问题阅读Xml文件 [英] Problem Reading Xml file

问题描述

我正在以下列方式编写XML文件。现在我需要再次阅读

该文件以检索姓名和年龄等数据。


有人可以帮我解决。

提前致谢


/ ********************************* /

static void writeXML（）

{

XmlTextWriter writer = new XmlTextWriter（@" c：\ hede.xml"，

Encoding.UTF8）;


writer.Formatting = Formatting.Indented;

writer.WriteStartDocument（true）; // true = standalone

writer.WriteStartElement（" Humans"）;


writer.WriteStartElement（" Person"）;

writer.WriteElementString（" Name"，" abc"）;

writer.WriteElementString（" Age"，" 17"）;

writer .WriteEndElement（）;


writer.WriteStartElement（" Person"）;

writer.WriteElementString（" Name"，" xyz"）;

writer.WriteElementString（" Age"，" 71"）;

writer.WriteEndElement（）;


writer .WriteEndElement（）;

writer.WriteEndDocument（）;

writer.Close（）;

}

解决方案

这是一个简单的例子：


您可以创建一个新的XMLTextReader实例，传递您创建的文件，然后使用ReadElementString读取姓名和年龄的方法如下：

XmlTextReader reader = new Xml TextReader（@" c：\ hede.xml"）;


while（reader.Read（））

{

if（reader.Name.Equals（" Name"））

{

Console.WriteLine（" Name：" + reader.ReadElementString（" Name"））;

Console.WriteLine（" Age：" + reader.ReadElementString（" Age"））;

}

}


- Mohan

我在写一个XML文件以下方式。现在我需要再次阅读该文件以检索姓名和年龄等数据。

有人可以帮助我。
先谢谢

/ ********************************* /
static void writeXML（）
{
XmlTextWriter writer = new XmlTextWriter（@" c：\\\ myde.xml"，
Encoding.UTF8）;

writer.Formatting = Formatting.Indented;
writer.WriteStartDocument（真）; // true = standalone
writer.WriteStartElement（" Humans"）;

writer.WriteStartElement（" Person"）;
writer.WriteElementString（" Name"， " abc"）;
writer.WriteElementString（" Age"，" 17"）;
writer.WriteEndElement（）;

writer.WriteStartElement（" Person" ;）;
writer.WriteElementString（" Name"，" xyz"）;
writer.WriteElementString（" Age"，" 71"）;
writer.WriteEndElement（） ;

writer.WriteEndElement（）;
writer.WriteEndDocument（）;
writer.Close（）;
}

用户从AEWNET提交（ http://www.aewnet.com/）

这是一个简单的例子：


您可以创建一个新的XMLTextReader实例，传递您创建的文件，通过使用ReadElementString方法进行读取g名称和年龄如下：

XmlTextReader reader = new XmlTextReader（@" c：\\\ myde.xml"）;


while（reader.Read（））

{

if（reader.Name.Equals（" Name"））

{

Console.WriteLine（" Name：" + reader.ReadElementString（" Name"））;

Console.WriteLine（" Age：" + reader.ReadElementString（" Age"））;

}

}


- Mohan

我在写一个XML文件以下方式。现在我需要再次阅读该文件以检索姓名和年龄等数据。

有人可以帮助我。
先谢谢

/ ********************************* /
static void writeXML（）
{
XmlTextWriter writer = new XmlTextWriter（@" c：\\\ myde.xml"，
Encoding.UTF8）;

writer.Formatting = Formatting.Indented;
writer.WriteStartDocument（真）; // true = standalone
writer.WriteStartElement（" Humans"）;

writer.WriteStartElement（" Person"）;
writer.WriteElementString（" Name"， " abc"）;
writer.WriteElementString（" Age"，" 17"）;
writer.WriteEndElement（）;

writer.WriteStartElement（" Person" ;）;
writer.WriteElementString（" Name"，" xyz"）;
writer.WriteElementString（" Age"，" 71"）;
writer.WriteEndElement（） ;

writer.WriteEndElement（）;
writer.WriteEndDocument（）;
writer.Close（）;

AEWNET提交的用户（ http://www.aewnet.com/ ）

你好Xarky


我只想指出XML DOM模型。这个库真的很容易以对象方式编写xmlfiles。甚至更容易阅读...所以你不需要自己创建xml解析器。


这就是你如何制作xml关于XML DOM：


================================== ============

XmlDocument Doc = new XmlDocument（）;


XmlNode humanElement = Doc.CreateElement（" Humans" ;）;


XmlNode personeElement1 = Doc.CreateElement（" Person"）;

XmlAttribute personElement1Name = Doc.CreateAttribute（" Name"）;

personElement1Name.Value =" abc";

