我怎么能做我的代码，所以我不必使用所有的def，if和elif语句 [英] How can I do my code so that I dont have to use all the def , if and elif statements

问题描述

menu_Cheap = [['1. Shark   ',4.10,], ['2. Flounder',4.10,], ['3. Cod     ',4.10,], ['4. Gurnet  ',4.10,], ['5. kahawai ',4.10,], ['6. Trevall ',4.10,]]
menu_Deluxe = [['7. Snapper      ',7.20,], ['8. Pink Salmon  ',7.20,], ['9. Tuna         ',7.20,], ['10.Smoked Marlin',7.20,], ['11.Clown fish   ',7.20,], ['12.Surgeonfish  ',7.20,]]

DELIVERY = 5
PICKUP = -1.05
MAX_FISH = 7

print('\nThese are the menu items and their prices \n')
for x in menu_Cheap:
    print(x)
for y in menu_Deluxe:
    print(y)
    
def Shark():
    print("you have choosen Shark ")
def Flounder():
    print("you have choosen Flounder ")
def Cod():
    print("you have choosen Cod ")
def Gurnet():
    print("you have choosen Gurnet ")
def Kahawai():
    print("you have choosen Kahawai ")
def Trevally():
    print("you have choosen Trevally ")
def Snapper():
    print("you have choosen Snapper ")
def Pink_Salmon():
    print("you have choosen Pink Salmon ")
def Tuna():
    print("you have choosenTuna ")
def Smoked_Marlin():
    print("you have choosen Smoked_Marlin ")
def Clown_Fish():
    print("you have choosen Clown fish ")
def Surgeonfish():
    print("you have choosen Surgeonfish ")
    
counter = 0
loop = int(input("\nPlease enter the total amount of fish you would like to order\n"))

while counter < loop :
    try:
        selection = int(input("\nPlease enter the type of fish you would like to order\n"))
        if selection == 1:
            Shark()
            counter = counter + 1
        elif selection == 2:
            Flounder()
            counter = counter + 1
        elif selection == 3:
            Cod()
            counter = counter + 1
        elif selection == 4:
            Gurnet()
            counter = counter + 1
        elif selection == 5:
            Kahawai()
            counter = counter + 1
        elif selection == 6:
            Trevally()
            counter = counter + 1
        elif selection == 7:
            Snapper()
            counter = counter + 1
        elif selection == 8:
            Pink_Salmon()
            counter = counter + 1
        elif selection == 9:
            Tuna()
            counter = counter + 1
        elif selection == 10:
            Smoked_Marlin()
            counter = counter + 1
        elif selection == 11:
            Clown_Fish()
            counter = counter + 1
        elif selection == 12:
            Surgeonfish()
            counter = counter + 1
        else:
            print("please enter a values between 1 and 12 ")
    except ValueError:
        print("No strings ")
exit
print (Surgeonfish())

我尝试了什么：



我的代码非常低效，并且想知道是否有人可以给我一些想法

What I have tried:

my code is very inefficient and was wondering if anyone can give me some ideas

推荐答案

见这里：如何在Python中实现switch-case语句 - JAXenter [ ^ ]

或者对于高级用户，请参阅Paul Rubin的解决方案：如何创建函数数组？ - Python [ ^ ]

See here: How to implement a switch-case statement in Python - JAXenter[^]
Or for advanced users, see Paul Rubin's solution here: How do I create an array of functions? - Python[^]

这是不完整的，但展示了如何在没有所有额外定义的方法或if / elif语句的情况下管理列表。

This is incomplete, but shows how to manage a list without all the extra defined methods, or the if/elif statements.

menu = [['1. Shark   ',4.10,], ['2. Flounder',4.10,], ['3. Cod     ',4.10,], ['4. Gurnet  ',4.10,], ['5. kahawai ',4.10,], ['6. Trevall ',4.10,],['7. Snapper      ',7.20,], ['8. Pink Salmon  ',7.20,], ['9. Tuna         ',7.20,], ['10.Smoked Marlin',7.20,], ['11.Clown fish   ',7.20,], ['12.Surgeonfish  ',7.20,]]

DELIVERY = 5
PICKUP = -1.05
MAX_FISH = 7

print('\nThese are the menu items and their prices \n')
for x in menu:
    print(x)
    
counter = 0
loop = int(input("\nPlease enter the total amount of fish you would like to order\n"))

while counter < loop :
    try:
        selection = int(input("\nPlease enter the type of fish you would like to order\n"))
        if selection < 1 or selection > len(menu):
            print("Invalid selection please try again")
        else:
            print("You have chosen", menu[selection -1][0])
    except ValueError:
        print("Please enter a number between 1 and " + len(menu))
exit

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