如何修复输入代码？ [英] How to fix input code ?

问题描述

#include <iostream.h>
#include <fstream.h>
#include <conio.h>
#include <string.h>
#include <ctype.h>
#include <stdlib.h>

class Smartphone
{
		private:
      	int kode;
         char brand[25];

      public:
      	void entri_smartphone();
};
void rekam_smartphone(Smartphone smartphone);
void main()
{
     int pilih;
   cout<<"Press  = 1 (Input)"; cin>>pilih;
   if(pilih==1)
   {
      	Smartphone smartphone_elektronik;

   rekam_smartphone(smartphone_elektronik);
   }
   }

   void Smartphone::entri_smartphone()
   {
   	char tmp[15];
      clrscr();
      cout<<"<<Merkam Data Smartphone>>"<<endl;
      cout<<endl;

       cout<<"Kode :";
      cin.getline(tmp,sizeof(tmp));
      kode=atoi(tmp);
      cout<<"Brand		:";
      cin.getline(brand,sizeof(brand));
      }
   void rekam_smartphone(Smartphone smartphone)
   {
   char jawab;

   ofstream file_smartphone("data1.DAT",ios::app);
   for(;;)
   {
   	smartphone.entri_smartphone();
      file_smartphone.write((char*)&smartphone,sizeof(smartphone));

      cout<<endl;
      cout<<"Input data lagi[Y/T]";
     do
      {
      jawab=toupper(getch());
      }while(!((jawab=='Y')||(jawab=='T')) );

      cout<<jawab<<endl;

      if(jawab=='T')
      	break;
         }
         file_smartphone.close();
}

我的尝试：



我想在我的代码中添加一个菜单但是当我添加菜单时输入了一个错误。

What I have tried:

I want to add a menu in my code but when I add the menu there is an error entered.

推荐答案

它不起作用或有错误可能是我们得到的最无用的问题报告 - 我们得到了很多。它没有告诉我们发生了什么，或者什么时候发生。

所以将来，告诉我们你做了什么，你没想到，或者没做你做过的。

告诉我们你做了什么来实现它。

告诉我们任何错误信息。



帮助我们帮助你！



在这种情况下，从你的评论

"It doesn't work" or "there is an error" are probably the most useless problem reports we get - and we get it a lot. It tells us nothing about what is happening, or when it happens.
So in future, tell us what it is doing that you didn't expect, or not doing that you did.
Tell us what you did to get it to happen.
Tell us any error messages.

Help us to help you!

In this case, from your comment

引用：

实际上没有程序中的错误，只有当输入输入时才有跳转

actually there is no error in the program, only if when entering the input there is a jump

没有你可以解释的消息，而且我们没有任何东西可以直接做，因为我们不知道代码应该做什么，你是什么进入，它做了什么。但是......并非所有错误都有消息 - 只有并发症（和严重的运行时间）错误。



编译并不意味着你的代码是正确的！ ：笑：

将开发过程想象成编写电子邮件：成功编译意味着您使用正确的语言编写电子邮件 - 例如英语而不是德语 - 而不是电子邮件包含您的邮件想发送。



所以现在你进入第二阶段的发展（实际上它是第四或第五阶段，但你将在之后的阶段进入）：测试和调试。



首先查看它的作用，以及它与你想要的有何不同。这很重要，因为它可以为您提供有关其原因的信息。例如，如果程序旨在让用户输入一个数字并将其翻倍并打印答案，那么如果输入/输出是这样的：

There are no message you could explain, and there isn't anything we can do directly as we have no idea what the code should do, what you entered, and what it does do. But ... not all errors have messages - only complication (and serious run time) errors do.

Compiling does not mean your code is right! :laugh:
Think of the development process as writing an email: compiling successfully means that you wrote the email in the right language - English, rather than German for example - not that the email contained the message you wanted to send.

So now you enter the second stage of development (in reality it's the fourth or fifth, but you'll come to the earlier stages later): Testing and Debugging.

Start by looking at what it does do, and how that differs from what you wanted. This is important, because it give you information as to why it's doing it. For example, if a program is intended to let the user enter a number and it doubles it and prints the answer, then if the input / output was like this:

Input   Expected output    Actual output
  1            2                 1
  2            4                 4
  3            6                 9
  4            8                16

然后很明显问题出在将它加倍的位 - 它不会将自身加到自身上，或者将它乘以2，它会将它自身相乘并返回输入的平方。

所以，你可以查看代码和很明显，它在某处：

Then it's fairly obvious that the problem is with the bit which doubles it - it's not adding itself to itself, or multiplying it by 2, it's multiplying it by itself and returning the square of the input.
So with that, you can look at the code and it's obvious that it's somewhere here:

int Double(int value)
   {
   return value * value;
   }

一旦你知道可能出现的问题，就开始使用调试器找出原因。在方法的第一行放置一个断点，然后运行你的应用程序。当它到达断点时，调试器将停止，并将控制权移交给您。您现在可以逐行运行代码（称为单步执行）并根据需要查看（甚至更改）变量内容（哎呀，您甚至可以更改代码并在需要时再试一次）。 />
在执行代码之前，请考虑代码中的每一行应该做什么，并将其与使用Step over按钮依次执行每一行时实际执行的操作进行比较。它符合您的期望吗？如果是这样，请转到下一行。

如果没有，为什么不呢？它有什么不同？

希望这可以帮助你找到代码的哪个部分有问题，以及问题是什么。

这是一项技能，它是一个值得开发的，因为它可以帮助你在现实世界和发展中。和所有技能一样，它只能通过使用来改进！

Once you have an idea what might be going wrong, start using the debugger to find out why. Put a breakpoint on the first line of the method, and run your app. When it reaches the breakpoint, the debugger will stop, and hand control over to you. You can now run your code line-by-line (called "single stepping") and look at (or even change) variable contents as necessary (heck, you can even change the code and try again if you need to).
Think about what each line in the code should do before you execute it, and compare that to what it actually did when you use the "Step over" button to execute each line in turn. Did it do what you expect? If so, move on to the next line.
If not, why not? How does it differ?
Hopefully, that should help you locate which part of that code has a problem, and what the problem is.
This is a skill, and it's one which is well worth developing as it helps you in the real world as well as in development. And like all skills, it only improves by use!

请使用更新的编译器。你的年龄太大而且不合规（例如 main 函数必须返回 int ）。

您的（修改过的）代码编译并运行（生成输出文件），所以我没有看到错误。请添加详细信息以获得更好的帮助。

Please use a more updated compiler. Yours is too old and not compliant (for instance the main function must return an int).
Your (amended) code compiles and runs (producing the output file), so I don't see errors. Please add details in order to get better help.

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