关于Python的random.choices的问题 [英] Question about Python's random.choices

问题描述

我一直在尝试使用python并尝试一些东西，目前我想知道为什么会出现这种情况随机选择



random.choices（[0,1,5,100 ]，weight = [0,0,0,0]）



它总是选择列表中的最后一项（100）。我知道在现实中如果所有人都没有可能性，那么你就得不到任何东西，但在这里它专门挑选最后一个，我想知道为什么，任何人都可以解释这个。



我尝试了什么：



尝试查看随机代码，但我真的不明白对不起我目前是业余

解决方案

我刚试过这个：

  for  i 在范围内（ 10 ）：
 random.choices（[ 0 ， 1 ， 5 ， 100 ]）

得到以下结果：

 [5 ] 
 [0] 
 [0] 
 [0] 
 [100] 
 [5] 
 [100] 
 [100] 
 [0] 
 [5] 

似乎使用全零的权重会影响结果。

< BLO ckquote>它没有：首先是因为它不是 random.choices 它是 random.choice ，其次是因为统计数据：

导入随机
打印（random.choice（[0,1,2,3]））
 print（random.choice（[0 ，1,2,3]））
 print（random.choice（[0,1,2,3]））
 print（random.choice（[0,1,2,3]） ）
 print（random.choice（[0,1,2,3]））
 print（random.choice（[0,1,2,3]））
 print（随机） .choice（[0,1,2,3]））
 print（random.choice（[0,1,2,3]））
 print（random.choice（[0,1， 2,3]））
打印（random.choice（[0,1,2,3]））

给我

 1 
 0 
 3 
 1 
 1 
 1 
 1 
 3 
 2 
 2 

然后这个：

 2 
 0 
 2 
 0 
 0 
 2 
 1 
 0 
 2 
 1 

请注意，第一个测试的运行为1 - 样本越小，运行的可能性越大：只有四个元素可供选择，很有可能你会连续几次获得相同的值。运行一千次，计数会均匀，但在短期内你应该期待奇怪的结果。

I have been experimenting with python and trying out things and currently i was wondering why this happens in random choices

random.choices([0,1,5,100], weights=[0,0,0,0])

it always chooses the last item in th list (100). I know in reality if all have zero possibilities then you don't get anything but in here it picks the last one specifically and i was wondering why and can anyone explain this.

What I have tried:

tried looking at the random code but i can't really understand it sorry im currently an amateur

解决方案

I just tried this:

for i in range(10):
	random.choices([0,1,5,100])

and got the following result:

[5]
[0]
[0]
[0]
[100]
[5]
[100]
[100]
[0]
[5]

It seems that using weights of all zeroes affects the outcome.

It doesn't: firstly because it's not random.choices it's random.choice, and secondly because of statistics:

import random
print(random.choice([0,1,2,3]))
print(random.choice([0,1,2,3]))
print(random.choice([0,1,2,3]))
print(random.choice([0,1,2,3]))
print(random.choice([0,1,2,3]))
print(random.choice([0,1,2,3]))
print(random.choice([0,1,2,3]))
print(random.choice([0,1,2,3]))
print(random.choice([0,1,2,3]))
print(random.choice([0,1,2,3]))

Gives me

1
0
3
1
1
1
1
3
2
2

Then this:

2
0
2
0
0
2
1
0
2
1

Notice that the first test has a "run" of '1's - the smaller your sample, the more likely a "run" is: with only four elements to choose from, it's quite possible that you will get the same value several times in a row. Run it a thousand times, and the count's will even out, but in the short term you should expect "odd looking" results.

这篇关于关于Python的random.choices的问题的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！