什么印刷？ [英] What is printed?
问题描述
什么打印到屏幕上？
#include< stdio.h>
int main（void）
{
printf（" Hello！\ n"）;
fclose（stdout）;
printf（" ;再见！\ n"）;
返回0;
}
What is printed to the screen?
#include <stdio.h>
int main(void)
{
printf("Hello!\n");
fclose(stdout);
printf("Goodbye!\n");
return 0;
}
推荐答案
DJ写道：
什么打印到屏幕上？
< stdio.h>
int main（void）
{
printf（" Hello！\ n"）;
fclose（stdout）;
printf（" Goodbye！\ n"）;
返回0;
}
What is printed to the screen?
#include <stdio.h>
int main(void)
{
printf("Hello!\n");
fclose(stdout);
printf("Goodbye!\n");
return 0;
}
你好！
然而，在哪里再见！ "去？这是默认行为吗？
-
一个人的自由停止在其他人开始的地方
Giannis Papadopoulos
http://dop.users.uth.gr/
塞萨利大学
电脑&通信工程部门
"Hello!"
However, where "Goodbye!" goes? Is this default behaviour?
--
one''s freedom stops where other''s begin
Giannis Papadopoulos
http://dop.users.uth.gr/
University of Thessaly
Computer & Communications Engineering dept.
" DJ" <安******** @ comcast.net>在消息中写道
新闻：SM ******************** @ comcast.com ...
"DJ" <An********@comcast.net> wrote in message
news:SM********************@comcast.com...
什么打印到屏幕上？
#include< stdio.h>
int main（无效）
{/> printf（" Hello！ \ n"）;
fclose（stdout）;
What is printed to the screen?
#include <stdio.h>
int main(void)
{
printf("Hello!\n");
fclose(stdout);
我想嗨。无论如何，这是一个变态代码。
Alex
I suppose just hi. What a pervert code anyway.
Alex
" Giannis Papadopoulos" < IP ****** @ inf.uth.gr>在消息中写道
news：dc ********** @ volcano1.grnet.gr ...
....
"Giannis Papadopoulos" <ip******@inf.uth.gr> wrote in message
news:dc**********@volcano1.grnet.gr...
....
fclose（stdout）;
printf（" Goodbye！\ n"）;
fclose(stdout);
printf("Goodbye!\n");
....但是，在哪里再见！去？这是默认行为吗？
.... However, where "Goodbye!" goes? Is this default behaviour?
我希望默认为undefined。并且应用程序可能会在两个函数调用中崩溃。
Alex
I''d expect default to be undefined. And the app may crash at either of those
two function calls.
Alex
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