获取方法参数的对象数组 [英] getting object array of method parameters

问题描述

给定一个方法如下
public byte [] ReadFile（string filename，int offset，int bufferSize，bool eof


我可以吗得到一个参数的对象数组，它将适用于任何方法而无需显式创建它mysel


在这种情况下相当于t


object [] ps = new object [] {filename，offset，bufferSize，eof}


Stev

Given a method lik

public byte[] ReadFile(string filename,int offset, int bufferSize, bool eof

can I get an object array of the parameters which will work with any method without explicitly creating it mysel

in this case equivalent t

object[] ps = new object[]{filename,offset,bufferSize,eof}

Stev

推荐答案

你可以通过反思：


class myClass

{

publiic void method1（string imp1）

{$ $
}

}

.....


Tyope t = typeof（myClass）;

MemberInfo mi = t.GetMethod（" method1"，BindingFlags.Instance）;

ParameterInfo [] pi = mi.GetParameters（）;

从这里你可以完全访问方法的参数。


干杯，

Branimir


-

Branimir Giurov

MCSD.NET，M CDBA，MCT

eAgility LLC

" Steve" <一个******* @ discussions.microsoft.com>在留言中写道

news：06 ********************************** @ microsof t.com ...

You can through Reflection:

class myClass
{
publiic void method1(string imp1)
{

}
}
.....

Tyope t = typeof(myClass);
MemberInfo mi = t.GetMethod("method1", BindingFlags.Instance);
ParameterInfo[] pi = mi.GetParameters();
From here on you have full access to the params of the method.

Cheers,
Branimir

--
Branimir Giurov
MCSD.NET, MCDBA, MCT
eAgility LLC
"Steve" <an*******@discussions.microsoft.com> wrote in message
news:06**********************************@microsof t.com...

给定一个方法，如

public byte [] ReadFile（string filename，int offset，int bufferSize，bool
eof）方法，而无需自己明确地创建它
在这种情况下相当于

对象[] ps =新对象[] {filename，offset，bufferSize，eof};

史蒂夫

Given a method like

public byte[] ReadFile(string filename,int offset, int bufferSize, bool eof)
can I get an object array of the parameters which will work with any method without explicitly creating it myself
in this case equivalent to

object[] ps = new object[]{filename,offset,bufferSize,eof};

Steve

你可以通过反思：


class myClass

{

publiic void method1（string imp1）

{


}

}

.....


Tyope t = typeof（myClass） ;

MemberInfo mi = t.GetMethod（" method1"，BindingFlags.Instance）;

ParameterInfo [] pi = mi.GetParameters（）;

从这里开始，您可以完全访问该方法的参数。


干杯，< br $>
Branimir


-

Branimir Giurov

MCSD.NET，MCDBA，MCT
eAgility LLC

" Steve" <一个******* @ discussions.microsoft.com>在留言中写道

news：06 ********************************** @ microsof t.com ...

You can through Reflection:

class myClass
{
publiic void method1(string imp1)
{

}
}
.....

Tyope t = typeof(myClass);
MemberInfo mi = t.GetMethod("method1", BindingFlags.Instance);
ParameterInfo[] pi = mi.GetParameters();
From here on you have full access to the params of the method.

Cheers,
Branimir

--
Branimir Giurov
MCSD.NET, MCDBA, MCT
eAgility LLC
"Steve" <an*******@discussions.microsoft.com> wrote in message
news:06**********************************@microsof t.com...

给定一个方法，如

public byte [] ReadFile（string filename，int offset，int bufferSize，bool
eof）方法，而无需自己明确地创建它
在这种情况下相当于

对象[] ps =新对象[] {filename，offset，bufferSize，eof};

Steve

Given a method like

public byte[] ReadFile(string filename,int offset, int bufferSize, bool eof)
can I get an object array of the parameters which will work with any method without explicitly creating it myself
in this case equivalent to

object[] ps = new object[]{filename,offset,bufferSize,eof};

Steve

Branimir Giurov< br * *****@nospam.com>写道：

Branimir Giurov <br******@nospam.com> wrote:

你可以通过反思：

类myClass
{publiic void method1（string imp1）
{

}
}
....

Tyope t = typeof（myClass）;
MemberInfo mi = t.GetMethod（" method1"， BindingFlags.Instance）;
ParameterInfo [] pi = mi.GetParameters（）;

从这里开始，您可以完全访问方法的参数。

You can through Reflection:

class myClass
{
publiic void method1(string imp1)
{

}
}
....

Tyope t = typeof(myClass);
MemberInfo mi = t.GetMethod("method1", BindingFlags.Instance);
ParameterInfo[] pi = mi.GetParameters();

From here on you have full access to the params of the method.

你知道他们的类型和名字，但是你没有*可以访问他们的

值，这是OP所追求的，我相信。 />

-

Jon Skeet - < sk *** @ pobox.com>
http://www.pobox.com/~skeet

如果回复该群组，请不要也寄给我

You know their types and names, but you *don''t* have access to their
values, which is what the OP was after, I believe.

--
Jon Skeet - <sk***@pobox.com>
http://www.pobox.com/~skeet
If replying to the group, please do not mail me too

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