用户在线/离线状态问题 [英] Problem of user online/ offline status
问题描述
我想知道如何检查该用户是在线还是离线状态如果
他在< body onunload>的帮助下关闭了他的浏览器。因为它无法工作
如果是用户更改他的页面，那时它太过火了。我想
只有在用户关闭浏览器时触发功能。
I want to know how to check that user is online or offline status if
he close his browser with the help of <body onunload>.As it not work
well if is user change his page as that time it is too fired.I want
only to fire function if user closed browser.
推荐答案
" Php Developer" < ph *************** @ gmail.com写信息
新闻：6f *************** ******************* @ s8g2000p rg.googlegroups.com ...
"Php Developer" <ph***************@gmail.comwrote in message
news:6f**********************************@s8g2000p rg.googlegroups.com...
>我想要知道如何检查用户是在线还是离线状态如果
他在< body onunload>的帮助下关闭了他的浏览器。因为它不起作用
如果是用户改变他的页面，因为它太过火了。我想
只有在用户关闭浏览器时才能触发功能。
>I want to know how to check that user is online or offline status if
he close his browser with the help of <body onunload>.As it not work
well if is user change his page as that time it is too fired.I want
only to fire function if user closed browser.
呃，什么？谷歌石斑鱼，数字。
在任何情况下，你都无法可靠地知道观众什么时候停止。看着你的
页面。 onunload不起作用 - 如果他们只是拔掉他们的
计算机上的插头或者徘徊到酒吧怎么办？
经常被问到这个问题。谷歌。
-
理查德。
Er, what? Google grouper, figures.
In any case you can not reliably know when a viewer "stops" looking at your
page. onunload does not work - what if they simply pull the plug on their
computer or wander off down to the pub?
This is asked frequently. Google.
--
Richard.
如果可能的话，我需要一些帮助才能使它工作。
谢谢
Hi,
What i need some help to make it work if possible any ways pls tell
Thanks
I想要知道如何检查该用户是在线还是离线状态如果
他在< body onunload>的帮助下关闭了他的浏览器。因为它不起作用
如果是用户更改他的页面，因为它太过火了。我想
只有在用户关闭浏览器时触发功能。
I want to know how to check that user is online or offline status if
he close his browser with the help of <body onunload>.As it not work
well if is user change his page as that time it is too fired.I want
only to fire function if user closed browser.
文章< 80 ********************** ************ @ s12g2000prg。 googlegroups.com>，Php开发人员< ph *************** @ gmail.comwrote：
In article <80**********************************@s12g2000prg. googlegroups.com>, Php Developer <ph***************@gmail.comwrote:
>
我需要一些帮助才能让它工作如果可能的话任何方式请告诉
>Hi,
What i need some help to make it work if possible any ways pls tell
当观众停止观看时你无法可靠地知道什么部分在你的
页面''你不明白吗？
What part of ''you can not reliably know when a viewer stops looking at your
page'' did you not understand?
谢谢
Thanks
>我想知道如何检查该用户是在线还是离线状态如果
他在< body onunload>的帮助下关闭了他的浏览器。作为它不工作
如果是用户更改他的页面，那时它太过火了。我想
只有在用户关闭浏览器时触发功能。
>I want to know how to check that user is online or offline status if
he close his browser with the help of <body onunload>.As it not work
well if is user change his page as that time it is too fired.I want
only to fire function if user closed browser.
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