XmlAttribute personElement1Age = Doc.CreateAttribute（" Age"）;

personElement1Age.Value =" ; 17"


personElement1.Attributes.Append（personElement1Name）;

personElement1.Attributes.Append（personElement1Age）;

humanElement.AppendChild（personElement1）;


XmlNode personeElement2 = Doc.CreateElement（" Person"）;

X mlAttribute personElement2Name = Doc.CreateAttribute（" Name"）;

personElement2Name.Value =" xyz";

XmlAttribute personElement2Age = Doc.CreateAttribute（" Age"） ;

personElement2Age.Value =" 71";


personElement2.Attributes.Append（personElement2Name）;

personElement2.Attributes .Append（personElement2Age）;

humanElement.AppendChild（personElement2）;


Doc.AppendChild（humanElement）;


Doc.Save（" test.xml" ）;


==================================== ============== ==

这就是你读它的方式：


==== ============================================== ==

XmlDocument Doc = new XmlDocument（）;

Doc.LoadXml（" test.xml"）;


string text ="";

foreach（Doc.Elements.ChildNodes中的XmlNode节点）

{

text ="" ;

if（node.Name ==" Person"）

{

if（node.Attributes [" Name"]]！ = null）

{

text = node.Attributes [" Name"]。Value）+" \r\\\
";

}

if（node.Attributes [" Name"]！= null）

{

text + = node.Attributes [" Name"]。Value）;

}


MessageBox.Show（text）;

}

}


================================ ===========


我希望我又不是太混乱，但我特地发现这是
$ B $的真快，方式B，创建XML数据库，并与小麻烦阅读。每个元素都被视为一个节点....所以你可以创建一个XmlNode对象来引用一个

特定元素，无论树有多深。 />

希望有所帮助！

" Xarky" <是********* @ yahoo.com>在消息中写道

news：bc ************************ @ posting.google.com ...

我正在以下列方式编写XML文件。现在我需要再次阅读该文件以检索姓名和年龄等数据。

有人可以帮助我。
先谢谢

/ ********************************* /
static void writeXML（）
{
XmlTextWriter writer = new XmlTextWriter（@" c：\\\ myde.xml"，
Encoding.UTF8）;

writer.Formatting = Formatting.Indented;
writer.WriteStartDocument（真）; // true = standalone
writer.WriteStartElement（" Humans"）;

writer.WriteStartElement（" Person"）;
writer.WriteElementString（" Name"， " abc"）;
writer.WriteElementString（" Age"，" 17"）;
writer.WriteEndElement（）;

writer.WriteStartElement（" Person" ;）;
writer.WriteElementString（" Name"，" xyz"）;
writer.WriteElementString（" Age"，" 71"）;
writer.WriteEndElement（） ;

writer.WriteEndElement（）;
writer.WriteEndDocument（）;
writer.Close（）;
}

Hi,
I am writing an XML file in the following way. Now I need to read
again that file to retrieve data such as Name and Age.

Can someone help me out.
Thanks in Advance

/*********************************/
static void writeXML()
{
XmlTextWriter writer = new XmlTextWriter(@"c:\hede.xml",
Encoding.UTF8);

writer.Formatting = Formatting.Indented;
writer.WriteStartDocument(true); // true = standalone
writer.WriteStartElement("Humans");

writer.WriteStartElement("Person");
writer.WriteElementString("Name", "abc");
writer.WriteElementString("Age", "17");
writer.WriteEndElement();

writer.WriteStartElement("Person");
writer.WriteElementString("Name", "xyz");
writer.WriteElementString("Age", "71");
writer.WriteEndElement();

writer.WriteEndElement();
writer.WriteEndDocument();
writer.Close();
}

解决方案

Here''s a simple example :

You may create a new XMLTextReader instance passing the file you created followed by use of the ReadElementString method for reading name and age like so :

XmlTextReader reader = new XmlTextReader(@"c:\hede.xml");

while (reader.Read())
{
if(reader.Name.Equals("Name"))
{
Console.WriteLine("Name : " + reader.ReadElementString("Name"));
Console.WriteLine("Age : " + reader.ReadElementString("Age"));
}
}

- Mohan

Hi,
I am writing an XML file in the following way. Now I need to read
again that file to retrieve data such as Name and Age.

