如何在方法中传递我的对象列表？ [英] How can I pass list of my object in method?

问题描述

喜欢我问：例如，我有两个不同的列表：

List< myoldobject>旧的;

列表< mynewobject> mnew;



所以，我想在其中一个参数中做一个方法，我可以传递字符串和列表



我不想通过两个清单。



我该怎么做？



我的尝试：

Liked I asked: For example I have two diffrent list:
List<myoldobject> old;
List<mynewobject> mnew;

So, I'd like to do method witch in one of parametrs I can pass string and list

I don't want pass two list.

How can I do that?

What I have tried:

public void save(List<myoldobject> obj ,string s) // I don't know what I should write in "<>"
{}

推荐答案

有几种方法。

1）你可以创建重载方法：

There are a couple of ways.
1) You can create overloaded methods:

public void save(List<myoldobject> obj ,string s)
{
   ...
}

和

And

public void save(List<mynewobject> obj ,string s)
{
   ...
}

2）您可以定义一个接口IMyObject，您的类都可以实现它（它不需要任何方法）并将其用于通用实现：

2) You could define an interface IMyObject which both your classes implement (it needs no methods) and use that for a generic implementation:

public interface IMyObject { }
public class myoldclass : IMyObject { }
public class mynewclass :IMyObject { }

然后你可以传递给你方法：

You can then pass either to your method:

public void save<T>(List<T> list, string s) where T: IMyObject
    {
    }

List<myoldclass> a = new List<myoldclass>();
List<mynewclass> b = new List<mynewclass>();
save(a, "");
save(b, "");

但是......在你的方法中，你将无法使用任何不属于界面的类成员。

But ... inside your method, you won't be able to use any class members which are not part of the interface.

它取决于你想在方法中做什么，但你可以：

It depends on what you want to do in the method, but you can:

public void save<T>(List<T> list, string s)
{

}

public class Result <T>
{
  public T List { get; set; }
}

	

Result<Object> Info = new Result<Object>();
Info.List = anyList;
save(Info, "string");



 public void save(Result<Object> List, string info)
 {
    .............
 }

这篇关于如何在方法中传递我的对象列表？的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！