值类型的数组 [英] Array of value types

问题描述

嗨。


我有一个struct数组。

我的问题是，如果我这样做：

STRUCT [ ] a = new STRUCT [0xA];

STRUCT s = new STRUCT（）;

a [0x0] = s;


由于STRUCT是一个值类型，当如上所述分配STRUCT数组的元素0

时，

是STRUCT然后复制到数组，就像通常的情况一样值类型？

我想是的。


这种结构很重。

它也是一个托管结构因此我不能使用指针。


我的选择可能是，而不是分配元素，

直接使用数组索引（很多索引然后）：


STRUCT [] a =新STRUCT [0xA];

a [0x0] .PROPERTY = 0x0;

请给我一些想法。


谢谢！


-

问候，

DennisJDMyrén

奥斯陆Kodebureau

Hi.

I have an array of struct.
My question is, if i do:
STRUCT [] a = new STRUCT [0xA];
STRUCT s = new STRUCT();
a [0x0] = s;

since STRUCT is a value type, when assigning element 0 of the STRUCT array
as above,
is the STRUCT then copied to the array, as is the usual case of value types?
I guess it is.

This structure is kind of heavy.
It is as well a managed struct, therefore i cannot use pointers.

My option might be to, rather than assigning the elements,
to use the array directly with indexing(a lot of indexing then):

STRUCT [] a = new STRUCT [0xA];
a [0x0].PROPERTY = 0x0;
Please give me some thoughts about this.

Thank you!

--
Regards,
Dennis JD Myrén
Oslo Kodebureau

推荐答案

如果这是实际情况，你可以改变


STRUCT [] a =新STRUCT [0xA];

STRUCT s = new STRUCT（）;

a [0x0] = s;


到


STRUCT [] a =新的STRUCT [0xA];


因为数组的每个元素都是一个初始化的结构体，就像defauly构造函数已经运行一样 - 你可以在[1]中读取我的博客条目价值类型初始化的详细信息


如果不是这种情况，那么是的，你会得到一份副本，但是有任何机会发布更接近ral情况的代码，所以我们可以更具体地建议


[1] http://staff.develop.com/richardb/we...c-b73640f24314


问候


Richard Blewett - DevelopMentor
http://staff.develop.com/richardb/weblog

nntp：//news.microsoft.com/microsoft.public.dotnet.languages。 csharp /< BC **************** @ news4.e.nsc.no>


嗨。


我有一个struct数组。

我的问题是，如果我这样做：

STRUCT [] a = new STRUCT [0xA];

STRUCT s = new STRUCT（）;

a [0x0] = s;


因为STRUCT是一个值类型，当分配元素时如上所述STRUCT数组的0

，

是STRUCT然后复制到数组，通常是值类型的情况吗？

我想是的。


这种结构很重。

它也是一个托管结构，因此我不能使用指针。


我的选择可能是，而不是分配元素，

直接使用数组索引（当时有很多索引）：

STRUCT [] a =新STRUCT [0xA];

a [0x0] .PROPERTY = 0x0;

请给我对此有些想法。


谢谢！


-

问候，

Dennis JD Myr？n

奥斯陆Kodebureau


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[microsoft.public。 dotnet.languages.csharp]

If this is the actual situation, you can change

STRUCT [] a = new STRUCT [0xA];
STRUCT s = new STRUCT();
a [0x0] = s;

to

STRUCT [] a = new STRUCT [0xA];

as each element of the array will be a struct initialized as if the defauly constructor had run - you can read my blog entry at [1] for the gory details of value type initialization

If this isn''t the situation, then yes you will get a copy, but any chance of posting code that is closer to the ral situation so we can advise more concretely

[1] http://staff.develop.com/richardb/we...c-b73640f24314

Regards

Richard Blewett - DevelopMentor
http://staff.develop.com/richardb/weblog

nntp://news.microsoft.com/microsoft.public.dotnet.languages.csharp/<BC****************@news4.e.nsc.no>

Hi.

I have an array of struct.
My question is, if i do:
STRUCT [] a = new STRUCT [0xA];
STRUCT s = new STRUCT();
a [0x0] = s;

since STRUCT is a value type, when assigning element 0 of the STRUCT array
as above,
is the STRUCT then copied to the array, as is the usual case of value types?
I guess it is.

This structure is kind of heavy.
It is as well a managed struct, therefore i cannot use pointers.

My option might be to, rather than assigning the elements,
to use the array directly with indexing(a lot of indexing then):

STRUCT [] a = new STRUCT [0xA];
a [0x0].PROPERTY = 0x0;
Please give me some thoughts about this.

Thank you!

--
Regards,
Dennis JD Myr?n
Oslo Kodebureau

---
Incoming mail is certified Virus Free.
Checked by AVG anti-virus system (http://www.grisoft.com).
Version: 6.0.771 / Virus Database: 518 - Release Date: 28/09/2004

[microsoft.public.dotnet.languages.csharp]

DennisMyrén< de **** @ oslokb.no>写道：

Dennis Myrén <de****@oslokb.no> wrote:

我有一个struct数组。
我的问题是，如果我这样做：
STRUCT [] a = new STRUCT [0xA];
STRUCT s = new STRUCT（）;
a [0x0] = s;

因为STRUCT是一个值类型，当如上所述分配STRUCT数组的元素0时，
然后STRUCT被复制到数组，就像通常的值类型一样？
我想是的。


是的。

这种结构很重。
它也是一个托管结构，因此我不能使用指针。


它真的需要是一个结构吗？

我的选择可能是，而不是分配元素，
使用数组直接使用索引（然后很多索引）：

STRUCT [] a =新STRUCT [0xA];
a [0x0] .PROPERTY = 0x0;


