如何将java转换为C ++？ [英] How do I convert java to C++?

问题描述

嘿......

我能帮助您将以下Java代码转换为C ++吗？

Hey...
Can I please have some help converting the following Java code into C++?

var a, b, c, d, s : int
var nikkySteps, nikkyDistance : int
var byronSteps, byronDistance : int
var next, sgn : int

get a, b, c, d, s

nikkySteps := 0
nikkyDistance := 0
next := a
sgn := 1
loop
    exit when nikkySteps + next >= s
    nikkySteps := nikkySteps + next
    nikkyDistance := nikkyDistance + sgn * next
    if sgn = 1 then
	next := b
    else
	next := a
    end if
    sgn := sgn * -1
end loop
nikkyDistance := nikkyDistance + sgn * (s - nikkySteps)

byronSteps := 0
byronDistance := 0
next := c
sgn := 1
loop
    exit when byronSteps + next >= s
    byronSteps := byronSteps + next
    byronDistance := byronDistance + sgn * next
    if sgn = 1 then
	next := d
    else
	next := c
    end if
    sgn := sgn * -1
end loop
byronDistance := byronDistance + sgn * (s - byronSteps)

if nikkyDistance > byronDistance then
    put "Nikky"
elsif nikkyDistance < byronDistance then
    put "Byron"
else
    put "Tied"
end if

谢谢



我尝试过：

Thanks

What I have tried:

#include <iostream>
using namespace std;

int main() {
	int a,b,c,d,s
        int nikkySteps, NikkyDistance
        int byronSteps, byrinDistance
        int next, sgn
        cin >> a;
        cin >> b;
        cin >> c;
        cin >> s;
        cin >> d;
        int nikkySteps = 0;
        int nikkyDistance = 0;
        int next = a;
        int sgn = 1;
*confused*
        nikkySteps = nikkySteps + next;
        nikkyDistance = nikkyDistance + sgn * next;
        if (sgn = 1 ){
           next = b
        } else {
           next = a
        }
        sgn = sgn * -1
*confused*
nikkyDistance = nikkyDistance + sgn * (s = nikkySteps);

int byronSteps = 0
int byronDistance = 0
int next = c
int sgn = 1
*confused"
        byronSteps = byronSteps + next;
       byronDistance = byronDistance + sgn * next;
        if (sgn = 1 ){
           next = d
        } else {
           next = c
        }
        sgn = sgn * -1
byronDistance = byronDistance + sgn * (s - byronSteps)
if (nikkyDistance > byronDistance ) { 
        cout << "Nicky" << endl;
} else if (nikkyDistance < byronDistance ) {
        cout << "Byron" << endl;
} else {
        cout << "Tied" << endl;
}
	return 0;
}

推荐答案

您必须了解上述代码的作用。你必须从头开始重写它！



如果你很懒，你可以使用在线转换器。注意：它不是Java，而是Delphi。可在此处找到可用转换器的列表： .NET代码转换 - 转换代码 [ ^ ]

You have to understand what above code does. And you have to rewrite it from scratch!

In case you're lazy, you can use online converter. Note: it's not Java, it's Delphi. A list of available converters, you'll find here: .NET Code Conversion - Convert Your Code[^]

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