使用数组 [英] Working with arrays
问题描述
有没有更好的方法来填充数组然后这个
a是一个自动生成的值，总是不同的。
它意味着循环直到数组充满了值，这会有效吗？
int i = 0;
while（array [array.Length-1] == null）
{
array [i] = a;
i ++;
}
is there a better way to fill an array then this
a is a auto generated value, always different.
its meant to loop through until the array is full of values, will this work?
int i=0;
while(array[array.Length-1] == null)
{
array[i] = a;
i++;
}
推荐答案
Thaynann< Th ****** @ discussion.microsoft.com>写道：
Thaynann <Th******@discussions.microsoft.com> wrote:
有没有更好的方法来填充数组然后这个
a是一个自动生成的值，总是不同的。
它意味着循环直到数组充满了值，这会有效吗？
int i = 0;
while（array [array.Length-1] == null）
array [i] = a;
i ++;
}
is there a better way to fill an array then this
a is a auto generated value, always different.
its meant to loop through until the array is full of values, will this work?
int i=0;
while(array[array.Length-1] == null)
{
array[i] = a;
i++;
}
嗯，这会更好：
for（int i = 0; i< array.Length; i ++）
{
array [i] = a;
}
我不认为框架中有任何东西可以填充数组
虽然。
-
Jon Skeet - < sk *** @ pobox.com>
http://www.pobox.com/~skeet
如果回复该群组，请不要给我发邮件
Well, this would be nicer:
for (int i=0; i < array.Length; i++)
{
array[i] = a;
}
I don''t think there''s anything in the framework to fill an array
though.
--
Jon Skeet - <sk***@pobox.com>
http://www.pobox.com/~skeet
If replying to the group, please do not mail me too
Thaynann，
除了John有时甚至更好一点，
\\\
foreach（arrayType a）in array
{
a = x;
}
///
Cor
Thaynann,
In addition to John sometimes called even a little bit better,
\\\
foreach (arrayType a) in array
{
a = x;
}
///
Cor
不是这样，这段代码什么都不做，你只是一遍又一遍地分配一个本地的
变量（a），数组保持不变。
-
Francisco Padron
www.chartfx.com
Not really, this code does nothing, you are simply assigning a local
variable (a) over and over, the array remains unchanged.
--
Francisco Padron
www.chartfx.com
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