将XML反序列化为显示错误的对象列表<的xmlns = '' >没想到。 [英] Deserializing XML into list of object showing error < xmlns=''> was not expected.

问题描述

我正在从我的应用程序中使用SOAP服务，并且在我的代码中将XMl内容作为响应消耗.wsdl文件。

I am consuming SOAP services from my application and I get following XMl content as response consuming .wsdl file in my code.

<Vehicles>
    <FourWheeler>
        <Availability>
            <Brand>Toyota</Brand>
            <Model>Fortuner</Model>
            <Country>Japan</Country>
            <Cost>90000</Cost>           
        </Availability>
        <Availability>
            <Brand>Hyundai</Brand>
            <Model>Elentra</Model>
            <Country>South Korea</Country>
            <Cost>75000</Cost>           
        </Availability>
        <Availability>
            <Brand>Volkswagan</Brand>
            <Model>Polo</Model>
            <Country>Gremany</Country>
            <Cost>95000</Cost>                   
        </Availability>
        <Availability>
            <Brand>Tata</Brand>
            <Model>Nano</Model>
            <Country>25000</Country>
            <Cost></Cost>                    
        </Availability>
    </Outbound>
    <TwoWheeler></TwoWheeler>
</Vehicles>

我设计了我的类以这种方式反序列化XML ::

I have designed my class to deserialise XML this way::

using System;
using System.Collections.Generic;
using System.Text;
using System.Threading.Tasks;

using System.Xml.Serialization;
namespace ConsoleApp2
{
    [XmlRoot("Vehicles")]
    public class Vehicles
    {
        [XmlElement("FourWheeler")]
        public FourWheeler FourWheeler
        {
            get;
            set;
        }
    }

    [XmlRoot("FourWheeler")]
    public class FourWheeler
    {
        [XmlElement("Availability")]
        public Vehicles Availability
        {
            get;
            set;
        }
    }

    [XmlRoot("Availability")]
    public class Availability
    {

        [XmlElement("Brand")]
        public string Brand
        {
            get;
            set;
        }

        [XmlElement("Model")]
        public string Model
        {
            get;
            set;
        }


        [XmlElement("Country")]
        public string Country
        {
            get;
            set;
        }

        [XmlElement("Cost")]
        public string Cost
        {
            get;
            set;
        }
    }
}

我要将XML反序列化为列表的代码是：

My code to deserialize XML to list is :

XmlSerializer xmlSerializer = new XmlSerializer(typeof(List<Vehicles>));
System.IO.StreamReader sr = new System.IO.StreamReader("E:\\xmlTier.txt");
List<Vehicles> flightavailabilitylst = (List<Vehicles>)xmlSerializer.Deserialize(sr);

我收到错误

I am getting error in line

List<Vehicles> flightavailabilitylst = (List<Vehicles>)xmlSerializer.Deserialize(sr);

：

:

System.InvalidOperationException: 'There is an error in XML document (1, 2).'

InvalidOperationException: <Vehicles xmlns=''> was not expected.

发生了什么错误以及将XML转换为对象列表的正确方法???



我尝试过：



查看XML，层次结构是车辆> FourWheeler>可用性列表...所以我添加了代码：

What is happening wrong and what is right approach to convert XML into list of object???

What I have tried:

Looking into XML, hierarchy is Vehicles > FourWheeler > List of Availability... So I added code:

XmlRootAttribute xRoot = new XmlRootAttribute();
xRoot.ElementName = "Vehicles";
xRoot.IsNullable = true;

这对我没有帮助。

This did not help me.

推荐答案

你的xml无效。替换

Your xml isn't valid. Replace

</Outbound>
<TwoWheeler></TwoWheeler>

with

with

</FourWheeler>

XML表示单个车辆节点而不是它们的列表，因此相应地更改代码

The XML represents a single Vehicles node not a list of them so change the code accordingly

XmlSerializer xmlSerializer = new XmlSerializer(typeof(Vehicles));
System.IO.StreamReader sr = new System.IO.StreamReader( ... );

Vehicles flightavailabilitylst = (Vehicles)xmlSerializer.Deserialize(sr);

另外可用性列表可用对象，而不是一个Vehicle对象，所以也改变了

Also Availability is a list of Available objects, not a single Vehicles object so change that also

[XmlRoot("FourWheeler")]
public class FourWheeler
{
    [XmlElement("Availability")]
    public List<Availability> Availability
    {
        get;
        set;
    }
}

您的FourWheeler和Outbound标签不匹配。



即您的XML无效。

Your "FourWheeler" and "Outbound" tags are "not matched".

i.e. your XML is invalid.

<Vehicles>
    <FourWheeler>
        <Availability>
            <Brand>Toyota</Brand>
            <Model>Fortuner</Model>
            <Country>Japan</Country>
            <Cost>90000</Cost>           
        </Availability>
        <Availability>
            <Brand>Hyundai</Brand>
            <Model>Elentra</Model>
            <Country>South Korea</Country>
            <Cost>75000</Cost>           
        </Availability>
        <Availability>
            <Brand>Volkswagan</Brand>
            <Model>Polo</Model>
            <Country>Gremany</Country>
            <Cost>95000</Cost>                   
        </Availability>
        <Availability>
            <Brand>Tata</Brand>
            <Model>Nano</Model>
            <Country>25000</Country>
            <Cost></Cost>                    
        </Availability>
    </FourWheeler>
    <TwoWheeler></TwoWheeler>
</Vehicles>

XML已更新。但仍然显示相同的错误。

XML updated. but still showing same error.

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