如何检查输入的数字是双精度还是整数？ （1是整数但1.0是双精度） [英] How do I check whether a number entered is double or integer? (1 is an integer but 1.0 is double)

问题描述

我想检查输入是Integer还是double。我的问题是，当我在1.00之间（这是两倍）时，我的结果是整数。我如何编写区分（1.00和1）的应用程序??



我尝试过：

I want to check if the input is Integer or double. My problem is that when I inter 1.00 (which is double) my result is integer. How I can write app that distinguish between ( 1.00 and 1 ) ??

What I have tried:

int main()
{

double a;
cin >> a;
if ( floor(a) == ceil(a) )
	cout << "Integer";
else
	cout << "Double";

    return 0;
}

推荐答案

检查字符串 Luke，检查字符串！

（搜索点）



您也可以使用 std :: strtol [ ^ ]提供（和检查） str_end 参数。

Check the string Luke, check the string!
(search for the dot)

You might also use std::strtol[^] providing (and the checking) the str_end parameter.

告诉的唯一方法是阅读它作为字符串而不是double，并手动解析。一旦你把它读成双，就无法告诉用户实际输入了什么。

The only way to tell is to read it as a string instead of a double, and manually parse that. Once you have read it into a double, there is no way to tell what the user actually entered.

你可以使用 sscanf 来将值设为字符串，然后计算字符串。谷歌是你的朋友。

You can use sscanf to make the value a string, and then evaluate the string. Google is your friend.

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