如何使用长双浮？ [英] How to use long double floating?
问题描述
指南说在printf（）函数中使用％f，使用关键字
float和double。
例如
浮动a = 1.2345;
双b = 5.166666667;
printf（"％。2f \ n％f \ n"，a，b）;
现在，我想使用long double而不是double来获得准确度
十进制数，它比正常值大数字如亿元
数字。我认为它将是％dd，但它不正确。你可以吗？
请提供它支持的长双倍的信息吗？
谢谢...
布莱恩·帕克夫
Bryan Parkoff写道：该指南说使用关键字
在printf（）函数中使用％f漂浮和双倍。
在printf函数族中使用％f来输出''float''类型的值
或''double''。同样的说明符适用于两者的原因是任何
类型''float''的值都被提升为''double''。
例如
浮动a = 1.2345;
双b = 5.166666667;
printf（"％。2f \ n％f \ n"，a，b）;
现在，我想使用long double而不是double来获得精确度十进制数，它比正常数字（如十亿数字）大。我认为它将是％dd，但它不正确。可以吗>请你提供它支持的信息长一倍，
好吗？谢谢...
标准规定你应该使用''L''宽度前缀（比如
％.2Lf
）输出''long double''值。
V
" Victor Bazarov" <五******** @ comAcast.net>在消息中写道
新闻：Qr ******************** @ comcast.com ...布莱恩Parkoff写道：指南说使用关键字
float和double在printf（）函数中使用％f。
使用％f in printf函数族输出类型''float''
或''double''的值。同样的说明符适用于两者的原因是任何类型''float''的值都被提升为''double''。
例子
浮动a = 1.2345;
双b = 5.166666667;
printf（"％。2f \ n％f \ n"，a， b）;
现在，我想使用long double而不是double来获得准确度十进制数，它比正常数字（如十亿数字）大。我认为它将是％dd，但它不正确。可以吗>请你提供它支持的信息长一倍，
好吗？谢谢......
标准规定你应该使用''L''宽度前缀（比如
％。2Lf
）输出''long double''值。
V
Victor，
谢谢为我提供答案，但这个十进制有6位数字
在。之后。它需要是10位到20位数才能获得最佳精确度十进制值
数字。 ％Lf怎么可能有帮助？ ％Lf仍然提供6位数。
如何克服限制？
Bryan Parkoff
" Bryan Parkoff" <无** @ nospam.net>在消息中写道
新闻：Xh ******************* @ newssvr21.news.prodigy。 com ...
" Victor Bazarov" <五******** @ comAcast.net>在消息中写道
新闻：Qr ******************** @ comcast.com ...Bryan Parkoff写道：< blockquote class =post_quotes>指南说使用关键字
float和double在printf（）函数中使用％f。
在printf函数族中使用％f输出类型''float''
或''double''的值。同样的说明符适用于两者的原因是任何类型''float''的值都被提升为''double''。
例子
浮动a = 1.2345;
双b = 5.166666667;
printf（"％。2f \ n％f \ n"，a， b）;
现在，我想使用long double而不是double来获得准确度十进制数，它比正常数字（如十亿数字）大。我认为它将是％dd，但它不正确。可以吗>请你提供它支持的信息长一倍，
好吗？谢谢......
标准规定你应该使用''L''宽度前缀（比如
％。2Lf
）输出''long double''值。
V
Victor，
感谢您给我答案，但是这个十进制有6位数字
在。之后。它需要是10位到20位才能获得最佳精度
十进制数。 ％Lf怎么可能有帮助？ ％Lf仍提供6位数字。我如何克服限制？
printf（"％。20Lf \ n"，b）;
你的教科书在哪里？
-Mike
The guideline says to use %f in printf() function using the keyword
float and double.
For example
float a = 1.2345;
double b = 5.166666667;
printf("%.2f\n %f\n", a, b);
Now, I want to use long double rather than double to get accuracy
decimal number which it is larger than normal number such as billion
numbers. I assume that it would be %dd, but it is not correct. Can you
please provide the information which it support long double, please?
Thanks...
Bryan Parkoff
Bryan Parkoff wrote:The guideline says to use %f in printf() function using the keyword
float and double.
Use %f in printf family of functions to output a value of type ''float''
or ''double''. The reason the same specifier works for both is that any
value of type ''float'' is promoted to ''double'' anyway.
For example
float a = 1.2345;
double b = 5.166666667;
printf("%.2f\n %f\n", a, b);
Now, I want to use long double rather than double to get accuracy
decimal number which it is larger than normal number such as billion
numbers. I assume that it would be %dd, but it is not correct. Can
you please provide the information which it support long double,
please? Thanks...
The Standard specifies that you should use ''L'' width prefix (like
%.2Lf
) to output a ''long double'' value.
V
"Victor Bazarov" <v.********@comAcast.net> wrote in message
news:Qr********************@comcast.com...Bryan Parkoff wrote:The guideline says to use %f in printf() function using the keyword
float and double.
Use %f in printf family of functions to output a value of type ''float''
or ''double''. The reason the same specifier works for both is that any
value of type ''float'' is promoted to ''double'' anyway.
For example
float a = 1.2345;
double b = 5.166666667;
printf("%.2f\n %f\n", a, b);
Now, I want to use long double rather than double to get accuracy
decimal number which it is larger than normal number such as billion
numbers. I assume that it would be %dd, but it is not correct. Can
you please provide the information which it support long double,
please? Thanks...
The Standard specifies that you should use ''L'' width prefix (like
%.2Lf
) to output a ''long double'' value.
V
Victor,
Thank you for providing me the answer, but this decimal has 6 digits
after ".". It needs to be 10 digits to 20 digits for best accuracy decimal
numbers. How is it possible that %Lf help? %Lf still provides 6 digits.
How do I overcome the limit?
Bryan Parkoff
"Bryan Parkoff" <no**@nospam.net> wrote in message
news:Xh*******************@newssvr21.news.prodigy. com...
"Victor Bazarov" <v.********@comAcast.net> wrote in message
news:Qr********************@comcast.com...Bryan Parkoff wrote:The guideline says to use %f in printf() function using the keyword
float and double.
Use %f in printf family of functions to output a value of type ''float''
or ''double''. The reason the same specifier works for both is that any
value of type ''float'' is promoted to ''double'' anyway.
For example
float a = 1.2345;
double b = 5.166666667;
printf("%.2f\n %f\n", a, b);
Now, I want to use long double rather than double to get accuracy
decimal number which it is larger than normal number such as billion
numbers. I assume that it would be %dd, but it is not correct. Can
you please provide the information which it support long double,
please? Thanks...
The Standard specifies that you should use ''L'' width prefix (like
%.2Lf
) to output a ''long double'' value.
V
Victor,
Thank you for providing me the answer, but this decimal has 6 digits
after ".". It needs to be 10 digits to 20 digits for best accuracy
decimal numbers. How is it possible that %Lf help? %Lf still provides 6
digits. How do I overcome the limit?
printf("%.20Lf\n", b);
Where''s your textbook?
-Mike
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