如何通过值(而非键)比较2个数组的哈希值 [英] How to compare 2 hashes of arrays by values(not keys)
问题描述
嗨
我的数组上有哈希值,例如,
%h1 =(''''=> [''abc'',' 'def''],
''b''=> [''ghi'',''jkl''],
''c''= > [''hop'',''uio'']
);
%h2 =(''a''=> [ ''abc'',''def''],
''b''=> [''wert'',''wer'']);
然后,我如何比较2个哈希值(基于值。不是键)并获得不同的值?
任何解决方案都将不胜感激.....
问题不是很清楚。我不理解你想用什么标准来比较哈希值(它是内部数组 - 比较长度或数组的元素??)。另外,让我们知道你到目前为止尝试了什么。
但是,首先,如果你想获得哈希的值,你可以使用''values''关键字。
例如
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感谢您的回复。
i想要比较的值%h1的值为%h2,最终结果为
(%h1的值,%h1而不是%h2)
结果是:
[''ghi'',''jkl'']
[''hop''' UIO]
(因为,这些都不是在%H 2)。
我想上面的输出。我怎么能这样做?????
感谢您的回复。
i想要比较这些值%h1的值为%h2,最终结果为
(%h1的值,%h1,而不是%h2)
结果是:
[''ghi'',''jkl'']
[''hop''''uio'']
(因为,这些不在%h2中)。
我想要上面的输出。我怎样才能做到这一点?????
您可以使用Data :: Compare模块来比较perl中的数据结构。
展开 | 选择 | Wrap | 行号< /跨度>
Hi
I have hashes with arrays to its keys like,
%h1 = (''a''=>[''abc'',''def''],
''b''=>[''ghi'',''jkl''],
''c''=>[''hop'',''uio'']
);
%h2 = (''a''=>[''abc'',''def''],
''b''=>[''wert'',''wer'']);
then, how can i compare the 2 hashes(based on values. not keys) and get distinct values ?
Any solution will be appreciated.....解决方案The question is not very clear. I am not understanding with what criteria you want to compare the values of hashes(which are inturn arrays-compare lengths or elements of array??) . Also, let us know what have you tried so far.
However, to begin with if you are trying to get values of the hash, you may use ''values'' keyword.
e.g.
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Thanks for responding.
i want to compare the values of %h1 with values of %h2 and the final result will be
( the values of %h1, which are in %h1 and not in %h2)
Result is :
[''ghi'' , ''jkl'' ]
[ ''hop'' '' uio'']
(since, these are not in %h2).
I want the above output. How can i do this?????
Thanks for responding.
i want to compare the values of %h1 with values of %h2 and the final result will be
( the values of %h1, which are in %h1 and not in %h2)
Result is :
[''ghi'' , ''jkl'' ]
[ ''hop'' '' uio'']
(since, these are not in %h2).
I want the above output. How can i do this?????You can make use of Data::Compare module to compare data structures in perl.
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