如何在C＃中处理复杂的json值 [英] How do I process complex json value in C#

问题描述

您好b 
 $ b有人可以帮助我处理下面的Json字符串值，请突出显示parseValue中的数据，如Message.ID，Message.Version，Message.Val .ValMessage.optionalAdditionalData.data。 
 
  {no：194，id：011049150083，parseValue：[{Message.ID：1，Message.Version： 2，Message.Val.ValMessage.optionalAdditionalData.data：F2A51}]};  
 
感谢您的回复

我尝试过：



我无法处理的值是标记为

 Message.ID，Message.Version 

解决方案

查看序列化和反序列化Json



Json反序列化

使用 JSON.NET [ ^ ]，您需要使用 JsonProperty属性 [ ^ ]指定属性名称。



例如：

  public   class  ParseValue 
 {
 [JsonProperty（  Message.ID）] 
  public   string  MessageId { get ;  set ; } 
 
 [JsonProperty（  Message.Version）] 
  public   string  MessageVersion { get ;  set ; } 
 
 [JsonProperty（  Message.Val.ValMessage.optionalAdditionalData.data）] 
  public   string  MessageAdditionalData { get ;  set ; } 
} 
 
  public   class  Root 
 { 
 [JsonProperty（  no）] 
  public   string 否{ get ;  set ; } 
 
 [JsonProperty（  id）] 
 < span class =code-keyword> public   string  ID { get ;  set ; } 
 
 [JsonProperty（  parseValue）] 
 < span class =code-keyword> public  ParseValue [] ParseValue { get ;  set ; } 
} 
 
 ... 
 
根数据= JsonConvert.DeserializeObject< Root>（jsonString）; 

有关JSON反序列化的其他信息，请查看此深入文章，该文章基于此处提出的问题汇总在一起：在C＃中使用JSON& VB [ ^ ]

Hi 

Can you please someone help me to process the below Json string value, Please highlight the data inside  parseValue like Message.ID, Message.Version , Message.Val.ValMessage.optionalAdditionalData.data. 

{"no":"194","id":"011049150083","parseValue":[{"Message.ID":"1","Message.Version":"2","Message.Val.ValMessage.optionalAdditionalData.data":"F2A51"}]}";

Appreciate your response 

What I have tried:

I am not able to process the value which is marked as

Message.ID, Message.Version

解决方案

Look at Serializing and Deserializing the Json

Json Deserialize

Using JSON.NET[^], you would need to use the JsonProperty attribute[^] to specify the property name.

For example:

public class ParseValue
{
    [JsonProperty("Message.ID")]
    public string MessageId { get; set; }

    [JsonProperty("Message.Version")]
    public string MessageVersion { get; set; }

    [JsonProperty("Message.Val.ValMessage.optionalAdditionalData.data")]
    public string MessageAdditionalData { get; set; }
}

public class Root
{
    [JsonProperty("no")]
    public string No { get; set; }

    [JsonProperty("id")]
    public string Id { get; set; }

    [JsonProperty("parseValue")]
    public ParseValue[] ParseValue { get; set; }
}

...

Root data = JsonConvert.DeserializeObject<Root>(jsonString);

For additional information on JSON deserialization, check out this in-depth article that was put together base on questions asked here: Working with JSON in C# & VB[^]

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