使用巴比伦算法找到平方根 [英] Using Babylonian algorithm to find square root

问题描述

我的程序正在尝试使用巴比伦算法来查找平方根...我有一个数字用于得到平方根，并且还有一个数字来运行循环...每当我走打印答案的四舍五入而不是给我我需要的答案......任何帮助??

my program is trying to use the babylonian algorithm in order to find the square root... i have a number for the number to have the square root taken of and also a number to run the loop... Whenever i go to print out the answer its rounding instead of giving me the answer i need... any help??

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推荐答案

for（double count = 1; count< = num2; count ++）;

for (double count = 1; count <= num2; count++);

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socondc22-


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谢谢

socondc22-

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Thanks

再看看这一行.....

Just TAKE A LOOK at this line again.....

我仍​​然不喜欢不知道出了什么问题...

I still don''t know what is wrong...

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