如何使用正则表达式从字符串中删除多个单词？ [英] How to remove more than one word from a string with regex ?
问题描述
我有一个带有一堆句子的.txt文件和一个带有我要从第一个文件中删除的单词的.txt文件。我刚刚开始玩正则表达式而且我不太确定该怎么做
我尝试过：
我尝试过以下方法，但对我来说无效。
I have a .txt file with a bunch of sentences and a .txt file with words I want to remove from the first file. I just started playing around regex and im not quite sure how to do it
What I have tried:
I have tried the following method which did not work for me.
class Program
{
static void Main(string[] args)
{
Program p = new Program();
const string CFd = "..\\..\\Duomenys.txt";
const string CFr = "..\\..\\Rezultatai.txt";
const string Remove = "..\\..\\NorimiZodziai.txt";
string lines = ReadingText(CFd);
string removeW = ReadingText(Remove); //Words i want to remove from CFd file
string replacedLines = Replaceing(lines, removeW);
p.Printing(replacedLines,CFr);
}
static string ReadingText(string CFd)
{
string lines = File.ReadAllText(CFd, Encoding.GetEncoding(1257));
return lines;
}
static string Replaceing(string lines, string removeW)
{
string pattern = @"\b"+removeW+"\b";
string output = Regex.Replace(lines, pattern, "");
return output;
}
void Printing (string replacedLines, string file)
{
using (StreamWriter writer = new StreamWriter(file))
{
writer.WriteLine(replacedLines);
}
}
}
推荐答案
你不需要正则表达式为此：string.Replace也可以完成这项工作（而且更快，正则表达式是一个通用的字符串处理器，所以它没有专用方法那么快。
String.Replace Method（System）| Microsoft Docs [ ^ ]
You don't need a regex for that: string.Replace will do the job just as well (and quicker, regex is a general purpose string processor, so it isn't as fast as a dedicated method.
String.Replace Method (System) | Microsoft Docs[^]
我尝试过以下方法，但是没有用对我来说。
I have tried the following method which did not work for me.
最好展示一下它是如何工作的例子。
It is a good idea to show examples of how it don't work.
我有一个.txt文件一堆句子和一个.txt文件，里面有我要从第一个文件中删除的单词。
I have a .txt file with a bunch of sentences and a .txt file with words I want to remove from the first file.
删除单词比你做的要复杂得多。
Removing words is a little more complicated than what you did.
string pattern = @"\b"+removeW+"\b";
在一个句子中，没有必要在空格之间插入一个单词，你可以拥有，。 ？ ！如果单词在字符串中是第一个或最后一个，则没有任何内容。
另一个问题是当你删除单词时，你不想删除单词周围的两个空格，你需要保留1个空格。
因此，用空格替换已经有了改进：
In a sentence, a word is not necessary embedded between spaces, you can have , . ? ! and nothing if the word is first or last in string.
Another problem is that when you remove a word, you don't want to remove both spaces around the word, you need to keep 1 space.
So replacing by a space will already an improvement:
string pattern = @"\b"+removeW+"\b";
string output = Regex.Replace(lines, pattern, " ");
您需要定义当单词不在空格之间时要执行的操作，然后推断它如何转换为代码。
-----
只是一些有趣的链接，可帮助构建和调试RegEx。
以下是RegEx文档的链接：
< a href =http://perldoc.perl.org/perlre.html> perlre - perldoc.perl.org [ ^ ]
以下是帮助构建RegEx并调试它们的工具的链接：
.NET正则表达式测试程序 - 正则表达式风暴 [ ^ ]
Expresso正则表达式工具 [ ^ ]
RegExr：Learn，Build，&测试RegEx [ ^ ]
在线正则表达式测试器和调试器：PHP，PCRE，Python，Golang和JavaScript [ ^ ]
这个显示RegEx是一个很好的图表，它非常有助于理解RegEx的作用：
Debuggex：在线可视正则表达式测试器。 JavaScript，Python和PCRE。 [ ^ ]
这个网站也在一个漂亮的图表中显示正则表达式，但无法测试与RegEx匹配的内容：
Regexper [ ^ ]
You need to define what to do when a word is not between spaces, then deduce how it translate into code.
-----
Just a few interesting links to help building and debugging RegEx.
Here is a link to RegEx documentation:
perlre - perldoc.perl.org[^]
Here is links to tools to help build RegEx and debug them:
.NET Regex Tester - Regex Storm[^]
Expresso Regular Expression Tool[^]
RegExr: Learn, Build, & Test RegEx[^]
Online regex tester and debugger: PHP, PCRE, Python, Golang and JavaScript[^]
This one show you the RegEx as a nice graph which is really helpful to understand what is doing a RegEx:
Debuggex: Online visual regex tester. JavaScript, Python, and PCRE.[^]
This site also show the Regex in a nice graph but can't test what match the RegEx:
Regexper[^]
谢谢你们，我修好了，然而，在删除单词后，还有空格和分隔符，有什么方法可以删除它们吗？
Thank you guys, i fixed it, however, after the words are removed, there are blank spaces and separators left, is there any possible way I can remove them ?
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