找到计数登记的方式[难] [英] Find the way to check in with count [ difficult ]
问题描述
请你帮我解决一下我的问题。我正在使用一个SQL Server数据库,它是一个体操项目,我想在他来健身房时检查客户端,我有两种方式提供第一种方式是按月方式,第二种是每日方式,第一个我没有问题,我用这个代码签入;
using (SqlCommand com = new SqlCommand( 从enddate中选择count(*),其中ID = @ID并且startdate< = @ C1和endDate> = @ C2,con))
{
com.Parameters.AddWithValue( @ ID,ID.Text);
com.Parameters.AddWithValue( @ C1,DateTime.Now);
com.Parameters.AddWithValue( @ C2,DateTime.Now);
int count =( int )com.ExecuteScalar();
if (count > 0 )
{
使用(SqlCommand com1 = new SqlCommand( INSERT INTO [checkin](ID,时间,用户名)VALUES(@ ID,@ time,@ username),con))
{
com1.Parameters.AddWithValue( @ ID,ID.Text);
com1.Parameters.AddWithValue( @ time,txttime.Text );
com1.Parameters.AddWithValue( @ username,txtusername.Text );
com1.ExecuteNonQuery();
}
MetroFramework.MetroMessageBox.Show( this , Check In Sucssesfuly ..................., < span class =code-string> Message,MessageBoxButtons.OK,MessageBoxIcon.Information);
}
else
{
MetroFramework.MetroMessageBox.Show( this , 此ID已过期................. ...., 消息,MessageBoxButtons.OK,MessageBoxIcon.Warning) ;
}
con.Close();
}
我想在此代码中添加第二个条件(每日报价)我有一个enddate表格;
| ID |开始|月|一天|结束|报价|
| 1 | 20-3-2019 | 3 | null | 20-6-2019 |(夏季)每月|
| 2 | 20-3-2019 | null | 5 | 20-3-2019 |(学生)每日|
在这种情况下,第一个可以随时出现3个月,在第二个ID中,他只能来5次。
我的签到表;
| ID |时间|用户名|
| 1 | 21-3-2019 |测试|
| 1 | 25-3-2019 |测试|
| 2 | 27-3-2019 |测试2 |
我可以算一下他来健身房的时间,但我不知道如何在我的代码中添加它
我尝试过:
< ; pre> var goodForVisit = false ;
int visitedCount;
int offerDayCount;
var endDate = DateTime.MinValue;
DateTime startDate = DateTime.MinValue;
使用(SqlConnection con = new SqlConnection( 数据源= SQL5037.site4now.net;初始目录= DB_A448D1_Dragon;用户ID = **********;密码= ***** *******))
{
con.Open();
// 尝试
/ / {
使用(SqlCommand com = new SqlCommand( select * from [enddate]其中ID = @ID,con))
{
com.Parameters.AddWithValue( @ ID,ID.Text);
使用(SqlDataReader reader = com.ExecuteReader())
{
if (reader.Read())
{
// 从enddate表获取信息
var offer = reader [ 要约跨度>]的ToString();
if (reader [ day]!= null )
offerDayCount =( int )reader [ day];
startDate =(DateTime)reader [ StartDate];
if (reader [ endDate]!= null )
endDate =(DateTime)reader [ 结束日期跨度>];
if (读者[ 月] == null && offer!= null )
{
endDate = DateTime.Now.Date;
}
// 从入住表中计算访问次数
使用( var com2 = new SqlCommand( SELECT COUNT(*)as count from checkin WHERE time> = @STDDATE and(time< = @ENDDATE)))
{
com2.Parameters.AddWithValue( @STARTDATE,startDate);
com2.Parameters.AddWithValue( @ ENDDATE,endDate);
使用(SqlDataReader reader2 = com2.ExecuteReader())
{
if (reader2.Read())
{
visitedCount =( int )reader2 [ count];
if (offer!= null && visitedCount < offerDayCount)
goodForVisit = true ;
if (offer!= null && DateTime.Now < span class =code-keyword>> = startDate&& DateTime.Now < = endDate)
goodForVisit = < span class =code-keyword> true ;
}
}
}
}
}
}
如果(goodForVisit)
{
使用(SqlCommand com1 = new SqlCommand ( INSERT INTO [checkin](ID,时间,用户名)VALUES(@ ID,@ time,@ username) ,con))
{
com1.Parameters.AddWithValue( @ ID ,ID.Text);
com1.Parameters.AddWithValue( @ time,txttime.Text );
com1.Parameters.AddWithValue( @ username,txtusername.Text );
com1.ExecuteNonQuery();
}
MetroFramework.MetroMessageBox.Show( this , Check In Sucssesfuly ..................., < span class =code-string> Message,MessageBoxButtons.OK,MessageBoxIcon.Information);
}
else
{
MetroFramework.MetroMessageBox.Show( this , 此ID已过期................. ...., 消息,MessageBoxButtons.OK,MessageBoxIcon.Warning) ;
}
不是直接解决方案,而是一般建议......
