更快地填充字节数组的方法 [英] Faster way to fill a byte array
问题描述
全部，
在C＃中有更快的方法吗：
byte []缓冲区;
buffer = new byte [43];
for（int i = 0; i< buffer.Length; i ++）
buffer [i ] = 0;
Dave
All,
Is there a faster way to do this in C#:
byte[] buffer;
buffer = new byte[43];
for(int i = 0; i < buffer.Length; i++)
buffer[i] = 0;
Dave
推荐答案
D.耶茨< fo **** @ hotmail.com>写道：
D. Yates <fo****@hotmail.com> wrote:
全部，
在C＃中有更快的方法吗：
byte [] buffer;
buffer =新字节[43];
for（int i = 0; i< buffer.Length; i ++）
buffer [i] = 0;
All,
Is there a faster way to do this in C#:
byte[] buffer;
buffer = new byte[43];
for(int i = 0; i < buffer.Length; i++)
buffer[i] = 0;
是：
byte [] buffer = new byte [43];
保证一开始就是零。
-
Jon Skeet - < sk *** @ pobox.com>
如果回复小组，请不要给我发邮件
Yes:
byte[] buffer = new byte[43];
It''s guaranteed to be all zeroes to start with.
--
Jon Skeet - <sk***@pobox.com>
http://www.pobox.com/~skeet Blog: http://www.msmvps.com/jon.skeet
If replying to the group, please do not mail me too
戴夫，
是的：
byte [] buffer;
buffer = new byte [43];
默认情况下，结构数组的元素与那些相同
结构，位为零ut，这正是你想要的。
希望这会有所帮助。
-
- Nicholas Paldino [.NET / C＃MVP]
- mv*@spam.guard.caspershouse.com
D。耶茨" < FO **** @ hotmail.com>在消息中写道
news：e
Dave,
Yes:
byte[] buffer;
buffer = new byte[43];
By default, elements of arrays of structures are the same as those
structures with the bits zeroed out, which is exactly what you want.
Hope this helps.
--
- Nicholas Paldino [.NET/C# MVP]
- mv*@spam.guard.caspershouse.com
"D. Yates" <fo****@hotmail.com> wrote in message
news:e
************** @ TK2MSFTNGP14.phx.gbl ...
**************@TK2MSFTNGP14.phx.gbl...
全部，
在C＃中有更快的方法吗：
byte [] buffer;
buffer = new byte [43 ];
for（int i = 0; i< buffer.Length; i ++）
buffer [i] = 0;
Dave
All,
Is there a faster way to do this in C#:
byte[] buffer;
buffer = new byte[43];
for(int i = 0; i < buffer.Length; i++)
buffer[i] = 0;
Dave
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