我需要帮助为kronecker产品创建cuda代码。有人可以帮忙吗？ [英] I need help in creating a cuda code for kronecker product. Can anyone help?
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问题描述
任何人都可以将此c代码转换为cuda ??
can anyone convert this c code into cuda??
// C code to find the Kronecker Product of two
// matrices and stores it as matrix C
#include <stdio.h>
// rowa and cola are no of rows and columns
// of matrix A
// rowb and colb are no of rows and columns
// of matrix B
const int cola = 2, rowa = 3, colb = 3, rowb = 2;
// Function to computes the Kronecker Product
// of two matrices
void Kroneckerproduct(int A[][cola], int B[][colb])
{
int C[rowa * rowb][cola * colb];
// i loops till rowa
for (int i = 0; i < rowa; i++) {
// k loops till rowb
for (int k = 0; k < rowb; k++) {
// j loops till cola
for (int j = 0; j < cola; j++) {
// l loops till colb
for (int l = 0; l < colb; l++) {
// Each element of matrix A is
// multiplied by whole Matrix B
// resp and stored as Matrix C
C[i + l + 1][j + k + 1] = A[i][j] * B[k][l];
printf("%d\t", C[i + l + 1][j + k + 1]);
}
}
printf("\n");
}
}
}
// Driver Code
int main()
{
int A[3][2] = { { 1, 2 }, { 3, 4 }, { 1, 0 } },
B[2][3] = { { 0, 5, 2 }, { 6, 7, 3 } };
Kroneckerproduct(A, B);
return 0;
}
我的尝试：
我已经试了好几天但总是有一些错误和警告。一些错误MSB3721总是在那里
What I have tried:
I have tried for days but always there are some errors and warnings. some error MSB3721 is always there
推荐答案
我用Visual Studio 2017 Ultimate测试了你的代码，没有任何警告或问题。
1.创建控制台应用程序
2.将以下代码放在主.cpp文件中
I tested your code with Visual Studio 2017 Ultimate, and there are no warnings or issues.
1. Create a Console application
2. Place the following code in your main .cpp file
// Test1.cpp : This file contains the 'main' function. Program execution begins and ends there.
//
#include "pch.h"
#include <iostream>
// C code to find the Kronecker Product of two
// matrices and stores it as matrix C
#include <stdio.h>
// rowa and cola are no of rows and columns
// of matrix A
// rowb and colb are no of rows and columns
// of matrix B
const int cola = 2, rowa = 3, colb = 3, rowb = 2;
// Function to computes the Kronecker Product
// of two matrices
void Kroneckerproduct(int A[][cola], int B[][colb])
{
int C[rowa * rowb][cola * colb];
// i loops till rowa
for (int i = 0; i < rowa; i++) {
// k loops till rowb
for (int k = 0; k < rowb; k++) {
// j loops till cola
for (int j = 0; j < cola; j++) {
// l loops till colb
for (int l = 0; l < colb; l++) {
// Each element of matrix A is
// multiplied by whole Matrix B
// resp and stored as Matrix C
C[i + l + 1][j + k + 1] = A[i][j] * B[k][l];
printf("%d\t", C[i + l + 1][j + k + 1]);
}
}
printf("\n");
}
}
}
// Driver Code
int main()
{
int A[3][2] = { { 1, 2 }, { 3, 4 }, { 1, 0 } },
B[2][3] = { { 0, 5, 2 }, { 6, 7, 3 } };
Kroneckerproduct(A, B);
return 0;
}
你还没有发布导致错误的代码和错误的全文（尽管在MSB3721的情况下这是可能没有帮助 - 这是一个通用的错误代码。）
我只能说你用来分配C中元素的索引是不正确的！您可能不相信，因为您的程序输出了正确的结果，但这只是这种情况，因为您使用相同的错误索引值在计算后立即打印C的每个单元格，并且显然在它有可能被覆盖之前！
代码无法正常工作可以很容易看出：对于行和列，此代码中用于C的最小inde值为1，因此永远不会分配第一行和第一行！此外，最大的索引值是2 + 3 + 1 = 6和3 + 2 + 1 = 6，因此一些值被写入随机存储器，导致不确定的行为。
如果将以下循环添加到函数KroneckerProduct（）中，您可以检查C的实际内容：
You still haven't posted the code that causes the errors, and the full text of the error (although in case of MSB3721 this may not be helpful - it is a generic error code).
I can only say that the index you use to assign elements in C are incorrect! You may not believe so since your program outputs the correct result, but this is only the case because you print each cell of C right after it's calculated, using the same incorrect index value, and obviously before there is a chance for it to be overwritten!
That the code can't function can be easily seen: the minimum inde values used for C in this code is 1, for both rows and colums, so the first row and column is never assigned! Furthermore, the largest index values are 2+3+1=6 and 3+2+1=6, so some of the values get written into random memory, causing undefined behaviour.
You can check the actual content of C if you add the following loop to the function KroneckerProduct():
for (int i=0; i < 6; ++i) {
printf("\n");
for (int j=0; j < 6; ++j) {
printf("%d\t", C[i][j]);
}
}
你会得到这样的东西：
You will get something like this:
-971846352 32519 -343317296 32767 -971795976 32519
64550200 0 6 12 -965645592 32519
0 0 18 24 -965709824 32519
4195187 0 6 0 4195096 0
0 5 7 0 0 0
-343317112 2 3 0 -965708464 32519
正确的产品功能应该是这样的：
The correct product function should be something like this:
for (int i = 0; i < rowa*rowb; ++i) {
int ai = i/rowb;
int bi = i%rowb;
for (int j = 0; j < cola*colb; ++j) {
int aj = j/colb;
int bj = j%colb;
C[i][j] = A[ai][aj]*B[bi][bj];
}
}
这将产生正确的输出：
This will produce the correct output:
0 5 2 0 10 4
6 7 3 12 14 6
0 15 6 0 20 8
18 21 9 24 28 12
0 5 2 0 0 0
6 7 3 0 0 0
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