to capture width of <img>
var myHeight=myHeight.style.height; //attempt to capture height of <img>
alert("myWidth+, +myHeight"); //show if I this function works
}
Will someone please tell me what I am doing wrong
--
Totus possum, totum Deum.
Totus ero, totum meum.
WSW
On Fri, 21 Apr 2006 21:46:37 GMT, News wrote:
I am trying to be able to manipulate the width and height of an <img> but do
not seem to be able.
"Yes", I know the JavaScript will "not" manip anything, which is ok. I
simply do not know how to capture the width or height. Once I can do that I
can manipulate them.
Here is the HTML for the <img>
<div class="ImgMnp" id="myImg" onmouseover="imgSize(''myImg'',''fpImg)">
There is a syntax error in this line, near the end. You''re
missing an apostrophe. It should go:
<div class="ImgMnp" id="myImg" onmouseover="imgSize(''myImg'',''fpImg'');">
Don''t know if that was what was breaking the code though.
News a écrit :I am trying to be able to manipulate the width and height of an <img> but do
not seem to be able. <div class="ImgMnp" id="myImg" onmouseover="imgSize(''myImg'',''fpImg)">
<img src="images/FirePlace.jpg" width="480" height="640" id="fpImg" />
</div>
Here is the JavaScript I tried to manipulate the <img>
function imgSize(myID,myImg)
{
var myDiv= document.getElementById(myID); //get correct <div>
var myImage=document.getElementById(myImg); //get correct <img>
var myWidth=myImage.style.width; //attempt to capture width of <img>
var myHeight=myHeight.style.height; //attempt to capture height of <img>
alert("myWidth+, +myHeight"); //show if I this function works
}
Will someone please tell me what I am doing wrong
simplest way :
<img src="pict.jpg"
onmousover="alert(''width = ''+this.width+'' height = ''+this.height)";>
maybe your code would be better with :
var myWidth= myImage.style&&myImage.style.width? myImage.style.width :
myImage.width; //attempt to capture width of <img>
var myWidth= myImage.style&&myImage.style.height? myImage.style.height :
myImage.height; //attempt to capture height of <img>
idea :
If your image didn''t get a width or height style, you can''t catch it.
--
Stephane Moriaux et son [moins] vieux Mac
test wrote:On Fri, 21 Apr 2006 21:46:37 GMT, News wrote:I am trying to be able to manipulate the width and height of an
<img> but do not seem to be able.
"Yes", I know the JavaScript will "not" manip anything, which is ok.
I simply do not know how to capture the width or height. Once I can
do that I can manipulate them.
Here is the HTML for the <img>
<div class="ImgMnp" id="myImg" onmouseover="imgSize(''myImg'',''fpImg)">
There is a syntax error in this line, near the end. You''re
missing an apostrophe. It should go:
<div class="ImgMnp" id="myImg"
onmouseover="imgSize(''myImg'',''fpImg'');">
Don''t know if that was what was breaking the code though.
I did not know I need that apostrophe thanks.
Nope did not correct the problem, if I take out these two lines
var myWidth=myImage.style.width;
var myHeight=myHeight.style.height;
the function works, put them in the function crashes.
--
Totus possum, totum Deum.
Totus ero, totum meum.
WSW
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