Android的复选框 - 删除previously setOnCheckedChangeListener [英] Android CheckBox - Removing a previously setOnCheckedChangeListener

问题描述

我有使用我自定义一个CursorAdapter的显示ListView控件的应用程序。在我的自定义CursorAdapter.bindView，我有我设置的检查值（根据光标列）一个CheckBox对象，并设置一个clickListener。这是我的code：

I have an application that displays a ListView using a CursorAdapter that I have customized. Within my custom CursorAdapter.bindView, I have a CheckBox object that I set the checked value (based on a column on the cursor) and set a clickListener. Here is my code:

    CheckBox mCheckBox = (CheckBox) view.findViewById(R.id.list_done);
    mCheckBox.setChecked(isDone);
    mCheckBox.setOnCheckedChangeListener(new OnCheckedChangeListener()
    {
        public void onCheckedChanged(CompoundButton buttonView, boolean isChecked)
        {
                AW.getDB().updateTask(c.getInt(c.getColumnIndex(ToDoDBAdapter.KEY_ID)), isChecked);
                TD.displayTasks();
        }
    });

唯一的问题是，当Android的回收我的意见，onCheckedChangeListener仍然活跃，从而调用setChecked（）使听者内的code运行。我想知道如何前右侧的code我已经包括运行invalidata的onCheckedChangedListener。

The only problem is that when Android recycles my views, the onCheckedChangeListener is still active, and thus the call to setChecked() causes that code within the listener to run. I would like to know how to invalidata the onCheckedChangedListener right before the code I have included runs.

推荐答案

您可以这样做：

// c is the Cursor you are getting
CheckBox mCheckBox = (CheckBox) view.findViewById(R.id.list_done);
mCheckBox.setTag(new Integer(c.getPosition());
mCheckBox.setChecked(isDone);
mCheckBox.setOnCheckedChangeListener(new OnCheckedChangeListener()
{
    public void onCheckedChanged(CompoundButton buttonView, boolean isChecked)
    {
        Integer posInt = (Integer)buttonView.getTag();

        int pos = posInt.intValue();
        c.moveToPosition(pos);
            AW.getDB().updateTask(c.getInt(c.getColumnIndex(ToDoDBAdapter.KEY_ID)), isChecked);
            TD.displayTasks();
    }
});

有很多的优化可以做，以高于code的含量。我刚刚说明的基本逻辑。

There are lots of optimizations you can do to above code. I just illustrated the basic logic.

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