我怎么能知道项目是在枚举? [英] How can I know items is in the enum?
问题描述
在这个问题的,我用的<$ C $ XOR运算符C>枚举与 [国旗]
属性如下:
In this question, I use xor operator between enum
with [Flags]
attribute as following:
[Flags]
enum QueryFlag
{
None = 0x1,
ByCustomer = 0x2,
ByProduct = 0x4,
ByDate = 0x8
}
QueryFlag flags = QueryFlag.ByCustomer | QueryFlag.ByProduct;
要添加QueryFlag,我们当然应该用 |
运营商
To add an QueryFlag, of course we should use |
operator.
flags |= QueryFlag.ByDate;
要删除一个,我有不同的方式与<一个href="http://stackoverflow.com/questions/3746291/other-method-for-iterating-an-enum/3746604#3746604">Dan涛的回答。我使用的:
To remove one, I have a different way with Dan Tao's answer. I'm using:
flags ^= QueryFlag.ByProduct;
而他使用:
flags &= ~QueryFlag.ByProduct;
显然,他的答案是正确的,容易理解。我想我犯了一个错误。但深思之后,我得到了:
Obviously his answer is correct and easy to understand. I thought I made a mistake. But after a deep thought I got:
a,b a^b a&(~b)
0,0 0 0
0,1 1 0 //the difference
1,0 1 1
1,1 0 0
现在我知道我的错误。 ^
是错误的,当你试图删除不存在的一个项目。
And now I knew my mistake. ^
is wrong when you try to remove one item which doesn't exist.
QueryFlag q = QueryFlag.ByCustomer | QueryFlag.ByDate;
//try to remove QueryFlag.ByProduct which doesn't exist in q
q ^ QueryFlag.ByProduct //equals to add ByProduct to q, wrong!
q & (~QueryFlag.ByProduct) // q isn't changed, remain the original value. correct!
但在这里我得到了另外一个问题:我如何才能知道是否①
包含了一个项目?立足丹道的答案,我写了一个扩展:
But here I got another question: how can I know if q
contains one item? Base on Dan Tao's answer I wrote an extension:
public static bool Contains(this QueryFlag flags, QueryFlag flag)
{
return (flags & (~flag)) != flags;
}
即,如果标志是从标志除去标志之后没有改变,我们知道标志不为在标志!这似乎是正确的时候:
That is, if flags is not changed after removing flag from flags, we know flag is not in flags! It seems correct when:
(QueryFlag.ByProduct | QueryFlag.ByDate).Contains(QueryFlag.None) //false
(QueryFlag.ByProduct | QueryFlag.ByDate).Contains(QueryFlag.ByDate) //true
但事实上:
(QueryFlag.ByProduct | QueryFlag.ByDate).Contains(QueryFlag.ByDate | QueryFlag.ByCustomer) //true, but I suppose it's false
我知道为什么它是假的原因,我怎么能提高呢?这是第一个问题。
第二:我想使。载
通用于多个枚举
与 [国旗]
属性。
I know the reason why it's false, how can I improve it? It's the first question.
The second: I want to make the .Contains
generic to more enum
with [Flags]
attribute.
public static bool Contains<T>(this T flags, T flag) where T : Enum//with [Flags]
{
return (flags & (~flag)) != flags;
}
大概是不可能的约束T搭配属性标记。但即使我删除此约束我得到一个编译错误,说操作符〜不能应用到类型T
。为什么以及如何解决?
Probably it's impossible to constrain T with attribute marked. But even I remove this constraint I get a compile error which says operator ~ can't be applied to type T
. Why and how to resolve?
推荐答案
您的错误在于这个方法:
Your error lies in this method:
public static bool Contains(this QueryFlag flags, QueryFlag flag)
{
return (flags & (~flag)) != flags;
}
这将返回true,每当标志
拥有的任意的(即至少有一个的)中所包含的标志标志
,但我想你想的所有的。
This returns true whenever flags
has any (i.e. at least one) of the flags contained in flag
, but I think you want all.
它应该阅读:
public static bool Contains(this QueryFlag flags, QueryFlag flag)
{
return (flags & flag) == flag;
}
另外,你可以使用 Enum.HasFlag()
这不正是这一点。例如:
Alternatively, you can just use Enum.HasFlag()
which does exactly this. For example:
QueryFlag qf = ...;
if (qf.HasFlag(QueryFlag.ByCustomer))
// ...
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