是的，你可以这样做 - 但如果你要设置任何重要的

数量的房产，你不会更好吗？还是有副本吗？

请给我一些想法。

I have an array of struct.
My question is, if i do:
STRUCT [] a = new STRUCT [0xA];
STRUCT s = new STRUCT();
a [0x0] = s;

since STRUCT is a value type, when assigning element 0 of the STRUCT array
as above,
is the STRUCT then copied to the array, as is the usual case of value types?
I guess it is.
Yes.
This structure is kind of heavy.
It is as well a managed struct, therefore i cannot use pointers.
Does it really need to be a structure then?
My option might be to, rather than assigning the elements,
to use the array directly with indexing(a lot of indexing then):

STRUCT [] a = new STRUCT [0xA];
a [0x0].PROPERTY = 0x0;
Yes, you could do that - but if you''re going to set any significant
number of properties, wouldn''t you be better off with a copy anyway?
Please give me some thoughts about this.

我建议你要做的第一件事是检查你是否*真的*需要它

是一个结构而不是一个类。我个人很少找到使用

来定义我自己的价值类型。


-

Jon Skeet - < sk ***@pobox.com>
http://www.pobox.com /〜双向飞碟

如果回复小组，请不要给我发邮件

I suggest the first thing to do is check whether you *really* need it
to be a struct rather than a class. I personally very rarely find a use
for defining my own value types.

--
Jon Skeet - <sk***@pobox.com>
http://www.pobox.com/~skeet
If replying to the group, please do not mail me too

谢谢你的回复，理查德。


我读了你的博客。好读！


-

问候，

DennisJDMyrén

Oslo Kodebureau

" Richard Blewett [DevelopMentor]" < RI ****** @ develop.com>在留言中写道

新闻：美国************** @ TK2MSFTNGP11.phx.gbl ...

Thank you for the response, Richard.

I read your blog. Good reading!

--
Regards,
Dennis JD Myrén
Oslo Kodebureau
"Richard Blewett [DevelopMentor]" <ri******@develop.com> wrote in message
news:uS**************@TK2MSFTNGP11.phx.gbl...

如果这是实际的情况，你可以改变

STRUCT [] a =新的STRUCT [0xA];
STRUCT s = new STRUCT（）;
a [0x0] = s;


STRUCT [] a = new STRUCT [0xA];

因为数组的每个元素都是一个初始化的结构，就像
defauly构造函数已运行 - 您可以在[1]上阅读我的博客条目，了解值类型初始化的详细信息

如果不是这种情况，那么是的，你会得到的一个副本，但任何机会发布更接近ral情况的代码，以便我们可以更具体地建议

[1]
http://staff.develop.com/richardb /we...c-b73640f24314

问候

Richard Blewett - DevelopMentor
http://staff.develop.com/richardb/weblog

NNTP：//news.microsoft.com/microsoft.public.dotnet.languages.csharp/< BC****************@news4.e.nsc.no> <无线电通信你好。我有一个结构数组。
我的问题是，如果我这样做：
STRUCT [] a = new STRUCT [0xA];
STRUCT s = new STRUCT（）;
a [0x0] = s;

因为STRUCT是一个值类型，当分配STRUCT数组的元素0时
如上所述，
是STRUCT然后复制到数组，就像通常的值类型一样？
我想是的。

这种结构是亲切的重的。
它也是一个托管结构，因此我不能使用指针。

我的选择可能是，而不是分配元素，
直接使用数组使用索引（然后进行大量索引）：

STRUCT [] a =新STRUCT [0xA];
a [0x0] .PROPERTY = 0x0;

请给我一些关于t的想法他的。

谢谢！

-
问候，
Dennis JD Myr？n
Oslo Kodebureau
由AVG反病毒系统检查（ http://www.grisoft.com）。
版本：6.0.771 /病毒库：518 - 发布日期：28/09/2004
[microsoft.public.dotnet.languages.csharp]

If this is the actual situation, you can change

STRUCT [] a = new STRUCT [0xA];
STRUCT s = new STRUCT();
a [0x0] = s;

to

STRUCT [] a = new STRUCT [0xA];

as each element of the array will be a struct initialized as if the
defauly constructor had run - you can read my blog entry at [1] for the
gory details of value type initialization

If this isn''t the situation, then yes you will get a copy, but any chance
of posting code that is closer to the ral situation so we can advise more
concretely

[1]
http://staff.develop.com/richardb/we...c-b73640f24314

Regards

Richard Blewett - DevelopMentor
http://staff.develop.com/richardb/weblog
nntp://news.microsoft.com/microsoft.public.dotnet.languages.csharp/<BC****************@news4.e.nsc.no>

Hi.

I have an array of struct.
My question is, if i do:
STRUCT [] a = new STRUCT [0xA];
STRUCT s = new STRUCT();
a [0x0] = s;

since STRUCT is a value type, when assigning element 0 of the STRUCT array
as above,
is the STRUCT then copied to the array, as is the usual case of value
types?
I guess it is.

This structure is kind of heavy.
It is as well a managed struct, therefore i cannot use pointers.

My option might be to, rather than assigning the elements,
to use the array directly with indexing(a lot of indexing then):

STRUCT [] a = new STRUCT [0xA];
a [0x0].PROPERTY = 0x0;
Please give me some thoughts about this.

Thank you!

--
Regards,
Dennis JD Myr?n
Oslo Kodebureau

---
Incoming mail is certified Virus Free.
Checked by AVG anti-virus system (http://www.grisoft.com).
Version: 6.0.771 / Virus Database: 518 - Release Date: 28/09/2004

[microsoft.public.dotnet.languages.csharp]

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