如何使用C ++进行连续极坐标和径向极坐标 [英] How to do a continuous polar and a radial polar using C++

问题描述

1.我想知道怎样做一个连续的极星，它有更多的站点可以获得无限性。

2.我不知道如何使用三个点来做极光极光。



我尝试了什么：

1.I WANT TO KNOW HOW TO DO A CONTINUOUS POLAR WHICH HAVE MORE STATION POINTS UP TO INFINITY.
2. I DONT KNOW HOW TO DO RADIAL POLAR WITH THREE POINTS.

What I have tried:

//Program to compute continuous polar 
#include<iostream>
#include<cmath>
using namespace std;
int main()
{
float direction,distance(d),y,x,Delta_y,Delta_X,T1,T2,T3,Bm1,Bm2;
std::cout<<"Enter the coordinates x,y and press Enter"<<endl;
cin>>x,y;
std::cout<<"Enter the direction and press Enter"<<endl;
cin>>direction;
std::cout<<"Enter the distance(d) and Press Enter"<<endl;
cin>>distance(d);
Delta_Y= Y1 + distance(d)*sin(direction);
Delta_x=x1 + distance(d)*cos(direction);

y2 = y1 + distance(d)*sin(direction);
x2 = x1 + distance(d)*cos(direction);

Display (y2,x2)

推荐答案

鉴于几乎没有定义任何变量，甚至没有编译。以下行应该做什么？

Given that almost none of your variables are defined, that will not even compile. And what is the following line supposed to do?

cin>>distance(d);

我想我得到了一个解决方案，但我只做了一个单极的样本，我想计算一个可以连接两个点的程序，找到未知点的坐标。我认为我之前的问题并不清楚。感谢您的帮助。



#include< iostream>

#include< cmath>

using namespace std ;

int main（）

{

浮动方向，距离，y，x，Delta_y，Delta_X;

std :: cout<<输入坐标x并按Enter键<< endl;

cin>> x;

std :: cout< <输入坐标y并按Enter键<< endl;

cin>> y;

std :: cout<<输入方向然后按Enter键输入<< endl;

cin>>方向;

std :: cout<<输入距离并按Enter键<< ; endl;

cin>>距离;

Delta_Y = Y1 +距离* sin（方向*（0.01475））;

Delta_x = x1 +距离* cos（方向*（0.01475））;



y2 = y1 + Delta_Y;

x2 = x1 + Delta_x; < br $>


std :: cout<<Y2的坐标，X2是=<

I think i got a solution but i only did a sample of a single polar,i wanted to compute a program that can join two points, finding the coordinates of the unknown point. I think my Previous question wasn't clear. Thanks for your help.

#include<iostream>
#include<cmath>
using namespace std;
int main()
{
float direction,distance,y,x,Delta_y,Delta_X;
std::cout<<"Enter the coordinates x and press Enter"<<endl;
cin>>x;
std::cout<<"Enter the coordinate y and press Enter"<<endl;
cin>>y;
std::cout<<"Enter the direction and press Enter"<<endl;
cin>>direction;
std::cout<<"Enter the distance and Press Enter"<<endl;
cin>>distance;
Delta_Y= Y1 + distance*sin(direction*(0.01475));
Delta_x=x1 + distance*cos(direction*(0.01475));

y2 = y1 + Delta_Y;
x2 = x1 + Delta_x ;

std::cout<<"The coordinates of Y2,X2 is ="<

我想我有一个解决方案，但我只做了一个单极的样本，我想计算一个可以连接两个点的程序，找到未知点的坐标。我认为我之前的问题并不清楚。感谢您的帮助。



#include< iostream>

#include< cmath>

using namespace std ;

int main（）

{

浮动方向，距离，y，x，Delta_y，Delta_X;

std :: cout<<输入坐标x并按Enter键<< endl;

cin>> x;

std :: cout< <输入坐标y并按Enter键<< endl;

cin>> y;

std :: cout<<输入方向然后按Enter键输入<< endl;

cin>>方向;

std :: cout<<输入距离并按Enter键<< ; endl;

cin>>距离;

Delta_Y = Y1 +距离* sin（方向*（0.01475））;

Delta_x = x1 +距离* cos（方向*（0.01475））;



y2 = y1 + Delta_Y;

x2 = x1 + Delta_x; < br $>


std :: cout<<Y2，X2的坐标是=<

I think i got a solution but i only did a sample of a single polar,i wanted to compute a program that can join two points, finding the coordinates of the unknown point. I think my Previous question wasn't clear. Thanks for your help.

#include<iostream>
#include<cmath>
using namespace std;
int main()
{
float direction,distance,y,x,Delta_y,Delta_X;
std::cout<<"Enter the coordinates x and press Enter"<<endl;
cin>>x;
std::cout<<"Enter the coordinate y and press Enter"<<endl;
cin>>y;
std::cout<<"Enter the direction and press Enter"<<endl;
cin>>direction;
std::cout<<"Enter the distance and Press Enter"<<endl;
cin>>distance;
Delta_Y= Y1 + distance*sin(direction*(0.01475));
Delta_x=x1 + distance*cos(direction*(0.01475));

y2 = y1 + Delta_Y;
x2 = x1 + Delta_x ;

std::cout<<"The coordinates of Y2,X2 is ="<

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