C＃如何在新类中存储字符串列表？ [英] C# how to store a list of strings in a new class?

问题描述

大家好！



我有一个XML，我从那里读取和存储数据。

喜欢：

< root> 
< main> 
< 1>样本< / 1> 
< 2>样本< / 2> 
< context>样本< / context> 
< context>样本< / context> 
< context>样本< / context> 
< context>样本< / context> 
< / main> 
< main> 
< 1>样本< / 1> 
< 2>样本< / 2> 
< context>样本< / context> 
< context>样本< / context> 
< context>样本< / context> 
< / main> 
< main> 
< 1>样本< / 1> 
< 2>样本< / 2> 
< / main> 
< / root> 

出于某种原因使用下面的代码，我无法存储每个类的上下文列表。



我的尝试：



我正在保存所有像这样的新类的主要：

 ht.Add（new HandledTUs {SOURCE = 1，TARGET = 2，context = context，}）; 

课程如下：

公共课程TU 
 {
 private List< string> _CONTEXT = new List< string>（）; 
 
 
 public string 1 {get;组; } 
 public string 2 {get;组; } 
 public List< string>语境{get {return _CONTEXT; } set {_CONTEXT = value; } 
 
 
 
} 

解决方案

添加理查德所说的， 1 和 2 不是值变量或属性名称，不能以数字字符开头。

所以你的C＃代码很糟糕 - 它不会编译 - 同样适用于XML字段名称，它也必须以下划线字母开头。



所以你的代码很糟糕，yoru数据很糟糕 - 我对你使用的任何代码都不起作用并不感到惊讶！

如果我更正你的xml：

< pre lang =HTML> <？ xml version = 1.0 encoding = utf-8 ？>
< root >
< main >
< A1 > 示例< / A1 >
< A2 > 示例< / A2 >
< context > 示例< / context >
< context & gt; 示例< / context > ;
< context > 示例< / context > ;
< context > 示例< / context > ;
< / main >
< main >
< A1 > 示例< / A1 >
< A2 > 示例< / A2 >
< context > 示例< / context >
< context > 示例< / context >
< context > 示例< < span class =code-leadattribute> / context >
< / main >
< main >
< A1 > 示例< / A1 >
< A2 > 示例< / A2 >
< / main >
< / root >

并使用VS生成类：

  ///   <  备注/  >  
  [System.Xml.Serialization.XmlTypeAttribute（AnonymousType =  true ）] 
 [ System.Xml.Serialization.XmlRootAttribute（Namespace =  ，IsNullable =  false ）] 
  public   partial   class  root 
 {
 
 私人 rootMain [] mainField; 
 
  ///   <  备注/  >  
  [System.Xml.Serialization.XmlElementAttribute（   main）] 
  public  rootMain [] main 
 {
  get  
 {
  return  此 .mainField; 
} 
  set  
 {
  this  .mainField = 值; 
} 
} 
} 
 
  ///   <  备注/  >  
  [System.Xml.Serialization.XmlTypeAttribute（AnonymousType =  true ）] 
  public   partial   class  rootMain 
 {
 
  private   string  a1Field; 
 
  private   string  a2Field; 
 
  private   string  [] contextField; 
 
  ///   <  备注/  >  
   public   string  A1 
 {
  get  
 {
  return   this  .a1Field; 
} 
  set  
 {
  this  .a1Field = 值; 
} 
} 
 
  ///   <  备注/  >  
   public   string  A2 
 {
  get  
 {
  return   this  .a2Field; 
} 
  set  
 {
  this  .a2Field = 值; 
} 
} 
 
  ///   <  备注/  >  
  [System.Xml.Serialization.XmlElementAttribute（  context）] 
  public   string  [] context 
 {
  get  
 {
  return   this  .contextField; 
} 
  set  
 {
  this  .contextField = 值; 
} 
} 
} 

然后rootMain类看起来像你的TUs类。

（VS可以从XML生成XML类data - 创建一个新的空类文件，然后从菜单栏中选择Edit ... Paste Special ... Paste XML as classes，它将根据剪贴板数据生成类。）

Hi all!

I have an XML and I read and store data from there.
like:

<root>
  <main>
    <1>sample</1>
    <2>sample</2>
    <context>sample</context>
    <context>sample</context>
    <context>sample</context>
    <context>sample</context>
  </main>
<main>
    <1>sample</1>
    <2>sample</2>
    <context>sample</context>
    <context>sample</context>
    <context>sample</context>
  </main>
<main>
    <1>sample</1>
    <2>sample</2>
  </main>
</root>

For some reason with the code below I can't store a list of context per class.

What I have tried:

I'm saving all the "main" to a new class like this:

ht.Add(new HandledTUs { SOURCE = 1, TARGET = 2, context = context,});

Class looks like this:

public class TUs
        {
            private List<string> _CONTEXT = new List<string>();
            

            public string 1{ get; set; }
            public string 2{ get; set; }
            public List<string> CONTEXT { get { return _CONTEXT; } set { _CONTEXT = value; } }

            

        }

解决方案

To add to what Richard says, 1 and 2 are not value variable or property names, which cannot start with a numeric character.
So your C# code is bad - it won't compile - and the same applies to XML field names which must also start with a letter of underscore.

So your code is bad, yoru data is bad - I'm not surprised that whatever code you are using won't work!
If I correct your xml:

<?xml version="1.0" encoding="utf-8" ?>
<root>
  <main>
    <A1>sample</A1>
    <A2>sample</A2>
    <context>sample</context>
    <context>sample</context>
    <context>sample</context>
    <context>sample</context>
  </main>
<main>
    <A1>sample</A1>
    <A2>sample</A2>
    <context>sample</context>
    <context>sample</context>
    <context>sample</context>
  </main>
<main>
    <A1>sample</A1>
    <A2>sample</A2>
  </main>
</root>

And use VS to generate the classes:

/// <remarks/>
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
[System.Xml.Serialization.XmlRootAttribute(Namespace = "", IsNullable = false)]
public partial class root
    {

    private rootMain[] mainField;

    /// <remarks/>
    [System.Xml.Serialization.XmlElementAttribute("main")]
    public rootMain[] main
        {
        get
            {
            return this.mainField;
            }
        set
            {
            this.mainField = value;
            }
        }
    }

/// <remarks/>
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
public partial class rootMain
    {

    private string a1Field;

    private string a2Field;

    private string[] contextField;

    /// <remarks/>
    public string A1
        {
        get
            {
            return this.a1Field;
            }
        set
            {
            this.a1Field = value;
            }
        }

    /// <remarks/>
    public string A2
        {
        get
            {
            return this.a2Field;
            }
        set
            {
            this.a2Field = value;
            }
        }

    /// <remarks/>
    [System.Xml.Serialization.XmlElementAttribute("context")]
    public string[] context
        {
        get
            {
            return this.contextField;
            }
        set
            {
            this.contextField = value;
            }
        }
    }

Then the rootMain class looks like your TUs class.
(VS can generate XML classes for you from XML data - create a new empty class file, and select "Edit...Paste Special...Paste XML as classes" from the menu bar and it will generate classes based on the clipboard data.)

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