如何重构我的代码关注亚马逊的s3客户端 [英] How to refactor my code regardin s3 client of amazon

问题描述

 public boolean createFolder（String path）{
 try {
 //为您的文件夹创建元数据并将content-length设置为0 
 ObjectMetadata metadata = new ObjectMetadata（）; 
 metadata.setContentLength（0）; 
 //创建空内容
 InputStream emptyContent = new ByteArrayInputStream（new byte [0]）; 
 //创建一个PutObjectRequest，传递文件夹名称后缀为/ 
 PutObjectRequest putObjectRequest = new PutObjectRequest（this.bucketName，path + SUFFIX，emptyContent，
 metadata）; 
 //向S3发送请求以创建文件夹
 boolean doesObjectExist = this.s3client.doesObjectExist（bucketName，path）; 
 if（！doesObjectExist）{
 this.s3client.putObject（putObjectRequest）; 
} 
返回true; 
} catch（例外e）{
返回false; 
} 
} 
 

我尝试了什么： <在bs客户端重构代码以减少复杂性

解决方案

<$


代码重构p $ p> public boolean createFolder（String path）{
return true;
}

public boolean createFolder(String path) {
    try {
        // create meta-data for your folder and set content-length to 0
        ObjectMetadata metadata = new ObjectMetadata();
        metadata.setContentLength(0);
        // create empty content
        InputStream emptyContent = new ByteArrayInputStream(new byte[0]);
        // create a PutObjectRequest passing the folder name suffixed by /
        PutObjectRequest putObjectRequest = new PutObjectRequest(this.bucketName, path + SUFFIX, emptyContent,
                metadata);
        // send request to S3 to create folder
        boolean doesObjectExist = this.s3client.doesObjectExist(bucketName, path);
        if (!doesObjectExist) {
            this.s3client.putObject(putObjectRequest);
        }
        return true;
    } catch (Exception e) {
        return false;
    }
}

What I have tried:

code refactoring in the aws s3 client to refactor the code for to reduce the complexity

解决方案

public boolean createFolder(String path) {
    return true;
}

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