列表清单 [英] list of lists
问题描述
我有一个由列表组成的列表。
例如T = [[1,2,3]，[4,5]，[6]]
有没有办法解决内部中的特定组件？列表
直接？
例如现在我想获得第一个列表的第二个值。
不幸的是我必须首先将它保存到变量然后读取它。
a = T [0]
打印一份[1]
那种糟透了，因为我必须从很多内容中读取很多价值
列出！ :-(
有没有比我将它保存到帮助变量更快的方式？
谢谢大家!!
问候，汤姆
在文章< bk ********** @ news.uni-kl.de>，Tom写道：
我有一个由列表组成的列表。
例如T = [[1 ，2,3]，[4,5]，[6]]
有没有办法直接解决内部列表中的特定组件？
例如，现在我想获得第一个列表的第二个值。
不幸的是我必须先将它保存到变量然后再读它。
a = T [0]
打印一个[1]
这种糟糕，因为我必须从很多
列表中读取很多值！:-（
有没有比我保存它更快的方法帮助变量首先？
使用你的例子：
T = [[1,2,3] ，[4,5]，[6]]
打印T [0] [1]
Zach
2003年9月15日星期一15:59:56 +0200，Tom写道：
我有一个由列表组成的列表。例如。 T = [[1,2,3]，[4,5]，[6]]
有没有办法解决内部的特定组成部分。列表
直接？
例如现在我想获得第一个列表的第二个值。
不幸的是我必须先将它保存到变量然后再读取它。 a =
T [0]
打印[1]
尝试使用T [0] [1]。 T [0]完全等同于''a''，所以你可以使用
相同的操作，你不必首先分配给''a'。
Johannes
Tom写道：
我有一个由列表组成的列表。
例如T = [[1,2,3]，[4,5]，[6]]
有没有办法解决内部的特定组成部分。列表
直接？
例如现在我想获得第一个列表的第二个值。
不幸的是我必须先将它保存到变量然后再读它。
a = T [0]
打印一个[ 1]
那种糟透了，因为我必须阅读很多
列表中的很多值！ :-(
有没有比我将它保存到帮助变量更快的方式？
感谢大家!!
此致，汤姆
你的例子而不是你的问题规范表明你想要
所有。如果我猜对了：
def flatten（lol）：
$ l $ l for lst in lol：
for item in lst：
yield item
T = [[1,2,3]，[4,5]，[6]]
for flatten（T） ：
打印项目
指数似乎是一个垂死的品种:-)
彼得
Hi,
I have a list that consists of lists.
E.g. T=[[1, 2, 3], [4, 5], [6]]
Is there a way to address the a specific component in the "inner" list
directly?
E.g. right now I want to get the second value of the first list.
Unfortunately I have to save it to a variable first and then read it.
a = T[0]
print a[1]
That kind of sucks, becaus I have to read a lot of values from a lot of
lists! :-(
Is there a faster way than my saving it to a "help variable" first?
Thanks folks!!
Regards, Tom
In article <bk**********@news.uni-kl.de>, Tom wrote:Hi,
I have a list that consists of lists.
E.g. T=[[1, 2, 3], [4, 5], [6]]
Is there a way to address the a specific component in the "inner" list
directly?
E.g. right now I want to get the second value of the first list.
Unfortunately I have to save it to a variable first and then read it.
a = T[0]
print a[1]
That kind of sucks, becaus I have to read a lot of values from a lot of
lists! :-(
Is there a faster way than my saving it to a "help variable" first?
To use your example:
T=[[1, 2, 3], [4, 5], [6]]
print T[0][1]
Zach
On Mon, 15 Sep 2003 15:59:56 +0200, Tom wrote:
Hi,
I have a list that consists of lists. E.g. T=[[1, 2, 3], [4, 5], [6]]
Is there a way to address the a specific component in the "inner" list
directly?
E.g. right now I want to get the second value of the first list.
Unfortunately I have to save it to a variable first and then read it. a =
T[0]
print a[1]
Try using T[0][1]. T[0] is exactly equivalent to ''a'', so you can use
the same operations, you don''t have to assign to ''a'' first.
Johannes
Tom wrote:
Hi,
I have a list that consists of lists.
E.g. T=[[1, 2, 3], [4, 5], [6]]
Is there a way to address the a specific component in the "inner" list
directly?
E.g. right now I want to get the second value of the first list.
Unfortunately I have to save it to a variable first and then read it.
a = T[0]
print a[1]
That kind of sucks, becaus I have to read a lot of values from a lot of
lists! :-(
Is there a faster way than my saving it to a "help variable" first?
Thanks folks!!
Regards, Tom
Your example rather than your problem specification suggests that you want
them all. If I''m guessing right:
def flatten(lol):
for lst in lol:
for item in lst:
yield item
T=[[1, 2, 3], [4, 5], [6]]
for item in flatten(T):
print item
Indices seem to be a dying breed :-)
Peter
这篇关于列表清单的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
