我该如何解决这个错误？解析错误：语法错误，意外'; '在第23行的C：\ xampp \\\\\\\\\\\\\\\\\\\\\\\\\\ [英] How I can fix this error? Parse error: syntax error, unexpected '; ' in C:\xampp\htdocs\project\include\singup.inc.php on line 23

问题描述

<?php
if(isset($_POST['submit'])){
include_once 'dbh.inc.php';
$first = mysqli_real_escape_string($conn,$_POST['Fname']);
$email = mysqli_real_escape_string($conn,$_POST['email']);
$username = mysqli_real_escape_string($conn,$_POST['username']);
$pwd = mysqli_real_escape_string($conn,$_POST['password']);
$confirm = mysqli_real_escape_string($conn,$_POST['confirm']);
// error handlers

if ($pwd != $confirm) {
  header("Location: ../singup.php?notsame=");
  exit();
}

//check for empty fields
if(empty($first) || empty($email) || empty($username) || empty($pwd) || empty($confirm) ){
  header("Location: ../singup.php?empty=");
  exit();
}else{
  // check if the input characters are valid
if(!preg_match("/^[a-zA-Z]*$/",$first){
  header("Location: ../singup.php?invalid=");   <<<<error is here
  exit();
}else{
// check if emal is valid
if(filter_var(!$email, FILTER_VALIDATE_EMAIL)){
  header("Location: ../singup.php?emailno=");
  exit();
}else{
$sql = "SELECT * FROM users WHERE user_uid = '$username'";
$result = mysqli_query($conn,$sql);
$resultCheck = mysqli_num_rows($result);
if($resultCheck > 0){
  header("Location: ../singup.php?usertaken=");
  exit();
}else{

我尝试过：



i已在网上搜索解决方案，但没有工作

What I have tried:

i have searched the web for solutions but non worked

推荐答案

_POST ['submit']））{
include_once'dbh .inc.php';

_POST['submit'])){ include_once 'dbh.inc.php';

first = mysqli_real_escape_string（

first = mysqli_real_escape_string(

conn，

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