我的C程序返回错误？警告：初始化从指针生成整数而没有强制转换[-wint-conversion] |？救命！ [英] My C program returns error? Warning: initialization makes integer from pointer without a cast [-wint-conversion]|? help!

问题描述

这是我的代码

  #include   < span class =code-keyword><   stdio.h  >  
   int  main（）{
  char 名称=   Daniel; 
 printf（  Hello My Name is％s，Name）; 
} 

：



这是我的错误：

警告：初始化使整数来自没有演员阵容的指针[-Wint-conversion] |



我尝试了什么：



我已经尝试过stackoverflow，我也看了遍布谷歌但无法找到awnser。我也试过quora

解决方案

Rick是正确的但您需要添加

 返回  0 ; 

在主要功能结束时!!!



访问一些教程，如学习C 提高您的编码技能。

正如其他人所建议的那样，它应该是

 #include< stdio .H> 
 
 int main（）
 {
 const char * name =Daniel; 
 printf（Hello我的名字是％s \ n，姓名）; 
返回0; 
} 

需要是char *。

  char  * name =   Daniel; 

This is my code

#include <stdio.h>
int main(){
char Name="Daniel";
printf("Hello My Name Is %s",Name);
}

:

This is my error:
warning: initialization makes integer from pointer without a cast [-Wint-conversion]|

What I have tried:

I have tried stackoverflow,I have also looked all over google but couldnt find the awnser.I also tried quora

解决方案

Rick is right but you need to add a

return 0;

at the end of main function!!!

Visit some tutorial like Learn C to improve your coding skills.

As suggested by the others, it should be

#include <stdio.h>

int main()
{
  const char * name = "Daniel";
  printf("Hello my name is %s\n", name);
  return 0;
}

That needs to be a "char *".

char * name = "Daniel";

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