Can someone help me out.
Thanks in Advance

/*********************************/
static void writeXML()
{
XmlTextWriter writer = new XmlTextWriter(@"c:\hede.xml",
Encoding.UTF8);

writer.Formatting = Formatting.Indented;
writer.WriteStartDocument(true); // true = standalone
writer.WriteStartElement("Humans");

writer.WriteStartElement("Person");
writer.WriteElementString("Name", "abc");
writer.WriteElementString("Age", "17");
writer.WriteEndElement();

writer.WriteStartElement("Person");
writer.WriteElementString("Name", "xyz");
writer.WriteElementString("Age", "71");
writer.WriteEndElement();

writer.WriteEndElement();
writer.WriteEndDocument();
writer.Close();
}

User submitted from AEWNET (http://www.aewnet.com/)

Here''s a simple example :

You may create a new XMLTextReader instance passing the file you created followed by use of the ReadElementString method for reading name and age like so :

XmlTextReader reader = new XmlTextReader(@"c:\hede.xml");

while (reader.Read())
{
if(reader.Name.Equals("Name"))
{
Console.WriteLine("Name : " + reader.ReadElementString("Name"));
Console.WriteLine("Age : " + reader.ReadElementString("Age"));
}
}

- Mohan

Hi,
I am writing an XML file in the following way. Now I need to read
again that file to retrieve data such as Name and Age.

Can someone help me out.
Thanks in Advance

/*********************************/
static void writeXML()
{
XmlTextWriter writer = new XmlTextWriter(@"c:\hede.xml",
Encoding.UTF8);

writer.Formatting = Formatting.Indented;
writer.WriteStartDocument(true); // true = standalone
writer.WriteStartElement("Humans");

writer.WriteStartElement("Person");
writer.WriteElementString("Name", "abc");
writer.WriteElementString("Age", "17");
writer.WriteEndElement();

writer.WriteStartElement("Person");
writer.WriteElementString("Name", "xyz");
writer.WriteElementString("Age", "71");
writer.WriteEndElement();

writer.WriteEndElement();
writer.WriteEndDocument();
writer.Close();

User submitted from AEWNET (http://www.aewnet.com/)

Hi Xarky

I just wanted to point out the XML DOM model. This library makes it really
easy to write xmlfiles in an object way. and even easier to read... so u
don''t have to make your own xml parser.

This is how you would make the xml on XML DOM:

==============================================
XmlDocument Doc = new XmlDocument();

XmlNode humanElement = Doc.CreateElement( "Humans");

XmlNode personeElement1 = Doc.CreateElement("Person");
XmlAttribute personElement1Name = Doc.CreateAttribute("Name");
personElement1Name.Value = "abc";
XmlAttribute personElement1Age = Doc.CreateAttribute("Age");
personElement1Age.Value = "17";

personElement1.Attributes.Append( personElement1Name );
personElement1.Attributes.Append( personElement1Age );
humanElement.AppendChild( personElement1 );

XmlNode personeElement2 = Doc.CreateElement("Person");
XmlAttribute personElement2Name = Doc.CreateAttribute("Name");
personElement2Name.Value = "xyz";
XmlAttribute personElement2Age = Doc.CreateAttribute("Age");
personElement2Age.Value = "71";

personElement2.Attributes.Append( personElement2Name );
personElement2.Attributes.Append( personElement2Age );
humanElement.AppendChild( personElement2 );

Doc.AppendChild( humanElement );

Doc.Save( "test.xml" );

================================================== ==
And this is how you would read it back:

================================================== ==
XmlDocument Doc = new XmlDocument();

Doc.LoadXml( "test.xml" );

string text = "";
foreach( XmlNode node in Doc.Elements.ChildNodes )
{
text="";
if ( node.Name == "Person" )
{
if ( node.Attributes["Name"] != null )
{
text = node.Attributes["Name"].Value ) + "\r\n";
}
if ( node.Attributes["Name"] != null )
{
text += node.Attributes["Name"].Value );
}

MessageBox.Show( text );
}
}

===========================================

I hope I''m not too confusing, but I''ve found this to be a really fast way of
creating xml databases and reading them with little hassle. Each Element is
treated as a node.... so you can create an XmlNode object to reference an
specific element no matter how deep in the tree is.

Hope that help!
"Xarky" <be*********@yahoo.com> wrote in message
news:bc************************@posting.google.com ...

Hi,
I am writing an XML file in the following way. Now I need to read
again that file to retrieve data such as Name and Age.

Can someone help me out.
Thanks in Advance

/*********************************/
static void writeXML()
{
XmlTextWriter writer = new XmlTextWriter(@"c:\hede.xml",
Encoding.UTF8);

writer.Formatting = Formatting.Indented;
writer.WriteStartDocument(true); // true = standalone
writer.WriteStartElement("Humans");

writer.WriteStartElement("Person");
writer.WriteElementString("Name", "abc");
writer.WriteElementString("Age", "17");
writer.WriteEndElement();

writer.WriteStartElement("Person");
writer.WriteElementString("Name", "xyz");
writer.WriteElementString("Age", "71");
writer.WriteEndElement();

writer.WriteEndElement();
writer.WriteEndDocument();
writer.Close();
}

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