将字符串转换为列表 [英] convert string to list
问题描述
我是Python的真正初学者，我想知道是否有办法将
转换成一个字符串（其中包含一个列表） ）到真实的清单。
我需要这个，因为我想从bash中给出一个列表作为我的
Python脚本的参数：
＃！/ usr / bin / python
import sys
argument1 = sys.argv [1]
thelist = ???（argument1）
然后像这样从bash调用脚本
thescript.py [" A"，" ; B"，" C"]
谢谢你，
Jochen
Hi,
I am a real beginner in Python and I was wondering if there is a way to
convert a string (which contains a list) to a "real" list.
I need this since I would like to give a list as an argument to my
Python script from the bash:
#!/usr/bin/python
import sys
argument1 = sys.argv[1]
thelist = ???(argument1)
and then call the script from the bash like this
thescript.py ["A","B","C"]
Thanks you,
Jochen
推荐答案
Jochen Hub写道：
Jochen Hub wrote:
我需要这个，因为我想从bash中列出一个列表作为我的
Python脚本的参数：
＃！/ usr / bin / python
import sys
argument1 = sys.argv [1]
thelist = ???（argument1）
然后像这样从bash调用脚本
thescript.py [" A"，" B"，" C"]
I need this since I would like to give a list as an argument to my
Python script from the bash:
#!/usr/bin/python
import sys
argument1 = sys.argv[1]
thelist = ???(argument1)
and then call the script from the bash like this
thescript.py ["A","B","C"]
为什么不给你独立的args
thescript.pyA " B" C
并执行此操作：
thelist = sys.argv [1：]
-
问候，
Diez B. Roggisch
Why don''t you give the args standalone
thescript.py "A" "B" "C"
and do this:
thelist = sys.argv[1:]
--
Regards,
Diez B. Roggisch
2004年3月-10-13在14:03 +0200，Jochen Hub写道：
On Wed, 2004-10-13 at 14:03 +0200, Jochen Hub wrote:
我是Python的真正初学者，我想知道是否有办法
将字符串（包含列表）转换为真实字符串。清单。
我需要这个，因为我想从bash中给出一个列表作为我的
Python脚本的参数：
＃！/ usr / bin / python
import sys
argument1 = sys.argv [1]
thelist = ???（argument1）
然后从bash这样调用脚本就像这样
thescript.py [" A，B，C]
Hi,
I am a real beginner in Python and I was wondering if there is a way to
convert a string (which contains a list) to a "real" list.
I need this since I would like to give a list as an argument to my
Python script from the bash:
#!/usr/bin/python
import sys
argument1 = sys.argv[1]
thelist = ???(argument1)
and then call the script from the bash like this
thescript.py ["A","B","C"]
您可以使用eval。更好的是，你可以简单地将你的列表作为bash的一系列参数传递给你：
＃！/ bin / bash
myscript.py ABC
＃！/ usr / bin / python
import sys
thelist = sys.argv [1：]
问候，
悬崖
-
Cliff Wells< cl *** *********@comcast.net>
You can use eval for this. Better, you could simply pass your list as a
series of arguments from bash:
#!/bin/bash
myscript.py A B C
#!/usr/bin/python
import sys
thelist = sys.argv[1:]
Regards,
Cliff
--
Cliff Wells <cl************@comcast.net>
>>
thescript.py [" A"，" B"，" C"]
您可以使用eval。更好的是，您可以简单地将您的列表作为一系列参数从bash传递出来：
thescript.py ["A","B","C"]
You can use eval for this. Better, you could simply pass your list as a
series of arguments from bash:
我尝试使用eval ...只需使用
thelist = eval（argv [1]）
它不起作用:-(，我收到错误消息
文件" ./ findCenter.py"，第64行，在？
print eval（sys.argv [1]）
文件"< ; string>"，第0行，在？
NameError：name''A''未定义
＃！/ bin / bash
myscript。 py ABC
I tried with eval...simply using
thelist=eval(argv[1])
it didn''t work :-(, I got the error message
File "./findCenter.py", line 64, in ?
print eval(sys.argv[1])
File "<string>", line 0, in ?
NameError: name ''A'' is not defined
#!/bin/bash
myscript.py A B C
问题是我想将一个或两个列表传递给脚本，所以它b / b
应该可以区分
thescript [A，B] [C，D，E]
thescript [" A，B，C[D，E]
thescript [A，B，C，D ;，E"]
The problem is that I want to pass one or two lists to the script, so it
should be able to distinguish between
thescript ["A","B"] ["C","D",E"]
thescript ["A","B","C"] ["D",E"]
thescript ["A","B","C","D",E"]
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