我使用存储过程 [ ^ ]用于此类要求。使用存储过程(SP)有很多好处...
如何编写这样的存储过程。你有2个想法:
1)理查兹的MacCutchan - 在问题的评论中
2)Gerry的Schmitz - 解决方案#1。
我还会改善你的报价
表:
用户ID |开始| Periodtype |期间值|结束|报价|
1 | 20-3-2019 | 'M'| 3 | 20-6-2019 | (夏天)每月|
2 | 20-3-2019 | 'D'| 5 | 20-3-2019 | (学生)每日|
然后SP的ody,返回true / false
可能看起来像:
DECLARE @ limitOfVisits INT = 0 ;
DECLARE @ isValidOffer BIT = 0 ; - 或BOOLEAN
- 检查用户可以访问健身房的次数
SELECT @ limitOfVisits = CASE
WHEN Periodtype = ' M' AND Stardate> = @startdate AND enddate< = @ enddate 那么 PeriodValue
WHEN Periodtype = ' D' AND Stardate> = @startdate THEN PeriodValue
ELSE 0 END
FROM offertable
WHERE UserID = @ UserID;
- 检查是否未超过条目限制
SELECT @ isValidOffer = COUNT(*)< @limitOfVisits
FROM [checkin]
WHERE UserID = @ UserID AND Stardate> = @ startdate AND enddate< = @ enddate;
RETURN @ isValidOffer ;
如您所见,这是其他成员想法的实现。
有关详细信息,请参阅:
CREATE PROCEDURE(Transact-SQL) - SQL Server | Microsoft Docs [ ^ ]
如何使用参数创建SQL Server存储过程 [ ^ ]
(Checkin table只需要ID;用户名是多余的,有问题。)
1)创建一个名为HasValidOffer(int id)的方法
2)调用带有返回客户ID的HasValidOffer(int id)(除了什么之外还暗示客户主人)你已经表明了)。在HasValidOffer()中:
- 检查客户是否有报价;如果没有,则返回false(无有效报价)。
- 如果报价已过期,则返回false。
- 如果报价是每日,则计算期间的访问次数;如果访问< max,返回true,否则为false。
3)因此,如果HasValidOffer()返回true,则具有有效报价(因此允许),否则无效的报价生效
Could you please help me to get a solution to my issue. I am using a SQL Server database, it is a gymnastics program, and I want to get check in the client when he comes to the gym , I have two way of offering the first one is a monthly way , and the second is a daily, the first I don't have a problem with it and I use this code for checkin;
using (SqlCommand com = new SqlCommand("select count(*)from enddate where ID=@ID and startdate <=@C1 and endDate >=@C2", con)) { com.Parameters.AddWithValue("@ID", ID.Text); com.Parameters.AddWithValue("@C1", DateTime.Now); com.Parameters.AddWithValue("@C2", DateTime.Now); int count = (int)com.ExecuteScalar(); if (count > 0) { using (SqlCommand com1 = new SqlCommand("INSERT INTO [checkin] (ID,time,username) VALUES (@ID,@time,@username)", con)) { com1.Parameters.AddWithValue("@ID", ID.Text); com1.Parameters.AddWithValue("@time", txttime.Text); com1.Parameters.AddWithValue("@username", txtusername.Text); com1.ExecuteNonQuery(); } MetroFramework.MetroMessageBox.Show(this, "Check In Sucssesfuly ................... ", "Message", MessageBoxButtons.OK, MessageBoxIcon.Information); } else { MetroFramework.MetroMessageBox.Show(this, "this ID Expired .....................", "Message", MessageBoxButtons.OK, MessageBoxIcon.Warning); } con.Close(); }
I want to add to this code the second condition ( the daily offer ) I have the enddate table like ;
| ID | Startdate | month | day | enddate | offer | | 1 | 20-3-2019 | 3 |null |20-6-2019|( summer ) monthly | | 2 | 20-3-2019 | null | 5 |20-3-2019|( student ) daily |
in this case, the first one can come anytime for 3 months, in the second ID he can come for 5 times only.
