在C语言中出现问题，将数字四舍五入 [英] Got a problem in the C language with it rounding numbers up

问题描述

嘿，这就是问题所在：我想打印只有三位数的0.3228并使用％。3f但是使用它将它四舍五入到0.323但是我希望它显示0.322任何人都有任何解决方案吗？ />


我尝试了什么：



i不知道如何做到这一点我我想在0.3228'2'之后切割数字，但有没有人对此有任何想法

解决方案

  #include   <   stdio.h  >  
   #include   <   math.h  >  
   int  main（）
 {
  double  d =  0 。 3228 ; 
  double  truncated = floor（d *  1000 ）/ 1000; 
 printf（  d =％。3f，truncated =％。3f\ n ，d，截断）; 
  return   0 ; 
} 

hey, here is the problem: i wanna print only three digits of 0.3228 and i use "%.3f" but by using this it rounds it up to 0.323 but i want it to show 0.322 anyone got any solutions?

What I have tried:

i have no clue how to do this i was thinking cutting the digits after '2' in 0.3228 but does anyone have any ideas about this

解决方案

#include <stdio.h>
#include <math.h>
int main()
{
  double d = 0.3228;
  double truncated = floor(d*1000)/1000;
  printf("d = %.3f, truncated=%.3f\n", d, truncated);
  return 0;
}

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