如何从Python获取退出代码？ [英] How to get exit code from Python?

问题描述

我有一个python代码。我使用cmd文件来执行我的python代码。在cmd文件中，我将从我的python代码中获取errorlevel。



我尝试过：

 infile =FeatureByte.txt
数组= [6J，yB，ss，11] 
 
 with open（infile，r）as input_file：
 output_list = [] 
 for rec in input_file.read（）。splitlines（）：
 rec = rec [： -3] 
 FBlist = [rec [i：i + 2] for i in range（0，len（rec），2）] 
 output_list.append（FBlist）
 print（output_list ）
 
 FBlist_set = set（FBlist）
 Array_set = set（Array）
 
如果是Array_set& FBlist_set：
 print（Found）
 exit（0）
 else：
 print（Not Found）
 exit（1） 
 
 set logfile = C ：\ Users \Log.txt 
 set PYTHONPATH =C：\ Users \ AppData \ Local \Programs\Python\Python37-32
 set PYTHONEXE =％PYTHONPATH ％\ _Python -B
 
 
C：\ Users \ AppData \ Local \Programs\Python\Python37-32\python.exe-BC ：\ Users \Desktop \Pyth.py 
 
 echo％ERRORLEVEL％>> ％logfile％
 
从这两个代码中，我总是在我的Log.txt文件中得到1。
 
解决方案
 
检查：从中获取退出代码使用Python的批处理文件 -  Stack Overflow  [ ^ ] 
 
 
I have a python code. I use cmd file to execute my python code. In the cmd file, I am going to get errorlevel from my python code.



What I have tried:



infile = "FeatureByte.txt"
Array = ["6J", "yB", "ss", "11"]

with open(infile, "r") as input_file:
	output_list = []
	for rec in input_file.read().splitlines():
	   rec = rec[:-3]  
	   FBlist = [rec[i:i+2] for i in range(0, len(rec), 2)] 
	   output_list.append(FBlist)
	   print(output_list)

FBlist_set = set(FBlist)
Array_set = set (Array)

if Array_set & FBlist_set:
	print ("Found")
	exit(0)
else:
	print ("Not Found")
exit(1)






This is my cmd file :

set logfile=C:\Users\Log.txt
set PYTHONPATH="C:\Users\AppData\Local\Programs\Python\Python37-32"
set PYTHONEXE="%PYTHONPATH%\Python -B"


"C:\Users\AppData\Local\Programs\Python\Python37-32\python.exe" -B C:\Users\Desktop\Pyth.py

echo %ERRORLEVEL% >> "%logfile%"

From these both code, I always get 1 inside my Log.txt file.
解决方案
Check this: Get the exit code from a Batch file using Python - Stack Overflow[^]


                        
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