my checkin table ;
| ID | Time | username | | 1 | 21-3-2019| test | | 1 | 25-3-2019| test | | 2 | 27-3-2019| test 2 |
I can count how many time he comes to the gym but I don't know how to add it in my code
What I have tried:
<pre>var goodForVisit = false; int visitedCount; int offerDayCount; var endDate = DateTime.MinValue; DateTime startDate = DateTime.MinValue; using (SqlConnection con = new SqlConnection("Data Source=SQL5037.site4now.net;Initial Catalog=DB_A448D1_Dragon;User Id=**********;Password=************")) { con.Open(); //try //{ using (SqlCommand com = new SqlCommand("select * from [enddate] where ID=@ID", con)) { com.Parameters.AddWithValue("@ID", ID.Text); using (SqlDataReader reader = com.ExecuteReader()) { if (reader.Read()) { //get information from enddate table var offer = reader["offer"].ToString(); if (reader["day"] != null) offerDayCount = (int)reader["day"]; startDate = (DateTime)reader["StartDate"]; if (reader["endDate"] != null) endDate = (DateTime)reader["endDate"]; if (reader["month"] == null && offer != null) { endDate = DateTime.Now.Date; } //count the visit from checkin table using (var com2 = new SqlCommand("SELECT COUNT(*) as count From checkin WHERE time >= @STARTDATE and (time <= @ENDDATE)")) { com2.Parameters.AddWithValue("@STARTDATE", startDate); com2.Parameters.AddWithValue("@ENDDATE", endDate); using (SqlDataReader reader2 = com2.ExecuteReader()) { if (reader2.Read()) { visitedCount = (int)reader2["count"]; if (offer != null && visitedCount < offerDayCount) goodForVisit = true; if (offer != null && DateTime.Now >= startDate && DateTime.Now <= endDate) goodForVisit = true; } } } } } } if (goodForVisit) { using (SqlCommand com1 = new SqlCommand("INSERT INTO [checkin] (ID,time,username) VALUES (@ID,@time,@username)", con)) { com1.Parameters.AddWithValue("@ID", ID.Text); com1.Parameters.AddWithValue("@time", txttime.Text); com1.Parameters.AddWithValue("@username", txtusername.Text); com1.ExecuteNonQuery(); } MetroFramework.MetroMessageBox.Show(this, "Check In Sucssesfuly ................... ", "Message", MessageBoxButtons.OK, MessageBoxIcon.Information); } else { MetroFramework.MetroMessageBox.Show(this, "this ID Expired .....................", "Message", MessageBoxButtons.OK, MessageBoxIcon.Warning); }解决方案Not a direct solution, but general advice...
I'd use stored procedure[^] for such of requirement. There's a lot of benefits of using stored procedures (SP)...
How to write such of stored procedure. You've got 2 ideas:
1) Richards' MacCutchan - in the comment to the question
2) Gerry's Schmitz - in the solution #1.
I'd also improve youroffer
table:
UserID | Startdate | Periodtype | Periodvalue | enddate | offer | 1 | 20-3-2019 | 'M' | 3 | 20-6-2019 | ( summer ) monthly | 2 | 20-3-2019 | 'D' | 5 | 20-3-2019 | ( student ) daily |
Then the ody of SP, which returnstrue/false
might look like:
DECLARE @limitOfVisits INT = 0; DECLARE @isValidOffer BIT = 0; --or BOOLEAN --check how many times user can access to gym SELECT @limitOfVisits = CASE WHEN Periodtype = 'M' AND Stardate>=@startdate AND enddate <=@enddate THEN PeriodValue WHEN Periodtype = 'D' AND Stardate>=@startdate THEN PeriodValue ELSE 0 END FROM offertable WHERE UserID=@UserID; --check if limit of entries has not been exceeded SELECT @isValidOffer = COUNT(*)<@limitOfVisits FROM [checkin] WHERE UserID = @UserID AND Stardate>=@startdate AND enddate <=@enddate; RETURN @isValidOffer;
As you can see, this is an implementation of other members ideas.
For further details, please see:
CREATE PROCEDURE (Transact-SQL) - SQL Server | Microsoft Docs[^]
How to create a SQL Server stored procedure with parameters[^]
Good luck!
("Checkin table" only requires ID; username is redundant and problematic.)
1) Create a method called "HasValidOffer( int id )"
2) Call HasValidOffer( int id ) with id of "returning" customer (which implies a "customer master" in addition to what you've shown). In HasValidOffer():
- Check if client has offer; if not, return false (no valid offer).
- If offer expired, return false.
- If offer is daily, count visits during period; if visits < max, return true, else false.
3) So, if HasValidOffer() returns true, has valid offer (and therefore admit), else no valid offer in effect.
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