确定密码的程序错误或正确。我的源代码有什么问题？ [英] A program that determines a password is either wrong or correct. What is wrong in my source code?

问题描述

#include<iostream>
using namespace std;
main ()
{
	//Local variable declaration
	string password = "Pretty BOY";
	string input;
	
	//Input data
	cout<<"Input password: ";
	cin>>input;
	
	//Process to check condition
	if (input == password)
	{
		cout<<"Access Granted.";
	}
	else 
	{
		cout<<"Access Denied, incorrect password.";
	}
}

我的尝试：



i不知道是什么问题

What I have tried:

i dont know what's the problem

推荐答案

看看 cin 确实：基本输入/输出 - C ++教程 [ ^ ]你会看到：

Look at what cin does: Basic Input/Output - C++ Tutorials[^] and you will see:

引用：

但是，cin提取总是将空格（空格，制表符，换行符......）视为终止提取的值，因此提取字符串意味着始终提取单个字，不是短语或整个句子。



要从cin获取整行，有一个名为getline的函数，它将流（cin）作为第一个参数，字符串变量为秒。

However, cin extraction always considers spaces (whitespaces, tabs, new-line...) as terminating the value being extracted, and thus extracting a string means to always extract a single word, not a phrase or an entire sentence.

To get an entire line from cin, there exists a function, called getline, that takes the stream (cin) as first argument, and the string variable as second.

空白是 cin 的分隔符，所以，如果我们er输入（正确）'Pretty BOY'，变量 input 将被赋予'Pretty'。您可以修改它阅读整行：

The blank is a separator for cin so, if the user enters (correctly) 'Pretty BOY', the variable input would be assigned with 'Pretty'. You may fix it reading the whole line:

#include<iostream>
using namespace std;
int main ()
{
  //Local variable declaration
  string password = "Pretty BOY";
  string input;

  //Input data
  cout<<"Input password: ";
  getline(cin, input);


  //Process to check condition
  if (input == password)
  {
    cout<<"Access Granted.\n";
  }
  else
  {
    cout<<"Access Denied, incorrect password.\n";
  }
}

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