将Java代码更改为C ++ [英] Change Java code to C++

问题描述

Hi
我编写了一个java类，现在我需要将它改为C ++代码，但我不是C ++的专家。任何人都可以为我改变代码到C ++吗？

PLZ我需要它!!

Hi I coded a java class, now I need to change it to C++ code, but I am not expert in C++. Can any body change the code to C++ for me?
plz i need it!!

public class Polynomial {
    private int[] coef;  // coefficients
    private int deg;     // degree of polynomial (0 for the zero polynomial)

    // a * x^b
    public Polynomial(int a, int b) {
        coef = new int[b+1];
        coef[b] = a;
        deg = degree();
    }

    // return the degree of this polynomial (0 for the zero polynomial)
    public int degree() {
        int d = 0;
        for (int i = 0; i < coef.length; i++)
            if (coef[i] != 0) d = i;
        return d;
    }

    // return c = a + b
    public Polynomial plus(Polynomial b) {
        Polynomial a = this;
        Polynomial c = new Polynomial(0, Math.max(a.deg, b.deg));
        for (int i = 0; i <= a.deg; i++) c.coef[i] += a.coef[i];
        for (int i = 0; i <= b.deg; i++) c.coef[i] += b.coef[i];
        c.deg = c.degree();
        return c;
    }

    // return (a - b)
    public Polynomial minus(Polynomial b) {
        Polynomial a = this;
        Polynomial c = new Polynomial(0, Math.max(a.deg, b.deg));
        for (int i = 0; i <= a.deg; i++) c.coef[i] += a.coef[i];
        for (int i = 0; i <= b.deg; i++) c.coef[i] -= b.coef[i];
        c.deg = c.degree();
        return c;
    }

    // return (a * b)
    public Polynomial times(Polynomial b) {
        Polynomial a = this;
        Polynomial c = new Polynomial(0, a.deg + b.deg);
        for (int i = 0; i <= a.deg; i++)
            for (int j = 0; j <= b.deg; j++)
                c.coef[i+j] += (a.coef[i] * b.coef[j]);
        c.deg = c.degree();
        return c;
    }

    // return a(b(x))  - compute using Horner's method
    public Polynomial compose(Polynomial b) {
        Polynomial a = this;
        Polynomial c = new Polynomial(0, 0);
        for (int i = a.deg; i >= 0; i--) {
            Polynomial term = new Polynomial(a.coef[i], 0);
            c = term.plus(b.times(c));
        }
        return c;
    }


    // do a and b represent the same polynomial?
    public boolean eq(Polynomial b) {
        Polynomial a = this;
        if (a.deg != b.deg) return false;
        for (int i = a.deg; i >= 0; i--)
            if (a.coef[i] != b.coef[i]) return false;
        return true;
    }


    // use Horner's method to compute and return the polynomial evaluated at x
    public int evaluate(int x) {
        int p = 0;
        for (int i = deg; i >= 0; i--)
            p = coef[i] + (x * p);
        return p;
    }

    // differentiate this polynomial and return it
    public Polynomial differentiate() {
        if (deg == 0) return new Polynomial(0, 0);
        Polynomial deriv = new Polynomial(0, deg - 1);
        deriv.deg = deg - 1;
        for (int i = 0; i < deg; i++)
            deriv.coef[i] = (i + 1) * coef[i + 1];
        return deriv;
    }

    // convert to string representation
    public String toString() {
        if (deg ==  0) return "" + coef[0];
        if (deg ==  1) return coef[1] + "x + " + coef[0];
        String s = coef[deg] + "x^" + deg;
        for (int i = deg-1; i >= 0; i--) {
            if      (coef[i] == 0) continue;
            else if (coef[i]  > 0) s = s + " + " + ( coef[i]);
            else if (coef[i]  < 0) s = s + " - " + (-coef[i]);
            if      (i == 1) s = s + "x";
            else if (i >  1) s = s + "x^" + i;
        }
        return s;
    }

    // test client
    public static void main(String[] args) { 
        Polynomial zero = new Polynomial(0, 0);

        Polynomial p1   = new Polynomial(4, 3);
        Polynomial p2   = new Polynomial(3, 2);
        Polynomial p3   = new Polynomial(1, 0);
        Polynomial p4   = new Polynomial(2, 1);
        Polynomial p    = p1.plus(p2).plus(p3).plus(p4);   // 4x^3 + 3x^2 + 1

        Polynomial q1   = new Polynomial(3, 2);
        Polynomial q2   = new Polynomial(5, 0);
        Polynomial q    = q1.plus(q2);                     // 3x^2 + 5


        Polynomial r    = p.plus(q);
        Polynomial s    = p.times(q);
        Polynomial t    = p.compose(q);

        System.out.println("zero(x) =     " + zero);
        System.out.println("p(x) =        " + p);
        System.out.println("q(x) =        " + q);
        System.out.println("p(x) + q(x) = " + r);
        System.out.println("p(x) * q(x) = " + s);
        System.out.println("p(q(x))     = " + t);
        System.out.println("0 - p(x)    = " + zero.minus(p));
        System.out.println("p(3)        = " + p.evaluate(3));
        System.out.println("p'(x)       = " + p.differentiate());
        System.out.println("p''(x)      = " + p.differentiate().differentiate());
   }

}

推荐答案

是的，你会遇到很多错误。以下是一些原因：

- C ++中没有 String 类;你可能想用 std：string 。

- 没有 Math.max ;你可能想用 __ max 。

- 当你在C ++中使用 new 时，它返回一个指针;这里有很多错误，而且你会泄漏掉wazoo因为 delete 永远不会被调用。

- 没有 coef.length ;你可能想要 __ countof（）。

- 这个在C ++中是一个指针。



底线：你必须用C ++从上到下重新编写它。因为我猜你没有完成所有的先决条件，所以你必须向朋友询问，或者付钱给别人为你做这件事。

Yes, you will have many errors. Here are some of the reasons:
- There is no String class in C++; you probably want to use std:string.
- There is no Math.max; you probably want to use __max.
- When you use new in C++, it returns a pointer; many errors here, plus you're going to have leaks out the wazoo because delete is never called.
- There is no coef.length; you probably want __countof().
- this in C++ is a pointer.

Bottom line: you have to man up and rewrite this in C++ from top to bottom. Since I'm guessing you took a course without having all the prereqs, you will have to ask a friend, or pay someone to do this for you.

在这里你去



Java和C ++的比较 [ ^ ]



XES - 用户指南 - 转换Java源代码C ++ [ ^ ] < br $> b $ b

C ++和Java语法差异备忘单 [ ^ ]

Here you go

Comparison of Java and C++[^]

XES - User Guide - Converting Java Source code C++[^]

C++ and Java Syntax Differences Cheat Sheet[^]

除了打印代码，这对我来说就像C ++。你为什么要转换它？你为什么不试试？

Apart from the printing code, this looks like C++ to me. Why do you need to convert it ? Why don't you just try ?

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