DLL导出，修饰功能 [英] DLL export, decorated function
问题描述
你好，
我正在研究一个小DLL，它将用作
工作应用程序的扩展。要求DLL只有一个名为
" C16_DLLCALL"的导出。所以我开始在Visual C ++ 2008中使用Win32
应用程序向导为DLL创建一个DLL，并对其进行了更改，以便它适用于我们的
应用程序。
但是当我构建DLL文件并使用dumpbin.exe / exports查看它时，导出的函数并不完全称为C16_DLLCALL。根据
函数声明，我得到以下出口名称之一：
？C16_DLLCALL @@ YAHPAUvC16_CCB @@@ Z =？C16_DLLCALL @@ YAHPAUvC16_CCB @ @@ Z（int
__cdecl C16_DLLCALL（struct vC16_CCB *））
使用时：__ declspec（dllexport）[...]
C16_DLLCALL = _C16_DLLCALL
使用时：extern" C" __declspec（dllexport）[...]
我有一个来自应用程序开发人员的示例DLL，当我使用dumpbin查看
时，它确切地说具有所需的名称，没有相同的标志或
其他字符，只是简单的C16_DLLCALL - 在这种情况下，
应用程序在dll中找到入口点。但是对于任何我的
DLL，它都会失败。
如何在不改变导出名称的情况下导出函数？
谢谢，
Patrick Westerhoff
Hello,
I''m currently working on a small DLL that will be used as an extension to a
working application. It is required that the DLL has only one export named
"C16_DLLCALL". So I started creating a DLL in Visual C++ 2008 using the Win32
application wizard for DLLs and changed it so it would work for our
application.
However when I build the DLL file and look at it using dumpbin.exe /exports,
the exported function is not exactly called "C16_DLLCALL". Depending on the
function declaration I get one of the following export names:
?C16_DLLCALL@@YAHPAUvC16_CCB@@@Z = ?C16_DLLCALL@@YAHPAUvC16_CCB@@@Z (int
__cdecl C16_DLLCALL(struct vC16_CCB *))
when using: __declspec(dllexport) [...]
C16_DLLCALL = _C16_DLLCALL
when using: extern "C" __declspec(dllexport) [...]
I have got a example DLL from the application developers and when I look at
it using dumpbin, it exactly has the required name, without equally signs or
other characters, just a plain "C16_DLLCALL" - and in that case the
application finds the entry point within the dll. However with any of my
DLLs, it fails.
How can I export the function without having its export name changed at all?
Thank you,
Patrick Westerhoff
推荐答案
嗨帕特里克，
Hi Patrick,
...我希望有一个名为C16_DLLCALL的出口。
...但我得到......
C16_DLLCALL = _C16_DLLCALL
使用时：extern" C" __declspec（dllexport）[...]
... I like to have one export named "C16_DLLCALL".
... but I get ...
C16_DLLCALL = _C16_DLLCALL
when using: extern "C" __declspec(dllexport) [...]
在项目中添加一个def文件
http://msdn.microsoft.com/en-us/libr...sh （VS.80）.aspx
-
SvenC
Add a def file to your project
http://msdn.microsoft.com/en-us/libr...sh(VS.80).aspx
--
SvenC
你好SvenC，
谢谢你的回答。我现在尝试了但收到了以下
出口：
C16_DDLCALL =？C16_DLLCALL @@ CAHPAUvC16_CCB @@@ Z（int __cdecl
C16_DLLCALL（struct vC16_CCB *））
仅使用.def文件时函数中没有任何其他内容
声明
和<当使用.def和externC时，
C16_DDLCALL = _C16_DDLCALL
__declspec（dllexport）
两个都不在申请中工作:(
Patrick Westerhoff
" SvenC"写道：
Hi SvenC,
thank you for your answer. I tried that now but received the following
exports:
C16_DDLCALL = ?C16_DLLCALL@@CAHPAUvC16_CCB@@@Z (int __cdecl
C16_DLLCALL(struct vC16_CCB *))
when using only the .def file without any additional things in the function
declaration
and
C16_DDLCALL = _C16_DDLCALL
when using the .def with extern "C" __declspec(dllexport)
both don''t work in the application :(
Patrick Westerhoff
"SvenC" wrote:
嗨Patrick，
为你的项目添加一个def文件
http：// msdn.microsoft.com/en-us/libr...sh(VS.80).aspx
-
SvenC
Hi Patrick,
Add a def file to your project
http://msdn.microsoft.com/en-us/libr...sh(VS.80).aspx
--
SvenC
嗨帕特里克，
Hi Patrick,
谢谢你的回答。我现在尝试了但收到了以下
出口
thank you for your answer. I tried that now but received the following
exports
重读文章并找到：
"如果你*不使用* __declspec（dllexport）要导出的关键字
DLL的函数，DLL需要.def文件。
相反，你应该指定调用公约明确地在你的
heade中r这样你就不依赖于vc项目默认值了。
externC __stdcall C16_DDLCALL（struct vC16_CCB *）;
-
SvenC
Reread the article and find:
"If you are *not using* the __declspec(dllexport) keyword to export
the DLL''s functions, the DLL requires a .def file."
Instead you should specify the calling convention explicitly in your
header so that you do not depend on vc project defaults.
extern "C" __stdcall C16_DDLCALL(struct vC16_CCB *);
--
SvenC
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