实现一个函数，该函数接受一个行字符串并返回行字符串的总长度。 [英] Implement a function that takes a line string and returns the overall length of the line string.

问题描述

定义一个行字符串的结构并实现一个函数，该函数接受一个行字符串并返回行字符串的总长度。



我是什么尝试过：



stringLength（struct string * s）

{

返回s- >长度;





}

Define a structure for a line string and implement a function that takes a line string and returns the overall length of the line string.

What I have tried:

stringLength(struct string *s)
{
return s->length;


}

推荐答案

您必须获取信息关于你的

You must get information about your

struct string

因为它可能有一个有长度的成员，但仔细阅读它也可能是最大尺寸。比Dirk的解决方案与字符串数据。



我想你需要学到很多东西来提高你的编码技巧。花时间学习，否则你会失败。谷歌的一些教程或阅读你的学校文件练习。



祝你好运

because it may have a member which has the length, but read carefully it could also be the max size. Than the the solution of Dirk with the string data.

I guess you need to learn a lot to improve your coding skills. Take time and learn or you will fail. Google for some tutorial or read your school documents an practise .

Good luck

我是假设你的字符串是空终止'\ 0' - 所以你可以在ANSI C中这样做。我没有实际测试过代码，但我很确定它应该像这样工作 - 另一种解决方案也是增加 s 和 i 并使用此表达式检查字符串的结尾 * s！='\\ \\ 0';

I am assuming your string is null terminated '\0' - so you could do it like this in ANSI C. I have not actually tested the code but I am pretty sure it should work like this - an alternative solution is also to increase s and i and check for the end of the string with this expression *s != '\0';

stringLength(struct string *s)
{
  int i=0;

  while(s[i] != '\0') i++;

  return i;
} 

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