Noob问题这里...... c ++ [英] Noob Question Here...c++
问题描述
大家好，
我有一个真正的n00b问题。我刚刚开始我的c ++课程大约2
周前，我们有一个任务。我们必须制作一个程序，使
改变，然后显示
改变客户回来的多少美元/季度/硬币/镍/便士....
我可以发誓我的数学是正确的（我在我的计算器上查了一下
10次），我只是不知道它为什么不能正常工作。似乎
美元/季度/硬币似乎在起作用，但是镍和硬币
有点搞砸...当我欠下20.00美元的欠款和22.72美元付费..我
当然得到2.72美元的变化...然后它显示2美元2季度2
角钱0镍1便士。
看看我在C ++中的代码：
//程序目的：帮助学生从销售中产生变化
#include< iostream>
使用命名空间std;
int main（）
{
float owe = 0.0;
浮动支付= 0.0;
浮动变化= 0.0;
int dollar = 0;
int quarter = 0;
int dime = 0;
int nickle = 0;
int penny = 0;
//输入输入项目
cout<< 输入欠款金额： ;
cin>>欠;
cout<< 输入支付金额： ;
cin>>支付;
//计算变更欠款总额
更改=已付款 - 欠款;
美元=变更/ 1;
quarter =（更改 - 美元）/ .25;
dime =（更改 - 美元 - （季度* .25））/。1;
nickle =（更改 - 美元 - （季度* .25） - （角钱* .1））/ .05;
penny =（更改 - 美元 - （季度* .25） - （ dime * .1） - （nickle * .05））
/ .01;
//显示输出项目
cout<< 改变： <<改变<< endl;
cout<< dollar（s）： <<美元<< endl;
cout<< quarter（s）： <<四分之一<< endl;
cout<< dime： <<一角硬币<< endl;
cout<< 镍（s）： <<尼克<< endl;
cout<< 便士： <<便士<<结束;
返回0;
}
//结束主要功能
感谢您的帮助!!
-EB
Hello all,
I have a real n00b question. I just started my c++ class about 2
weeks ago and we have an assignment. We have to make a program that makes
change, and then shows how many dollars/quarters/dimes/nickles/pennies in
change the customer gets back....
I could swear my math is correct(I checked it on my calculator over
10 times), I just have no idea why it is not working correctly. It seems
the dollars/quarters/dimes seems to be working but the nickles and pennies
are kinda messed up...When I put an amount of $20.00 owed and $22.72 paid..I
of course get $2.72 in change...and then it displays 2 dollar 2 quarter 2
dime 0 nickle 1 penny.
Take a look at my code in C++:
//Program Purpose : To help students produce change from a sale
#include <iostream>
using namespace std;
int main()
{
float owe = 0.0;
float paid = 0.0;
float change = 0.0;
int dollar = 0 ;
int quarter = 0 ;
int dime = 0 ;
int nickle = 0;
int penny = 0;
//enter input items
cout << "Enter Amount Owed: " ;
cin >> owe;
cout << "Enter Amount Paid: " ;
cin >> paid;
//calculate total owed in change
change = paid - owe;
dollar = change / 1;
quarter = (change - dollar) / .25;
dime = (change - dollar - (quarter * .25)) / .1;
nickle = (change - dollar - (quarter * .25) - (dime * .1)) / .05;
penny = (change - dollar - (quarter * .25) - (dime * .1) - (nickle * .05))
/ .01;
//display output items
cout << "change: " << change << endl;
cout << "dollar(s): " << dollar << endl;
cout << "quarter(s): " << quarter << endl;
cout << "dime(s): " << dime << endl;
cout << "nickel(s): " << nickle << endl;
cout << "penny(s): " << penny << endl;
return 0;
}
//end main function
Thanks for the help!!
-EB
推荐答案
20.00欠款和
22.72 pay..I
当然得到
22.72 paid..I
of course get
2.72 in change ...然后它显示2美元2季度2 br $>
dime 0 nickle 1 penny。
看看我在C ++中的代码：
//程序目的：帮助学生从销售中产生变化
#include< iostream>
使用命名空间std;
int main（）
{
浮动欠款= 0.0;
浮动支付= 0.0;
浮动变化= 0.0;
int dollar = 0;
int quarter = 0;
int dime = 0;
int nickle = 0;
int penny = 0;
//输入输入项目
cout<< 输入欠款金额： ;
cin>>欠;
cout<< 输入支付金额： ;
cin>>支付;
//计算变更欠款总额
更改=已付款 - 欠款;
美元=变更/ 1;
quarter =（更改 - 美元）/ .25;
dime =（更改 - 美元 - （季度* .25））/。1;
nickle =（更改 - 美元 - （季度* .25） - （角钱* .1））/ .05;
penny =（更改 - 美元 - （季度* .25） - （ dime * .1） - （nickle * .05））
/ .01;
//显示输出项目
cout<< 改变： <<改变<< endl;
cout<< dollar（s）： <<美元<< endl;
cout<< quarter（s）： <<四分之一<< endl;
cout<< dime： <<一角硬币<< endl;
cout<< 镍（s）： <<尼克<< endl;
cout<< 便士： <<便士<<结束;
返回0;
}
//结束主要功能
感谢您的帮助!!
-EB
2.72 in change...and then it displays 2 dollar 2 quarter 2
dime 0 nickle 1 penny.
Take a look at my code in C++:
//Program Purpose : To help students produce change from a sale
#include <iostream>
using namespace std;
int main()
{
float owe = 0.0;
float paid = 0.0;
float change = 0.0;
int dollar = 0 ;
int quarter = 0 ;
int dime = 0 ;
int nickle = 0;
int penny = 0;
//enter input items
cout << "Enter Amount Owed: " ;
cin >> owe;
cout << "Enter Amount Paid: " ;
cin >> paid;
//calculate total owed in change
change = paid - owe;
dollar = change / 1;
quarter = (change - dollar) / .25;
dime = (change - dollar - (quarter * .25)) / .1;
nickle = (change - dollar - (quarter * .25) - (dime * .1)) / .05;
penny = (change - dollar - (quarter * .25) - (dime * .1) - (nickle * .05))
/ .01;
//display output items
cout << "change: " << change << endl;
cout << "dollar(s): " << dollar << endl;
cout << "quarter(s): " << quarter << endl;
cout << "dime(s): " << dime << endl;
cout << "nickel(s): " << nickle << endl;
cout << "penny(s): " << penny << endl;
return 0;
}
//end main function
Thanks for the help!!
-EB
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