如何正确显示直方图？ [英] How do I display my histogram properly ?

问题描述

大家好我正试图为我的选举显示直方图。

我认为我的代码有效，但在第10级它似乎改变了我的所有选票，因为我认为有2数字......

再次感谢您的时间;）



我尝试过的事情：

Hi everyone i'm trying to display a histogram for my "election".
I think my code works but at the 10th rank its seem to shift all my votes because i think there is 2 numbers ...
Thank you again for your time ;)

What I have tried:

#include <stdio.h>
#include <stdlib.h>

int main() {

    char character ;
    int TAB[12] = {0} ;
    int vote = 0;
    int I;
    printf("Please enter a character:\n");
    scanf(" %c", &character);
    printf("Please enter votes\n");
    while(1) {
        scanf("%d", &vote);
        if (vote == -1) {
            break;
        }
        TAB[vote-1]++;
    }
        printf("Histogram :\n");
        /* Search for the maximum value */
        int MAX=0;
        for (I=0; I<12; I++)
        {
            if(TAB[I]>TAB[MAX]) MAX=I;

        }

        int maximum = TAB[MAX];

         while (maximum > 0) {

             for (I = 0; I < 12; I++) {
                 if (TAB[I] == maximum) {
                     printf("%c ",character);
                     TAB[I] = (TAB[I] - 1) ;
                 }
                 else {
                     printf("  ");
                 }

             }
             maximum= maximum - 1;

             printf("\n");
         }
    for (I = 0; I < 13; I++) {
        printf("%d ",I+1);
    }
    printf("\n");
     MAX = MAX + 1;
    switch (MAX)
    {
        case 1:
            printf("Ido was elected!");
            break;
        case 2:
            printf("Alon was elected!");
            break;
        case 3:
            printf("Asaf was elected!");
            break;
        case 4:
            printf("Daniella was elected!");
            break;
        case 5:
            printf("Daniel was elected!");
            break;
        case 6:
            printf("Dimitri was elected!");
            break;
        case 7:
            printf("Gasob was elected!");
            break;
        case 8:
            printf("Ido was elected!");
            break;
        case 9:
            printf("Najib was elected!");
            break;
        case 10:
            printf("Nir was elected!");
            break;
        case 11:
            printf("Omer was elected!");
            break;
        case 12:
            printf("Yair was elected!");
            break;
        case 13:
            printf("Yarah was elected!");
            break;

    }

    return 0;
}

推荐答案

您需要阅读 printf 文档。

You need to read the printf documentation carefully.

printf("%2d ",I+1);

应该可以帮到你。



提示：你可以将这些名字放入 char *数组，所以你不需要这么大的开关。

should help you.

tip: you can put the names into a char* array, so you dont need such a big switch.

试试

Try

#include <stdio.h>

#define CANDIDATES 12

int main() 
{
  // array used to get the candidate name by its index
  const char * candidate[CANDIDATES]=
  {
    "Ido", "Alon", "Asaf", "Daniella", "Daniel", "Dimitri",
    "Gasob", "Najib", "Nir", "Omer", "Yair", "Yarah"
  };

  char character ;
  int imax;
  int votemax;
  int vote[CANDIDATES] =  {0};

  do
  {
    printf("Please enter a character:\n");
  } while ( scanf("%c", &character) != 1);


  printf("Now please enter votes int the 1..%d range, -1 to exit\n", CANDIDATES);

  while (1)
  {
    int v;
    while ( scanf("%d", &v) != 1) {}
    if ( v == -1)
      break;
    --v;
    if ( v >= 0 && v <CANDIDATES)
      ++vote[v];
    else
      printf("Warning, invalid vote %d\n", v);
  }
  
  {// find the index of the candidate most voted
    int i;
    imax = 0;
    for ( i = 1; i<CANDIDATES; ++i)
      if (vote[imax] < vote[i])
        imax = i;
  }

  votemax = vote[imax];

  {// print the histogram
    int row;
    int i;
    for (row = 0; row < votemax; ++row)
    {
      for (i=0; i<CANDIDATES; ++i)
      {
        char c =  vote[i] >= (votemax-row) ? character : ' ';
        printf(" %c ", c);
      }
      printf("\n");
    }
    for (i=0; i<CANDIDATES; ++i)
      printf("%-3d", (i+1));
  }

  printf("%s is elected\n", candidate[imax]);
  return 0;
}

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